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  • Question 1 - Which one of the following immunological changes is seen in progressive HIV infection?...

    Incorrect

    • Which one of the following immunological changes is seen in progressive HIV infection?

      Your Answer: Increased type IV hypersensitivity responses

      Correct Answer: Increase in B2-microglobulin levels

      Explanation:

      The immunological changes in HIV include depletion in CD4+ T cell, cytokine dysregulation and immune dysfunction. The dominant immunologic feature of HIV infection is progressive depletion of the helper T cell (CD4+ T cell), which reverses the normal CD4:CD8 ratio and subsequently lead to immunodeficiency. Other imuunological changes include:
      increased B2-microglobulin
      decreased IL-2 production
      polyclonal B-cell activation
      decreased NK cell function
      reduced delayed hypersensitivity responses

    • This question is part of the following fields:

      • Clinical Sciences
      52.3
      Seconds
  • Question 2 - A 42-year-old patient has been admitted with a very swollen and painful right...

    Incorrect

    • A 42-year-old patient has been admitted with a very swollen and painful right knee. He was unable to walk on it so came into hospital. It is currently being treated as gout with non steroidal anti-inflammatory drugs. You notice he is of short stature, has shortened arms and legs and a flat nasal bridge. A mutation in which gene is responsible for this condition?

      Your Answer:

      Correct Answer: Fibroblast growth factor receptor

      Explanation:

      Achondroplasia is a common cause of dwarfism. It is caused by a mutation in fibroblast growth factor receptor 3 (FGFR3). In normal development FGFR3 has a negative regulatory effect on bone growth. In achondroplasia, the mutated form of the receptor is constitutively active and this leads to severely shortened bones. The effect is genetically dominant, with one mutant copy of the FGFR3 gene being sufficient to cause achondroplasia, while two copies of the mutant gene are invariably fatal. A person with achondroplasia thus has a 50% chance of passing dwarfism to each of their offspring. People with achondroplasia can be born to parents that do not have the condition due to spontaneous mutation. It occurs as a sporadic mutation in approximately 80% of cases (associated with advanced paternal age) or it may be inherited as an autosomal dominant genetic disorder.
      People with achondroplasia have short stature, with an average adult height of 131 centimeters (52 inches) for males and 123 centimeters (48 inches) for females.

    • This question is part of the following fields:

      • Clinical Sciences
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      Seconds
  • Question 3 - You want to measure the potential benefit of creating a service dedicated to...

    Incorrect

    • You want to measure the potential benefit of creating a service dedicated to patients with multiple sclerosis in the local area. Which factor would determine how many resources will be required?

      Your Answer:

      Correct Answer: Prevalence

      Explanation:

      To describe how often a disease or another health event occurs in a population, different measures of disease frequency can be used. The prevalence reflects the number of existing cases of a disease. In contrast to the prevalence, the incidence reflects the number of new cases of disease and can be reported as a risk or as an incidence rate. Prevalence and incidence are used for different purposes and to answer different research questions.

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 4 - Which of following does not promote the release of endothelin? ...

    Incorrect

    • Which of following does not promote the release of endothelin?

      Your Answer:

      Correct Answer: Prostacyclin

      Explanation:

      Prostacyclin (PGI2) generated by the vascular wall is a potent vasodilator, and the most potent endogenous inhibitor of platelet aggregation so far discovered. Prostacyclin inhibits platelet aggregation by increasing cyclic AMP levels. Prostacyclin is a circulating hormone continually released by the lungs into the arterial circulation. Circulating platelets are, therefore, subjected constantly to prostacyclin stimulation and it is via this mechanism that platelet aggregability in vivo is controlled.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 5 - Which of the following is not a tumour suppressor gene? ...

    Incorrect

    • Which of the following is not a tumour suppressor gene?

      Your Answer:

      Correct Answer: myc

      Explanation:

      Myc is a family of regulator genes and proto-oncogenes that code for transcription factors.

      A tumor suppressor gene, or antioncogene, is a gene that protects a cell from one step on the path to cancer. When this gene mutates to cause a loss or reduction in its function, the cell can progress to cancer, usually in combination with other genetic changes. Tumor suppressor genes can be grouped into categories including caretaker genes, gatekeeper genes, and landscaper genes; the classification schemes are continually evolving.
      Examples include:
      Gene Associated cancers
      p53 Common to many cancers, Li-Fraumeni syndrome
      APC Colorectal cancer
      BRCA1 Breast and ovarian cancer
      BRCA2 Breast and ovarian cancer
      NF1 Neurofibromatosis
      Rb Retinoblastoma
      WT1 Wilm’s tumour

    • This question is part of the following fields:

      • Clinical Sciences
      0
      Seconds
  • Question 6 - What is northern blotting used for? ...

    Incorrect

    • What is northern blotting used for?

      Your Answer:

      Correct Answer: Detect RNA

      Explanation:

      Northern blotting’s purpose is to measure the size and amount of RNA transcribed from a specific gene of interest.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 7 - The average weight of 64 patients with type 2 diabetes mellitus was 81...

    Incorrect

    • The average weight of 64 patients with type 2 diabetes mellitus was 81 kg, with a standard deviation of 12 kg. What is the standard error of the mean?

      Your Answer:

      Correct Answer: 1.5

      Explanation:

      The SEM is dependent on the variation in the population and the number of the extracted samples. A large variation in the population causes a large difference in the sample means, ultimately resulting in a larger SEM. However, as more samples are extracted from the population, the sample means move closer to the population mean, which results in a smaller SEM. In short, the SEM is an indicator of how close the sample mean is to the population mean. Standard error of the mean = standard deviation / square root (number of patients)
      The standard error of the mean is calculated by the standard deviation / square root (number of patients)

      = 12 / square root (64) = 12 / 8 = 1.5

    • This question is part of the following fields:

      • Clinical Sciences
      0
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  • Question 8 - A study is developed to compare the calcemia of men and women with...

    Incorrect

    • A study is developed to compare the calcemia of men and women with Crohn's disease. The objective of the study is to detect any differences between the average calcium levels in men compared to women. Previous studies have shown a normal distribution regarding calcium levels. Which of the the following tests would you most likely apply?

      Your Answer:

      Correct Answer: Student's unpaired t-test

      Explanation:

      A t test is a type of statistical test that is used to compare the means of two groups. It is one of the most widely used statistical hypothesis tests in pain studies. There are two types of statistical inferences: parametric and nonparametric methods. Parametric methods refer to a statistical technique in which one defines the probability distribution of probability variables and makes inferences about the parameters of the distribution. In cases in which the probability distribution cannot be defined, nonparametric methods are employed. T tests are a type of parametric method; they can be used when the samples satisfy the conditions of normality, equal variance, and independence. In this case the data is parametric, comparing two independent samples from the same population.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 9 - A study is done on 1000 patients to assess the specificity of a...

    Incorrect

    • A study is done on 1000 patients to assess the specificity of a new rapid finger-prick blood test developed to help diagnose deep vein thrombosis (DVT). The new test was positive on 200 patients with DVT and on 100 patients without DVT. It was also negative on 20 patients with DVT and 680 without DVT. What is the specificity of the new test?

      Your Answer:

      Correct Answer: 680/780

      Explanation:

      Specificity (negative in health)
      The ability of a test to correctly classify an individual as disease- free is called the test′s specificity. [Table 2]

      Specificity = d / b+d

      = d (true negative) / b+d (true negative + false positive)

      = Probability of being test negative when disease absent.

      Example: One hundred persons with normal angles (diagnosed by ′gold standard′: gonioscopy) are examined by peripheral angle chamber depth examination. Eighty-five persons had normal peripheral angle chamber depth [Table 3]. The specificity of the peripheral angle chamber depth examination to PACG is therefore –

      85 / 100 = 85%.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 10 - Which one of the following statements regarding mitochondrial inheritance is true? ...

    Incorrect

    • Which one of the following statements regarding mitochondrial inheritance is true?

      Your Answer:

      Correct Answer: Poor genotype:phenotype correlation

      Explanation:

      The human cell has two type of DNA: Nuclear DNA and Mitochondrial DNA (MtDNA). A MtDNA copy is passed down entirely unchanged, through the maternal line. Males cannot pass their MtDNA to their offspring although they inherit a copy of it from their mother. There is poor genotype:phenotype correlation. Within a tissue or cell there can be different mitochondrial populations (this is known as heteroplasmy).
      Examples of mitochondrial diseases include:
      – Leber’s optic atrophy
      – MELAS syndrome (mitochondrial encephalomyopathy lactic acidosis and stroke-like episodes)
      – MERRF syndrome (myoclonus epilepsy with ragged-red fibres)
      – Kearns-Sayre syndrome (more severe syndromic variant of chronic progressive external ophthalmoplegia, onset in patients < 20 years old)

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 11 - Intracellular proteins tagged with mannose-6-phosphate are destined to which of the following organelles?...

    Incorrect

    • Intracellular proteins tagged with mannose-6-phosphate are destined to which of the following organelles?

      Your Answer:

      Correct Answer: Lysosome

      Explanation:

      Lysosomal hydrolases are synthesized in the rough endoplasmic reticulum and specifically transported through the Golgi apparatus to the trans-Golgi network, from which transport vesicles bud to deliver them to the endosomal/lysosomal compartment. The explanation of how the lysosomal enzymes are accurately recognized and selected over many other proteins in the trans-Golgi network relies on them being tagged with a unique marker: the mannose-6-phosphate (M6P) group, which is added exclusively to the N-linked oligosaccharides of lysosomal soluble hydrolases, as they pass through the cis-Golgi network. Generation of the M6P recognition marker depends on a reaction involving two different enzymes: UDP-N-acetylglucosamine 1-phosphotransferase and α-N-acetylglucosamine-1-phosphodiester α-N-acetylglucosaminidase.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 12 - Which one of the following occurs during reverse transcriptase polymerase chain reaction? ...

    Incorrect

    • Which one of the following occurs during reverse transcriptase polymerase chain reaction?

      Your Answer:

      Correct Answer: RNA is converted to DNA

      Explanation:

      Reverse transcription polymerase chain reaction is a laboratory technique combining reverse transcription of RNA into DNA and amplification of specific DNA targets using polymerase chain reaction. It is primarily used to measure the amount of a specific RNA. The main advantage of PCR is its sensitivity: only one strand of sample DNA is needed to detect a particular DNA sequence. It now has many uses including prenatal diagnosis, detection of mutated oncogenes and diagnosis of infections.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 13 - Which of the following suggests a diagnosis of molluscum contagiosum rather than chickenpox?...

    Incorrect

    • Which of the following suggests a diagnosis of molluscum contagiosum rather than chickenpox?

      Your Answer:

      Correct Answer: Absence of erythema surrounding lesions

      Explanation:

      Molluscum contagiosum (MC), is a viral infection of the skin that results in small, raised, pink lesions with a dimple in the center with little to no surrounding erythema. They may occasionally be itchy or sore. They may occur singularly or in groups. Any area of the skin may be affected, with abdomen, legs, arms, neck, genital area, and face being most common. Onset of the lesions is around 7 weeks after infection. It usually goes away within a year without scarring.
      Chickenpox lesions in the early stages may be mistaken for molluscum. However, the presence of associated macules and later vesicles and pustules help to differentiate them.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 14 - A 27-year-old lady presents with severe morning headaches associated with nausea. Head MRI...

    Incorrect

    • A 27-year-old lady presents with severe morning headaches associated with nausea. Head MRI reveals a large compressive tumour arising from the falx cerebri. The tumour is well delineated. What is the most probable diagnosis?

      Your Answer:

      Correct Answer: Meningioma

      Explanation:

      Meningiomas are the most common benign tumours of the brain. Their name is derived from the fact that they arise from the dura mater which together with the pia matter and arachnoid mater form the meninges. The chances that a meningioma is benign are almost 98%. They are non-invasive and well delineated, causing sign and symptoms of brain compression.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 15 - A 45-year-old male patient presents with severe pharyngitis and dysphagia. He's found to...

    Incorrect

    • A 45-year-old male patient presents with severe pharyngitis and dysphagia. He's found to be HIV positive and with oesophageal candidiasis. Which of the following regarding HIV virus is correct?

      Your Answer:

      Correct Answer: HIV is an RNA virus

      Explanation:

      The human immunodeficiency virus (HIV) is grouped to the genus Lentivirus within the family of Retroviridae, subfamily Orthoretrovirinae. The HIV genome consists of two identical single-stranded RNA molecules that are enclosed within the core of the virus particle. The genome of the HIV provirus, also known as proviral DNA, is generated by the reverse transcription of the viral RNA genome into DNA, degradation of the RNA and integration of the double-stranded HIV DNA into the human genome.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 16 - Where is secretin secreted from? ...

    Incorrect

    • Where is secretin secreted from?

      Your Answer:

      Correct Answer: S cells in upper small intestine

      Explanation:

      Secretin is a peptide hormone produced in the S cells of the duodenum, which are located in the intestinal glands. In humans, the secretin peptide is encoded by the SCT gene.
      Secretin helps regulate the pH of the duodenum by
      1) inhibiting the secretion of gastric acid from the parietal cells of the stomach and
      (2) stimulating the production of bicarbonate from the ductal cells of the pancreas.
      G cells in the antrum of the stomach release gastrin
      I cells in upper small intestine release CCK
      D cells in the pancreas & stomach secrete somatostatin
      K cells secrete gastric inhibitory peptide, an incretin, which also promotes triglyceride storage.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 17 - Which part of the renal tubule is impermeable to water: ...

    Incorrect

    • Which part of the renal tubule is impermeable to water:

      Your Answer:

      Correct Answer: The ascending limb of loop of Henle

      Explanation:

      The walls of the ascending limb of the loop of Henle are not permeable to water. The tubular fluid thus becomes increasingly dilute as it ascends toward the cortex, whereas the interstitial fluid around the loops of Henle in the medulla becomes increasingly more concentrated.

      The ascending limb actively reabsorbs NaCl but has an extremely low transepithelial osmotic water permeability, even in the presence of vasopressin. This combination of NaCl reabsorption without water reabsorption serves two vital functions: it provides NaCl to increase the osmolality of the medullary interstitium, tubules, vasculature, and collecting ducts; and it dilutes the luminal fluid within the thick ascending limb.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 18 - A 61-year-old female presents to the A&E with malaise and muscle twitching. Her...

    Incorrect

    • A 61-year-old female presents to the A&E with malaise and muscle twitching. Her blood pressure is 114/78 mmHg and her pulse is 84/min. Blood exam reveals Calcium = 1.94 mmol/l and Albumin = 38 g/l. Which of the following tests is most useful in establishing her diagnosis?

      Your Answer:

      Correct Answer: Parathyroid hormone

      Explanation:

      Hypocalcaemia occurs in patients with impaired function of the parathyroid glands. This is most common after thyroid or parathyroid surgery, but it can be idiopathic—mostly in young adults and less often as part of a genetic syndrome, such as autoimmune polyglandular syndrome type 1. Usually, the first and most useful test to perform in such cases is the measurement of the parathyroid hormone.

    • This question is part of the following fields:

      • Clinical Sciences
      0
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  • Question 19 - The family of a 10-year-old boy was advised to take the boy to...

    Incorrect

    • The family of a 10-year-old boy was advised to take the boy to see an oncologist, for suspected lymphoma. The boy had lymphadenopathy on presentation. His mother says that he's had a fever, night sweats and has experienced weight loss. The boy underwent a lymph node biopsy at the oncologist which suggests Burkitt's lymphoma. Which oncogene are you expecting to see after molecular testing?

      Your Answer:

      Correct Answer: c-MYC

      Explanation:

      Burkitt lymphoma is a germinal centre B-cell-derived cancer that was instrumental in the identification of MYC as an important human oncogene more than three decades ago. Recently, new genomics technologies have uncovered several additional oncogenic mechanisms that cooperate with MYC to create this highly aggressive cancer.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 20 - Choose the correct formula to calculate the negative predictive value of a screening...

    Incorrect

    • Choose the correct formula to calculate the negative predictive value of a screening test:

      Your Answer:

      Correct Answer: TN / (TN + FN)

      Explanation:

      NPV = TN / FN+TN

      = TN (true negative) / FN+TN (false negative + true negative)

      = Probability (patient not having disease when test is negative)

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 21 - A 68-year-old male patient presents with central chest pain and associated flushing. He...

    Incorrect

    • A 68-year-old male patient presents with central chest pain and associated flushing. He claims the pain is crushing in character. ECG reveals T wave inversion in II, III and AVF. Blood exams are as follows: Troponin T = 0.9 ng/ml. Which substance does troponin bind to?

      Your Answer:

      Correct Answer: Tropomyosin

      Explanation:

      Troponin T is a 37 ku protein that binds to tropomyosin, thereby attaching the troponin complex to the thin filament.

    • This question is part of the following fields:

      • Clinical Sciences
      0
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  • Question 22 - Through which foramen does the maxillary nerve pass through? ...

    Incorrect

    • Through which foramen does the maxillary nerve pass through?

      Your Answer:

      Correct Answer: Foramen rotundum

      Explanation:

      The foramen rotundum is one of the several circular apertures (the foramina) located in the base of the skull, in the anterior and medial part of the sphenoid bone. The maxillary branch (V2) of the trigeminal nerve (CN V) passes through and exits the skull via the pterygopalatine fossa and the foramen rotundum.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 23 - Empagliflozin was found to reduce the risk of cardiovascular deaths, non-fatal myocardial infarction...

    Incorrect

    • Empagliflozin was found to reduce the risk of cardiovascular deaths, non-fatal myocardial infarction and non-fatal stroke when added to standard treatment plans in patients with type 2 diabetes mellitus. This information was shared in 2015 by The New England Journal of Medicine and the results were expressed per 1000 patient years. In fact, empagliflozin had an event rate of 37.3/1000 patient years and placebo an event rate of 43.9/1000 patient years. How many patients who are at high cardiovascular risk need to be treated with empagliflozin to prevent a cardiovascular death, a non-fatal myocardial infarction or a non-fatal stroke?

      Your Answer:

      Correct Answer: 150

      Explanation:

      The number needed to treat (NNT) is an absolute effect measure that has been used to assess beneficial and harmful effects of medical interventions. In this case the NNT can be calculated as follows: NNT = 1/ Absolute risk reduction (ARR). ARR=(Control event rate expressed per 1000 patient years) – (Experimental event rate expressed per 1000 patient years) = 43.9-37.3 = 6.6/1000 patient years

      NNT=(Patient years)/ARR = 1000/ 6.6 = 151.5. The closest to 151.5 is 150, thus it is the correct answer.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 24 - Choose the correct definition regarding the standard error of the mean: ...

    Incorrect

    • Choose the correct definition regarding the standard error of the mean:

      Your Answer:

      Correct Answer: Standard deviation / square root (number of patients)

      Explanation:

      The SEM is an indicator of how close the sample mean is to the population mean. In reality, however, only one sample is extracted from the population. Therefore, the SEM is estimated using the standard deviation (SD) and a sample size (Estimated SEM). The SEM computed by a statistical program is an estimated value calculated via this process.

      Estimated Standard Error of the Mean (SEM)=SDn√

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 25 - What is the correct formula to calculate the positive predictive value? (TP =...

    Incorrect

    • What is the correct formula to calculate the positive predictive value? (TP = true positive; FP = false positive; TN = true negative; FN = false negative)

      Your Answer:

      Correct Answer: TP / (TP + FP)

      Explanation:

      Positive predictive value is the probability that subjects with a positive screening test truly have the disease.

      Positive predictive value = true positive / ( true positive + false positive)

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 26 - Choose the molecule that acts as the co-receptor for cells expressing antigens linked...

    Incorrect

    • Choose the molecule that acts as the co-receptor for cells expressing antigens linked with MHC class I molecules:

      Your Answer:

      Correct Answer: CD8

      Explanation:

      CD8+ T cells recognize antigens in the form of short peptide fragments bound to major histocompatibility complex class I (MHCI) molecules on the target cell surface.1 Specific engagement of peptide-MHCI (pMHCI) complexes via the clonotypically expressed αβ T-cell receptor (TCR) triggers a range of effector functions that play a critical role in protective immunity against intracellular infections and various malignancies.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 27 - A new blood test developed to screen individuals for cardiac failure was performed...

    Incorrect

    • A new blood test developed to screen individuals for cardiac failure was performed on 500 patients. The results were positive for 40 out of 50 patients with echocardiography-established heart failure. However, the test was also positive for 20 patients with no signs of heart failure. What is the positive predictive value of the test?

      Your Answer:

      Correct Answer: 0.66

      Explanation:

      Positive predictive value = TP (true positives) / [TP + FP (false positives)] = 40 / (40 + 20) = 0.66

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 28 - Choose the correct statement regarding the standard error of the mean: ...

    Incorrect

    • Choose the correct statement regarding the standard error of the mean:

      Your Answer:

      Correct Answer: Gets smaller as the sample size increases

      Explanation:

      When statistically comparing data sets, researchers estimate the population of each sample and examine them to see whether they are identical. The standard error of the mean (SEM) – not the standard deviation (SD), which represents the variation in the sample – is used to estimate the population mean. Via this process, researchers conclude that the sample used in their studies appropriately represents the population within the error range specified by the pre-set significance level.
      The SEM is smaller than the SD, as the SEM is estimated usually with the SD divided by the square root of the sample size. For this reason, researchers are tempted to use the SEM when describing their samples. It is acceptable to use either the SEM or SD to compare two different groups if the sample sizes of the two groups are equal; however, the sample size must be stated in order to deliver accurate information. For example, when a population has a large amount of variation, the SD of an extracted sample from this population must be large. However, the SEM will be small if the sample size is deliberately increased.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 29 - A 34-year-old man presents with haemoptysis and weight loss. History reveals he suffers...

    Incorrect

    • A 34-year-old man presents with haemoptysis and weight loss. History reveals he suffers from night sweats and upon auscultation you notice reduced breath sounds over the apex of his right lung and significant nail clubbing. You refer him to a pneumologist who administers the following antibiotics: rifampicin, ethambutol, pyrazinamide and isoniazid. What is the mechanism of action of the first drug?

      Your Answer:

      Correct Answer: Inhibit RNA synthesis

      Explanation:

      Rifampicin specifically inhibits bacterial RNA polymerase, the enzyme responsible for DNA transcription, by forming a stable drug-enzyme complex with a binding constant of 10(-9) M at 37 C.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 30 - Choose the correct statement regarding hyponatremia: ...

    Incorrect

    • Choose the correct statement regarding hyponatremia:

      Your Answer:

      Correct Answer: Hyperlipidaemia may cause pseudohyponatraemia

      Explanation:

      The Hyperlipidaemia Effect: Pseudohyponatremia in Pancreatic Cancer; Patients who have disorders of cholestasis commonly present with volume depletion due to vomiting and poor oral intake, which, in turn, often leads to hypovolemic hyponatremia. It is less well known that disorders of cholestasis, including tumours of the hepatobiliary system, can be accompanied by hyperlipidaemia.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 31 - Choose the correct statement regarding endothelin: ...

    Incorrect

    • Choose the correct statement regarding endothelin:

      Your Answer:

      Correct Answer: Endothelin antagonists are useful in primary pulmonary hypertension

      Explanation:

      Current guidelines recommend the use of ambrisentan, Bosentan (recommendation I, level of evidence A) and macitentan (I, B) in patients with PAH and WHO functional class II and III. In WHO functional class IV, the first-line drug is Epoprostenol and the recommendation for Endothelin receptor antagonists is weaker (IIb, C).

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 32 - Choose the cell organelle involved in the synthesis of lipids: ...

    Incorrect

    • Choose the cell organelle involved in the synthesis of lipids:

      Your Answer:

      Correct Answer: Smooth endoplasmic reticulum

      Explanation:

      The Smooth endoplasmic reticulum (ER) is the major site at which membrane lipids are synthesized in eukaryotic cells. Because they are extremely hydrophobic, lipids are synthesized in association with already existing cellular membranes rather than in the aqueous environment of the cytosol. Although some lipids are synthesized in association with other membranes, most are synthesized in the ER. They are then transported from the ER to their ultimate destinations either in vesicles or by carrier proteins.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 33 - Cholecystokinin is secreted from: ...

    Incorrect

    • Cholecystokinin is secreted from:

      Your Answer:

      Correct Answer: I cells in upper small intestine

      Explanation:

      Cholecystokinin (CCK) was discovered in 1928 in jejunal extracts as a gallbladder contraction factor. It was later shown to be member of a peptide family, which are all ligands for the CCK1 and CCK2 receptors. CCK peptides are known to be synthetized in the small intestinal endocrine I-cells and cerebral neurons.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 34 - Intracellular proteins tagged with ubiquitination are destined to which of the following organelles?...

    Incorrect

    • Intracellular proteins tagged with ubiquitination are destined to which of the following organelles?

      Your Answer:

      Correct Answer: Proteasome

      Explanation:

      Delivery of ubiquitinated substrates to the proteasome.
      Ubiquitinated proteins are delivered to the proteasome by various routes and the complete picture of how these pathways fit together has yet to emerge, reviewed in. Some substrates bind directly to the proteasome by interacting with the 19S regulatory particle subunits Rpn1028 or Rpn1329, and probably Rpt530. Alternatively, ubiquitinated substrates can be brought to the proteasome by adaptors that bind both the proteasome and the ubiquitin chain on the substrate to deliver it for degradation.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 35 - A study was developed to assess a new oral antithrombotic drug on the...

    Incorrect

    • A study was developed to assess a new oral antithrombotic drug on the chance of stroke in high-risk patients, compared to warfarin. The total number of patients receiving the new drug were 200 compared to 600 who were receiving warfarin. From the ones receiving the new drug, 10 patients had a stroke within 3 years, compared to 12 patients who were receiving warfarin and had a stroke. What is the relative risk of having a stroke within 3 years for patients receiving the new drug?

      Your Answer:

      Correct Answer: 2.5

      Explanation:

      Relative Risk = (Probability of event in exposed group) / (Probability of event in not exposed group)
      Experimental event rate, EER = 10 / 200 = 0.05

      Control event rate, CER = 12 / 600 = 0.02

      Therefore the relative risk = EER / CER = 0.05 / 0.02 = 2.5

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 36 - A clinical trial is conducted to study the benefits of a new oral...

    Incorrect

    • A clinical trial is conducted to study the benefits of a new oral medication to improve the symptoms of patients with asthma. In the trial 400 patients with asthma, half were given the new medication and half a placebo. Three months later they are asked to rate their symptoms using the following scale: much improved, slight improvement, no change, slight worsening, significantly worse. What is the most appropriate statistical test to see whether the new medication is beneficial?

      Your Answer:

      Correct Answer: Mann-Whitney U test

      Explanation:

      The type of significance test used depends on whether the data is parametric (can be measured, usually normally distributed) or non-parametric.
      Parametric tests:
      Student’s t-test – paired or unpaired*
      Pearson’s product-moment coefficient – correlation

      Non-parametric tests:
      Mann-Whitney U test – unpaired data
      Wilcoxon signed-rank test – compares two sets of observations on a single sample
      chi-squared test – used to compare proportions or percentages
      Spearman, Kendall rank – correlation.

      The outcome measured is not normally distributed, i.e. it is non-parametric. This excludes the Student’s t-tests. We are not comparing percentages/proportions so the chi-squared test is excluded. The Mann–Whitney U test is a nonparametric test of the null hypothesis that it is equally likely that a randomly selected value from one sample will be less than or greater than a randomly selected value from a second sample.
      This test can be used to investigate whether two independent samples were selected from populations having the same distribution.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 37 - A 3-year-old boy has been brought to the hospital by his mother with...

    Incorrect

    • A 3-year-old boy has been brought to the hospital by his mother with pallor, lethargy and abdominal enlargement. His mother said she only noticed these symptoms two weeks ago but further questioning reveals that they have been progressively worsening over a longer period of time. The boy was born naturally following an uncomplicated pregnancy. Past and family histories are not significant and the family hasn't been on any vacations recently. However, the mother mentions a metabolic disorder present in the family history but couldn't remember the exact name. Clinical examination reveals generalised pallor, abdominal enlargement, massive splenomegaly and hepatomegaly. The spleen is firm but not tender and there is no icterus or lymphadenopathy. What is the most probable diagnosis?

      Your Answer:

      Correct Answer: Gaucher's disease

      Explanation:

      Gaucher’s disease is characterized by hepatosplenomegaly, cytopenia, sometimes severe bone involvement and, in certain forms, neurological impairment. The variability in the clinical presentations of GD may be explained by the continuum of phenotypes. However, three major phenotypic presentations can usually be distinguished. Type-1 GD is usually named non-neuronopathic GD; type-2 and type-3 are termed neuronopathic-GD. Gaucher disease (GD, ORPHA355) is a rare, autosomal recessive genetic disorder. It is caused by a deficiency of the lysosomal enzyme, glucocerebrosidase, which leads to an accumulation of its substrate, glucosylceramide, in macrophages.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 38 - Randomised control trials offer the following level of evidence: ...

    Incorrect

    • Randomised control trials offer the following level of evidence:

      Your Answer:

      Correct Answer: Ib

      Explanation:

      1B: Individual Randomised Control Trial (with narrow confidence intervals)

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 39 - Which one of the following statements best describes a type II statistical error?...

    Incorrect

    • Which one of the following statements best describes a type II statistical error?

      Your Answer:

      Correct Answer: The null hypothesis is accepted when it is false

      Explanation:

      In statistical hypothesis testing there are 2 types of errors:
      – type I: the null hypothesis is rejected when it is true – i.e. Showing a difference between two groups when it doesn’t exist, a false positive.
      – type II: the null hypothesis is accepted when it is false – i.e. Failing to spot a difference when one really exists, a false negative.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 40 - A study is performed to assess a new proton pump inhibitor (PPI) in...

    Incorrect

    • A study is performed to assess a new proton pump inhibitor (PPI) in 120 elderly patients who are receiving aspirin. A control group of 240 elderly patients is given the standard PPI. The final evaluation after five years revealed that 24 individuals receiving the new PPI experienced an upper GI bleed. What is the absolute risk reduction if 60 individuals receiving the standard PPI experienced the same condition?

      Your Answer:

      Correct Answer: 5%

      Explanation:

      Absolute risk reduction (ARR) – also called risk difference (RD) – is the most useful way of presenting research results to help your decision-making. Absolute risk reduction = (Control event rate) – (Experimental event rate) = 0.05 = 5% reduction

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 41 - What kind of receptor is the nitric oxide receptor? ...

    Incorrect

    • What kind of receptor is the nitric oxide receptor?

      Your Answer:

      Correct Answer: Guanylate cyclase receptor

      Explanation:

      Soluble guanylyl cyclase (GC-1) is the primary receptor of nitric oxide (NO) in smooth muscle cells and maintains vascular function by inducing vasorelaxation in nearby blood vessels. GC-1 converts guanosine 5′-triphosphate (GTP) into cyclic guanosine 3′,5′-monophosphate (cGMP), which acts as a second messenger to improve blood flow.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 42 - A 22-year-old man is investigated for visual loss and diagnosed with Leber's optic...

    Incorrect

    • A 22-year-old man is investigated for visual loss and diagnosed with Leber's optic atrophy. Given the mitochondrial inheritance of this condition, which one of the following relatives is most likely to be also affected?

      Your Answer:

      Correct Answer: Sister

      Explanation:

      The human cell has two type of DNA: Nuclear DNA and Mitochondrial DNA (MtDNA). A MtDNA copy is passed down entirely unchanged, through the maternal line. Males cannot pass their MtDNA to their offspring although they inherit a copy of it from their mother. Mitochondrial inheritance therefore has the following characteristics:
      – Inheritance is only via the maternal line
      – All children of affected males will not inherit the disease
      – All children of affected females will inherit it

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 43 - A 67-year-old man presents with anaemia and weight loss. Upon endoscopy, a gastric...

    Incorrect

    • A 67-year-old man presents with anaemia and weight loss. Upon endoscopy, a gastric tumour is revealed, later established as an adenocarcinoma. The patient refuses any treatment and claims that his condition is not influencing the quality of his life. Clinical examination has nothing particularly interesting to show and the patient seems to be conscious of his decision, regardless of the likely curative nature of surgery. What is the single most appropriate management?

      Your Answer:

      Correct Answer: Respect his wishes and book a follow-up appointment for four weeks

      Explanation:

      The patient seems to be conscious about his decision, which should be respected. According to Mental Capacity Act 2005, a person who makes an unwise decision should not be treated as unable to make a decision.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 44 - A study is carried out to assess the efficacy of a rapid urine...

    Incorrect

    • A study is carried out to assess the efficacy of a rapid urine screening test developed to detect Chlamydia. The total number of people involved in the study were 200. The study compared the new test to the already existing NAAT techniques. The new test was positive in 20 patients that were Chlamydia positive and in 3 patients that were Chlamydia negative. For 5 patients that were Chlamydia positive and 172 patients that were Chlamydia negative the test turned out to be negative. Choose the correct value regarding the negative predictive value of the new test:

      Your Answer:

      Correct Answer: 172/177

      Explanation:

      The definition of negative predictive value is the probability that the individuals with truly negative screening test don’t have Chlamydia. The equation is the following: Negative predictive value = Truly negative/(truly negative + false negative) = 172 / (172 + 5) = 172 / 177

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 45 - What do T-helper cells of the Th2 subset typically secrete? ...

    Incorrect

    • What do T-helper cells of the Th2 subset typically secrete?

      Your Answer:

      Correct Answer: IL-4, IL-5, IL-6, IL-10, IL-13

      Explanation:

      Interleukin-4 (IL-4), IL-5 and IL-13, the signature cytokines that are produced during type 2 immune responses, are critical for protective immunity against infections of extracellular parasites and are responsible for asthma and many other allergic inflammatory diseases. Although many immune cell types within the myeloid lineage compartment including basophils, eosinophils and mast cells are capable of producing at least one of these cytokines, the production of these “type 2 immune response-related” cytokines by lymphoid lineages, CD4 T helper 2 (Th2) cells and type 2 innate lymphoid cells (ILC2s) in particular, are the central events during type 2 immune responses.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 46 - A 2-day-old girl is admitted by her mother because she gets cyanotic upon...

    Incorrect

    • A 2-day-old girl is admitted by her mother because she gets cyanotic upon feeding and she wouldn't stop crying. The doctors suspect a congenital heart disease. What is the most probable aetiology?

      Your Answer:

      Correct Answer: Transposition of the great arteries

      Explanation:

      Transposition of the great arteries results in a significant hypoxemic status that is observed clinically by central cyanosis. The bluish discoloration of the skin and mucous membranes is therefore the basic pattern of clinical presentation in transposition. Its onset and severity depend on anatomical and functional variants that influence the degree of mixing between the two circulations. Limited intercirculatory mixing, usually present if the ventricular septum is intact or the atrial septal defect is restrictive, is related to progressive and profound central cyanosis evident within the first hours of life. Tachypnoea, tachycardia, diaphoresis, poor weight gain, a gallop rhythm, and eventually hepatomegaly can be then detected later on during infancy. Heart murmurs associated with left outflow tract obstruction, due to a persistent arterial duct or a septal defect may be heard, but they are not a constant finding.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 47 - One of your colleagues shares with you the fact that he is HBV...

    Incorrect

    • One of your colleagues shares with you the fact that he is HBV positive. He's a general surgeon in the local hospital and he's afraid that if people know he might lose his job. However, you try to convince him that it's important to inform occupational health but he explicitly refuses. What is the most appropriate management?

      Your Answer:

      Correct Answer: Inform your colleague's employing body

      Explanation:

      According to the updated GMC guidelines, patient safety is more important than anything else, thus the correct thing to do is inform your colleague’s employing body.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 48 - Choose the best source of folic acid: ...

    Incorrect

    • Choose the best source of folic acid:

      Your Answer:

      Correct Answer: Liver

      Explanation:

      Beef liver is one of the best sources of folic acid, amongst others like green vegetables and nuts.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 49 - A 68-year-old male patient presents with haematemesis. Gastroscopy and biopsy reveal a carcinoma....

    Incorrect

    • A 68-year-old male patient presents with haematemesis. Gastroscopy and biopsy reveal a carcinoma. Who is the one to inform the patient of his diagnosis?

      Your Answer:

      Correct Answer: The consultant in-charge of his care

      Explanation:

      One of the questions the therapist poses himself while informing a patient is: whom shall I inform about the diagnosis, treatment and prognosis? If we unconditionally accepted the view that information belongs to the patient from an ethical and legal standpoint, we would automatically exclude the partner and the family. Therefore, the therapist should raise another question: what is the benefit to the patient? To answer the question and the resulting dilemma, we have to leverage the long experience of family therapy and tailor it to the cases we are dealing with. It should be taken into consideration that patient and family are a dynamic system which was balanced before the onset of the disease, but is now disrupted, entering into crisis. Therefore, the denial mechanisms and personality characteristics we have previously elaborated on, and communication among members play a crucial role in determining the information strategy and the way family should be approached. In this particular case, the most appropriate person to inform the patient is the consultant, meaning the one currently responsible for the patient’s care. The patient most probably has already developed some form of close and trustful relationship with his consultant.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 50 - Choose the part of the antibody to which immune cells bind: ...

    Incorrect

    • Choose the part of the antibody to which immune cells bind:

      Your Answer:

      Correct Answer: Fc region

      Explanation:

      Fc Receptors include the IgG receptors (FcγR), high-affinity IgE receptor (FcεRI), IgA and IgA/IgM receptors, and neonatal Fc receptor for IgG (FcRn). In particular, the FcγRs have been well known to play an important role in many biologic processes including those associated with the response to infection and cancer as well as in the pathogenesis of immune-mediated diseases. Fc receptors, the receptors for the Fc region of immunoglobulins, play an essential role in antibody-dependent immune responses. Fc receptors are detected on many types of hematopoietic cells including macrophages, neutrophils, dendritic cells, eosinophils, basophils, mast cells, and NK cells. Plasma cells produce five classes of antibodies, IgA, IgD, IgE, IgG and IgM. Fc receptors with an Ig superfamily related structure exist that correspond to each of these classes of immunoglobulins.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 51 - Which one of the following statements regarding interleukin 1 (IL-1) is true? ...

    Incorrect

    • Which one of the following statements regarding interleukin 1 (IL-1) is true?

      Your Answer:

      Correct Answer: It is released mainly by macrophages/monocytes

      Explanation:

      Interleukin 1 alpha and interleukin 1 beta (IL1 alpha and IL1 beta) are cytokines that participate in the regulation of immune responses, inflammatory reactions, and hematopoiesis. It is secreted mainly by macrophages and monocytes and acts as a costimulator of T cell and B cell proliferation.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 52 - A 36-year-old man is scheduled to start on interferon-alpha and ribavarin for the...

    Incorrect

    • A 36-year-old man is scheduled to start on interferon-alpha and ribavarin for the treatment of hepatitis C. His past history includes intravenous drug usage. Which are the most common side effects of interferon-alpha?

      Your Answer:

      Correct Answer: Depression and flu-like symptoms

      Explanation:

      Adverse effects due to IFN-alpha have been described in almost every organ system. Many side-effects are clearly dose-dependent. Taken together, occurrence of flu-like symptoms, haematological toxicity, elevated transaminases, nausea, fatigue, and psychiatric sequelae are the most frequently encountered side effects.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 53 - Which one of the following cardiac tissue types has the highest conduction velocity?...

    Incorrect

    • Which one of the following cardiac tissue types has the highest conduction velocity?

      Your Answer:

      Correct Answer: Purkinje fibres

      Explanation:

      Nerve conduction velocity is an important aspect of nerve conduction studies. It is the speed at which an electrochemical impulse propagates down a neural pathway. Ultimately, conduction velocities are specific to each individual and depend largely on an axon’s diameter and the degree to which that axon is myelinated.
      The cardiac action potential is a brief change in voltage (membrane potential) across the cell membrane of heart cells. Conduction speed varies:
      Atrial conduction spreads along ordinary atrial myocardial fibres at 1 m/sec
      AV node conduction 0.05 m/sec
      Ventricular conduction Purkinje fibres are of large diameter and achieve velocities of 2-4 m/sec (this allows a rapid and coordinated contraction of the ventricles.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 54 - A 33-year-old woman has missed her last two periods and has been lactating....

    Incorrect

    • A 33-year-old woman has missed her last two periods and has been lactating. Upon anamnesis, she claims she's lost weight and she's been suffering from vaginal dryness. The endocrinologist suggests that she checks her prolactin levels. Which of the following inhibits prolactin release from the hypophysis?

      Your Answer:

      Correct Answer: Dopamine

      Explanation:

      Dopamine (DA) holds a predominant role in the regulation of prolactin (PRL) secretion. Through a direct effect on anterior pituitary lactotrophs, DA inhibits the basally high-secretory tone of the cell. It accomplishes this by binding to D2 receptors expressed on the cell membrane of the lactotroph, activation of which results in a reduction of PRL exocytosis and gene expression by a variety of intracellular signalling mechanisms.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 55 - A 15-year-old girl is admitted to hospital following a ruptured ectopic pregnancy. She...

    Incorrect

    • A 15-year-old girl is admitted to hospital following a ruptured ectopic pregnancy. She comes from a family of Jehovah's Witnesses. Her haemoglobin on admission is 6.7 g/dl. She consents to a blood transfusion but her mother refuses. What is the most appropriate course of action?

      Your Answer:

      Correct Answer: Give the blood transfusion

      Explanation:

      People aged 16 or over are entitled to consent to their own treatment. This can only be overruled in exceptional circumstances. Children under the age of 16 can consent to their own treatment if they’re believed to have enough intelligence, competence and understanding to fully appreciate what’s involved in their treatment. This is known as being Gillick competent.

      Otherwise, someone with parental responsibility can consent for them.
      This could be:
      the child’s mother or father
      the child’s legally appointed guardian
      a person with a residence order concerning the child
      a local authority designated to care for the child
      a local authority or person with an emergency protection order for the child.
      Giving the blood transfusion is therefore both clinically and ethically the right course of action.
      Jehovah’s Witnesses frequently carry a signed and witnessed Advance Decision Document listing the blood products and autologous procedures that are, or are not, acceptable to them It is appropriate to have a frank, confidential discussion with the patient about the potential risks of their decision and the possible alternatives to transfusion, but the freely expressed wish of a competent adult must always be respected.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 56 - 170 patients are enrolled in a study to assess the addition of a...

    Incorrect

    • 170 patients are enrolled in a study to assess the addition of a new antiplatelet drug to aspirin for those who've had a stroke. Out of 170 patients, 120 received the aspirin in addition to the new drug with the remaining 50 patients receiving just aspirin. After 5 years, 18 out of the 120 patients receiving the new drug in addition to aspirin and 10 out of the 50 patients receiving just aspirin, had had a stroke. What is the number needed to treat?

      Your Answer:

      Correct Answer: 20

      Explanation:

      The number needed to treat (NNT) is valuable information in treatment decisions. NNT is the inverse of the absolute risk reduction (1/ARR) between two treatment options. Control event rate = 10 / 50 = 0.2
      Experimental event rate = 18 / 120 = 0.15

      Absolute risk reduction = 0.2 – 0.15 = 0.05
      Number needed to treat = 1 / 0.05 = 20

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 57 - A scientist is using denaturation, annealing and elongation to amplify a desired fragment...

    Incorrect

    • A scientist is using denaturation, annealing and elongation to amplify a desired fragment of DNA. Which molecular technique is he using?

      Your Answer:

      Correct Answer: Polymerase Chain Reaction (PCR)

      Explanation:

      PCR is a simple, yet elegant, enzymatic assay, which allows for the amplification of a specific DNA fragment from a complex pool of DNA. PCR can be performed using source DNA from a variety of tissues and organisms, including peripheral blood, skin, hair, saliva, and microbes. Only trace amounts of DNA are needed for PCR to generate enough copies to be analysed using conventional laboratory methods. For this reason, PCR is a sensitive assay. Each PCR assay requires the presence of template DNA, primers, nucleotides, and DNA polymerase. The DNA polymerase is the key enzyme that links individual nucleotides together to form the PCR product. The above mentioned components are mixed in a test tube or 96-well plate and then placed in a machine that allows repeated cycles of DNA amplification to occur in three basic steps. The machine is essentially a thermal cycler. It has a thermal block with holes, into which the test tubes or plates holding the PCR reaction mixture are inserted. The machine raises and lowers the temperature of the block in discrete, precise and pre-programmed steps. The reaction solution is first heated above the melting point of the two complementary DNA strands of the target DNA, which allows the strands to separate, a process called denaturation. The temperature is then lowered to allow the specific primers to bind to the target DNA segments, a process known as hybridization or annealing. Annealing between primers and the target DNA occurs only if they are complementary in sequence (e.g. A binding to G). The temperature is raised again, at which time the DNA polymerase is able to extend the primers by adding nucleotides to the developing DNA strand. With each repetition of these three steps, the number of copied DNA molecules doubles.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 58 - How is the left ventricular ejection fraction calculated? ...

    Incorrect

    • How is the left ventricular ejection fraction calculated?

      Your Answer:

      Correct Answer: Stroke volume / end diastolic LV volume

      Explanation:

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) * 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 59 - Which one of the following best describes the main action of the polymerase...

    Incorrect

    • Which one of the following best describes the main action of the polymerase chain reaction?

      Your Answer:

      Correct Answer: DNA amplification

      Explanation:

      Polymerase chain reaction (PCR) is a method widely used in molecular biology to make several copies of a specific DNA segment. Using PCR, copies of DNA sequences are exponentially amplified to generate thousands to millions of more copies of that particular DNA segment.The main advantage of PCR is its sensitivity: only one strand of sample DNA is needed to detect a particular DNA sequence. It now has many uses including prenatal diagnosis, detection of mutated oncogenes and diagnosis of infections. PCR is also extensively used in forensics.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 60 - What is the site of action of antidiuretic hormone? ...

    Incorrect

    • What is the site of action of antidiuretic hormone?

      Your Answer:

      Correct Answer: Collecting ducts

      Explanation:

      Vasopressin, also called antidiuretic hormone (ADH), regulates the tonicity of body fluids. It is released from the posterior pituitary in response to hypertonicity and promotes water reabsorption in the collecting ducts of the kidneys by the insertion of aquaporin-2 channels.. An incidental consequence of this renal reabsorption of water is concentrated urine and reduced urine volume. In high concentrations may also raise blood pressure by inducing moderate vasoconstriction.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 61 - Which of the following is caused by vitamin D? ...

    Incorrect

    • Which of the following is caused by vitamin D?

      Your Answer:

      Correct Answer: Increased plasma phosphate

      Explanation:

      Intestinal phosphate absorption is mediated by both transcellular and paracellular routes. The 1,25(OH)2D increases intestinal transcellular phosphate absorption at least in part by enhancing expression of type 2b sodium–phosphate cotransporter, thus increasing plasma phosphate.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 62 - Choose the most important stimulator of the central chemoreceptors: ...

    Incorrect

    • Choose the most important stimulator of the central chemoreceptors:

      Your Answer:

      Correct Answer: Decrease in pH

      Explanation:

      Central chemoreception refers to the detection of changes in CO2/H+ within the brain and the associated effects on breathing. In the conscious animal the response of ventilation to changes in the brain’s interstitial fluid (ISF) pH is very sensitive. Note that a small change in cerebrospinal fluid (CSF) pH from 7.30 to 7.25 is associated with a doubling of alveolar ventilation; it is a very sensitive reflex response. Note also that the relationship of alveolar ventilation to ISF pH is essentially the same for both types of stimulation, metabolic acid-base disorders and primary CO2 stimulation.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 63 - A 75-year-old woman experiences weakness of her left hand. Clinical examination reveals wasting...

    Incorrect

    • A 75-year-old woman experiences weakness of her left hand. Clinical examination reveals wasting of the hypothenar eminence and weakness of finger abduction and thumb adduction. The lesion is most probably located at:

      Your Answer:

      Correct Answer: Ulnar nerve

      Explanation:

      Patients with compressive neuropathy of the ulnar nerve typically describe numbness and tingling of the ulnar-sided digits of the hand, classically in the small finger and ulnar aspect of the ring finger. Among the general population, symptoms usually begin intermittently and are often worse at night, particularly if the elbow is flexed while sleeping. As the disease progresses, paraesthesia may occur more frequently and during the daytime.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 64 - Each one of the following statements regarding atrial natriuretic peptide are true, except:...

    Incorrect

    • Each one of the following statements regarding atrial natriuretic peptide are true, except:

      Your Answer:

      Correct Answer: Secreted mainly by the left atrium

      Explanation:

      Atrial natriuretic peptide (ANP) is a 28-amino acid peptide that is synthesized, stored, and released by atrial myocytes in response to atrial distension, angiotensin II stimulation, endothelin, and sympathetic stimulation (beta-adrenoceptor mediated). ANP is synthesized and secreted by cardiac muscle cells in the walls of the atria in the heart. The main physiological actions of natriuretic peptides is to reduce arterial pressure by decreasing blood volume and systemic vascular resistance. It causes a reduction in expanded extracellular fluid (ECF) volume by increasing renal sodium excretion.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 65 - A 19-year-old lady with established anorexia nervosa is admitted with a BMI of...

    Incorrect

    • A 19-year-old lady with established anorexia nervosa is admitted with a BMI of 16. However, she gives the consent to be fed by a nasogastric tube. Which of the following electrolyte disturbances are you most likely to find?

      Your Answer:

      Correct Answer: Hypophosphataemia

      Explanation:

      Refeeding syndrome can be defined as the potentially fatal shifts in fluids and electrolytes that may occur in malnourished patients receiving artificial refeeding (whether enterally or parenterally). These shifts result from hormonal and metabolic changes and may cause serious clinical complications. The hallmark biochemical feature of refeeding syndrome is hypophosphatemia. However, the syndrome is complex and may also feature abnormal sodium and fluid balance; changes in glucose, protein, and fat metabolism; thiamine deficiency; hypokalaemia; and hypomagnesaemia.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 66 - A 38-year-old female is referred to the dermatologist for a rash on both...

    Incorrect

    • A 38-year-old female is referred to the dermatologist for a rash on both her elbows. The rash is red, is papulovesicular in nature, and looks like it has many small blisters. The dermatologist diagnoses her with dermatitis herpetiformis. Which HLA haplotype is this associated with?

      Your Answer:

      Correct Answer: HLA-DR3

      Explanation:

      Dermatitis herpetiformis (DH), or Duhring’s disease, is a chronic blistering skin condition,characterised by blisters filled with a watery fluid. Despite its name, it is neither related to nor caused by herpes virus: the name means that it is a skin inflammation having an appearance similar to herpes.
      Dermatitis herpetiformis is characterized by intensely itchy, chronic papulovesicular eruptions, usually distributed symmetrically on extensor surfaces (buttocks, back of neck, scalp, elbows, knees, back, hairline, groin, or face)
      Dermatitis herpetiformis is an autoimmune condition associated with HLA-DR3.
      HLA-A3 is associated with haemochromatosis. HLA-B5 is most commonly associated with Behcet’s disease. HLA-DR4 is associated with both type 1 diabetes mellitus and rheumatoid arthritis. HLA-B27 is most commonly associated with several diseases, most commonly ankylosing spondylitis.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 67 - A 23-year-old woman presents to the A&E with a 24-hour-history of gradual-onset fever,...

    Incorrect

    • A 23-year-old woman presents to the A&E with a 24-hour-history of gradual-onset fever, light sensitivity and headache. Clinical examination reveals neck stiffness and an area of rash which does not disappear upon pressure on her right shin. Anamnesis reveals a history of 3 episodes of meningococcal meningitis in the past and she was started on ceftriaxone for another suspected meningitis. However, you suspect that the patients might be immunodeficient. Which immunodeficiency does she most probably have?

      Your Answer:

      Correct Answer: C5-9 deficiency

      Explanation:

      Pneumococcal meningitis is the most common and severe form of bacterial meningitis. Fatality rates are substantial, and long-term sequelae develop in about half of survivors. Disease outcome has been related to the severity of the proinflammatory response in the subarachnoid space. The complement system, which mediates key inflammatory processes, has been implicated as a modulator of pneumococcal meningitis disease severity in animal studies. C5 fragment levels in cerebrospinal fluid (CSF) of patients with bacterial meningitis correlated with several clinical indicators of poor prognosis. The common terminal pathway consists of complement components C5–C9, and activation forms the anaphylatoxin C5a, a strong proinflammatory mediator, and the membrane attack complex (MAC), which creates pores in the bacterial cell wall (12). Deficiencies in these late complement components have been recognized as a cause of recurrent and familial meningococcal infections.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 68 - A study is developed to compare two chemotherapy schemas for individuals with small...

    Incorrect

    • A study is developed to compare two chemotherapy schemas for individuals with small cell lung cancer. Which of the following would you choose to compare survival time with in this particular study?

      Your Answer:

      Correct Answer: Hazard ratio

      Explanation:

      The hazard ratio describes the relative risk of the complication based on comparison of event rates.

      Hazard ratios have also been used to describe the outcome of therapeutic trials where the question is to what extent treatment can shorten the duration of the illness. However, the hazard ratio, a type of relative risk, does not always accurately portray the degree of abbreviation of the illness that occurred. In these circumstances, time-based parameters available from the time-to-event curve, such as the ratio of the median times of the placebo and drug groups, should be used to describe the magnitude of the benefit to the patient. The difference between hazard-based and time-based measures is analogous to the odds of winning a race and the margin of victory. The hazard ratio is the odds of a patient’s healing faster under treatment but does not convey any information about how much faster this event may occur.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 69 - A 36-year-old lady with back pain is found to have loss of sensation...

    Incorrect

    • A 36-year-old lady with back pain is found to have loss of sensation of the kneecaps. Choose the dermatome most likely compromised:

      Your Answer:

      Correct Answer: L4

      Explanation:

      L4 dermatome distribution includes the kneecaps.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 70 - A 23-year-old man is referred to the pneumologist with a suspicion of bronchiectasis....

    Incorrect

    • A 23-year-old man is referred to the pneumologist with a suspicion of bronchiectasis. History reveals he's been having recurrent pulmonary infections his whole life together with difficulties gaining weight. He's a non-smoker with a clear family history and he admits inhalers haven't helped him in the past. He is finally suspected of having cystic fibrosis. What is the normal function of the cystic fibrosis transmembrane regulator?

      Your Answer:

      Correct Answer: Chloride channel

      Explanation:

      Chloride channels are involved in a diverse set of functions in normal physiology and acquired diseases. Additionally, there are genetic diseases caused by mutations in chloride channels (channelopathies) — the most common being cystic fibrosis, which has a prevalence of 1 in 2,000 Caucasians.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 71 - Which is the formula to calculate the number needed to treat? ...

    Incorrect

    • Which is the formula to calculate the number needed to treat?

      Your Answer:

      Correct Answer: 1 / (Absolute risk reduction)

      Explanation:

      The number needed to treat (NNT) is valuable information in treatment decisions. NNT is the inverse of the absolute risk reduction (1/ARR) between two treatment options.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 72 - You want to compare a new oral hypoglycaemic drug with an existing treatment,...

    Incorrect

    • You want to compare a new oral hypoglycaemic drug with an existing treatment, which would also lower HbA1c. Which study design would you choose?

      Your Answer:

      Correct Answer: Superiority trial

      Explanation:

      When the aim of the randomized controlled trial (RCT) is to show that one treatment is superior to another, a statistical test is employed and the trial (test) is called a superiority trial (test).

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 73 - A 60-year-old male presents with dyspnoea and an urgent chest X-ray is scheduled....

    Incorrect

    • A 60-year-old male presents with dyspnoea and an urgent chest X-ray is scheduled. Sputum cultures reveal pneumonia and he receives treatment with erythromycin. What is the mechanism of action of this drug?

      Your Answer:

      Correct Answer: Inhibit 50S subunit of ribosomes

      Explanation:

      Erythromycin is a bacteriostatic antibiotic. This means it stops the further growth of bacteria rather than directly destroying it. This is achieved by inhibiting protein synthesis. Erythromycin binds to the 23S ribosomal RNA molecule in the 50S subunit of the bacterial ribosome. This causes a blockage in the exiting of the peptide chain that is growing. Given that humans have 40S and 60S subunits, and do not have 50S subunits, erythromycin does not affect protein synthesis in human tissues.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 74 - A 21-year-old man presents with a three day history of general malaise and...

    Incorrect

    • A 21-year-old man presents with a three day history of general malaise and low-grade temperature. Yesterday he developed extensive painful ulceration of his mouth and gums. On examination his temperature is 37.4ºC, pulse 84 / min and there is submandibular lymphadenopathy. What is the most likely diagnosis?

      Your Answer:

      Correct Answer: Herpes simplex virus infection

      Explanation:

      This man has gingivostomatitis, a characteristic feature of primary herpes simplex virus infection. Herpetic gingivostomatitis is often the initial presentation during the first (primary) herpes simplex infection. It is of greater severity than herpes labialis (cold sores) which is often the subsequent presentations. Primary herpetic gingivostomatitis is the most common viral infection of the mouth.
      Primary herpetic gingivostomatitis (PHGS) is caused predominantly by HSV-1 and affects mainly children. Prodromal symptoms, such as fever, anorexia, irritability, malaise and headache, may occur in advance of disease. Sub-mandibular lymphadenitis, halitosis and refusal to drink are usual concomitant findings.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 75 - A cohort study is developed to assess the correlation between blood pressure and...

    Incorrect

    • A cohort study is developed to assess the correlation between blood pressure and working long hours. After 10 years of follow-up and for the 1050 individuals working less than 40 hours per week, 1000 patients had normal blood pressure and 50 patients were diagnosed with hypertension. For the 660 patients working more than 40 hours per week, 600 patients had normal blood pressure and 60 patients were diagnosed with hypertension. If you work more than 40 hours per week, what is the odds ratio of developing hypertension compared to the individuals working less than 40 hours per week?

      Your Answer:

      Correct Answer: 2

      Explanation:

      An odds ratio (OR) is a measure of the association between an exposure and an outcome. The OR represents the odds that an outcome will occur given a particular exposure, compared to the odds of the outcome occurring in the absence of that exposure. Odds ratios are most commonly used in case-control studies, however they can also be used in cross-sectional and cohort study designs as well (with some modifications and/or assumptions). Where

      a = Number of exposed cases

      b = Number of exposed non-cases

      c = Number of unexposed cases

      d = Number of unexposed non-cases

      OR=(a/c) / (b/d) = ad/bc

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 76 - A 55-year-old woman with established metastatic breast cancer is admitted to the A&E...

    Incorrect

    • A 55-year-old woman with established metastatic breast cancer is admitted to the A&E with hypercalcemia. She has a clear medical history, doesn't smoke and works in an office based job. At the A&E she's given intravenous fluids and bisphosphonates. She's finally discharged after normalization of her calcium levels. However, before leaving the hospital she's sent to the endocrinology department for consultation regarding outpatient care and serum calcium monitoring. What is the most appropriate and useful advice for this patient?

      Your Answer:

      Correct Answer: Increase fluid intake

      Explanation:

      NICE guidelines on hypercalcemia recommend that maintaining good hydration equals drinking 3-4 L of fluid/day, provided there are no contraindications. A low calcium diet is not necessary because intestinal absorption of calcium is reduced. The patient should avoid any other drugs or vitamins that could worsen the hypercalcemia. Mobilization is encouraged and any symptoms of hypercalcemia should be reported.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 77 - From which cells is somatostatin secreted? ...

    Incorrect

    • From which cells is somatostatin secreted?

      Your Answer:

      Correct Answer: D cells in the pancreas

      Explanation:

      The somatostatin-secreting D-cells comprise ,5% of the cells of the pancreatic islets. The D-cells have a complex morphology and may, via cellular process, interact with many more islet cells than suggested by their low number. D-cells are equipped with ATP-sensitive potassium channels (KATP channels).

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 78 - Choose the correct statement regarding leptin: ...

    Incorrect

    • Choose the correct statement regarding leptin:

      Your Answer:

      Correct Answer: Is produced mainly by the hypothalamus

      Explanation:

      Leptin, a 167–amino acid hormone, was discovered in 1994 and is secreted mainly by adipocytes. Plasma leptin levels are significantly correlated with body mass index (BMI) and the total amount of body fat.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 79 - A 54-year-old female patient presents with a one week history of bloody diarrhoea,...

    Incorrect

    • A 54-year-old female patient presents with a one week history of bloody diarrhoea, fever and abdominal pain. She has a history of rheumatoid arthritis which she controls with methotrexate. Her stool sample shows Campylobacter jejuni. What is the single most appropriate management?

      Your Answer:

      Correct Answer: Fluids + clarithromycin

      Explanation:

      This woman is receiving methotrexate, an immunosuppressant, to control her rheumatoid arthritis. In such immunocompromised patients, BNF suggests clarithromycin as first-line management.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 80 - A 40-year-old female patient with a history of rheumatoid arthritis is diagnosed with...

    Incorrect

    • A 40-year-old female patient with a history of rheumatoid arthritis is diagnosed with type 1 renal tubular acidosis. What is the most probable sequela of this condition?

      Your Answer:

      Correct Answer: Nephrocalcinosis

      Explanation:

      Distal renal tubular acidosis is due to defective proton secretion from the alpha intercalated cells of the distal tubule caused by dysfunction of the H+/K+ antiporter on the apical membrane. This leads to failure of H+ excretion thereby causing systemic acidosis and potassium depletion. Inability to lower the urine pH below 5.3 in the presence of systemic acidosis is the diagnostic hallmark of type I or distal renal tubular acidosis. Hypercalciuria, hypocitraturia and elevated urinary pH observed in distal renal tubular acidosis can lead to nephrocalcinosis and may cause renal calculi, obstructive uropathy and renal failure necessitating surgical or endoscopic stone extraction.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 81 - A non-cyanosed 1-year-old female patient has a continuous murmur which is loudest at...

    Incorrect

    • A non-cyanosed 1-year-old female patient has a continuous murmur which is loudest at the left sternal edge. What pulse abnormality is most associated with patent ductus arteriosus if that's her suspected diagnosis?

      Your Answer:

      Correct Answer: Collapsing pulse

      Explanation:

      DIAGNOSIS:
      A consensus definition for hemodynamically significant PDA is lacking. The diagnosis is often suspected clinically, when an infant demonstrates signs of excessive shunting from the arterial to pulmonary circulation. Continuous or a systolic murmur; note, a “silent” PDA may also occur when the ductus shunt is large enough that nonturbulent flow fails to generate a detectible murmur.
      A low diastolic blood pressure (due to runoff into the ductus during diastole, more frequent in the most premature infants).
      A wide pulse pressure (due to ductus runoff or steal)Hypotension (especially in the most premature infants)
      Bounding pulses
      Increased serum creatinine concentration or oliguria
      Hepatomegaly

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 82 - A 35-year-old male is admitted following a collapse while competiung in an iron...

    Incorrect

    • A 35-year-old male is admitted following a collapse while competiung in an iron man triathlon. His blood results are as follows: Na+: 122 mmol/L, K+: 3.4 mmol/L, Urea: 3.2 mmol/L, Creatinine: 69 umol/l. During assessment he becomes increasingly obtunded and goes on to have multiple tonic clonic seizures. What is the most appropriate treatment from the list below to improve his neurological status?

      Your Answer:

      Correct Answer: Hypertonic saline

      Explanation:

      Over consumption of fluids, prolonged race duration and inadequate training all can predispose to acute hyponatraemia.
      Mild symptoms include a decreased ability to think, headaches, nausea, and an increased risk of falls. Severe symptoms include confusion, seizures, and coma. Normal serum sodium levels are 135 – 145 mEq/liter (135 – 145 mmol/L). Hyponatremia is generally defined as a serum sodium level of less than 135 mEq/L and is considered severe when the level is below 120 mEq/L.
      The correct treatment to give is hypertonic saline. Decompressive craniotomy would help alleviate raised intracranial pressure due to cerebral oedema however is not an appropriate first line treatment. Demeclocycline is used for SIADH and mannitol is more likely to be used in the context of traumatic brain injury.
      Hyponatremia is corrected slowly, to lessen the risk of the development of central pontine myelinolysis (CPM), a severe neurological disease involving a breakdown of the myelin sheaths covering parts of nerve cells. During treatment of hyponatremia, the serum sodium (salt level in the blood) should not rise by more than 8 mmol/L over 24 hours.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 83 - A 22-year-old man presents with red and flaky patches at the corners of...

    Incorrect

    • A 22-year-old man presents with red and flaky patches at the corners of his mouth. Upon examination, angular cheilitis is diagnosed. Anamnesis reveals a history of excessive drinking and malnutrition. What is the most probable deficiency responsible for his condition?

      Your Answer:

      Correct Answer: Vitamin B2 deficiency

      Explanation:

      Riboflavin, vitamin B2, is a water-soluble and heat-stable vitamin that the body uses to metabolize fats, protein, and carbohydrates into glucose for energy. Riboflavin deficiency can cause fatigue, swollen throat, blurred vision, and depression. It can affect the skin by causing skin cracks, itching, and dermatitis around the mouth. Hyperaemia and oedema around throat, liver degeneration, and hair loss can also occur along with reproductive issues. Usually, people with riboflavin deficiency also have deficiencies of other nutrients. In most cases, riboflavin deficiency can be reversed unless it has caused anatomical changes such as cataracts.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 84 - Sensorineural deafness is strongly associated with which one of the following? ...

    Incorrect

    • Sensorineural deafness is strongly associated with which one of the following?

      Your Answer:

      Correct Answer: Rubella

      Explanation:

      Primary rubella infection during pregnancy, particularly during the first trimester, can affect several organs and cause birth defects that are responsible for congenital rubella syndrome (CRS). The most common defects of CRS are hearing impairment (unilateral or bilateral sensorineural), eye defects (e.g., cataracts, congenital glaucoma, or pigmentary retinopathy), and cardiac defects (e.g., patent ductus arteriosus or peripheral pulmonic stenosis). Congenital hearing loss is the most common sequela, occurring in approximately 60% of cases, especially when infection occurs in the 4th month of pregnancy.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 85 - A woman with severe renal failure undergoes a kidney transplant. However, after a...

    Incorrect

    • A woman with severe renal failure undergoes a kidney transplant. However, after a few hours, she develops fever and anuria. The doctors are suspecting hyperacute organ rejection. Which are the cells primarily responsible for hyperacute organ rejection?

      Your Answer:

      Correct Answer: B Cells

      Explanation:

      Hyperacute rejection appears in the first minutes following transplantation and occurs only in vascularized grafts. This very fast rejection is characterized by vessel thrombosis leading to graft necrosis. Hyperacute rejection is caused by the presence of antidonor antibodies existing in the recipient before transplantation. These antibodies induce both complement activation and stimulation of endothelial cells to secrete Von Willebrand procoagulant factor, resulting in platelet adhesion and aggregation. The result of these series of reactions is the generation of intravascular thrombosis leading to lesion formation and ultimately to graft loss. Today, this type of rejection is avoided in most cases by checking for ABO compatibility and by excluding the presence of antidonor human leukocyte antigen (HLA) antibodies by cross-match techniques between donor graft cells and recipient sera. This type of rejection is also observed in models of xenotransplantation of vascularized organs between phylogenetically distant species when no immunosuppressive treatment is given to the recipients.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 86 - Which form of study design would you choose if you were trying to...

    Incorrect

    • Which form of study design would you choose if you were trying to ascertain whether the use of dummies in infants is correlated with sudden infant death syndrome?

      Your Answer:

      Correct Answer: Case-control study

      Explanation:

      A case-control study is designed to help determine if an exposure is associated with an outcome (i.e., disease or condition of interest). In theory, the case-control study can be described simply. Case-control studies have specific advantages compared to other study designs. They are comparatively quick, inexpensive, and easy. They are particularly appropriate for (1) investigating outbreaks, and (2) studying rare diseases or outcomes. Sudden infant death syndrome is a rare medical event, thus case-control study is the most suitable option.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 87 - A study is developed to look at the potential of hip protectors to...

    Incorrect

    • A study is developed to look at the potential of hip protectors to reduce femoral neck fractures in elderly nursing home patients. The study included 800 patients randomly selected with an average age of 82 years of age. The data was collected over a two year period and the patients were randomly put in the standard care group or the hip protector group. From the 400 patients assigned to the hip protector group, 10 had a femoral neck fracture over the two year period. From the 400 patients assigned to the standard care group, 20 had a femoral neck fracture over the two year period. What is the correct value regarding the absolute risk reduction?

      Your Answer:

      Correct Answer: 0.025

      Explanation:

      Absolute risk reduction (ARR) – also called risk difference (RD) – is the most useful way of presenting research results to help your decision-making. In this example, the ARR is 8 per cent (20 per cent – 12 per cent = 8 per cent). This means that, if 100 children were treated, 8 would be prevented from developing bad outcomes. Another way of expressing this is the number needed to treat (NNT). If 8 children out of 100 benefit from treatment, the NNT for one child to benefit is about 13 (100 ÷ 8 = 12.5). CER = 20 / 400 = 1 / 20 = 0.05, EER = 10 / 400 = 0.025, ARR =CER – EER = 0.025

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 88 - A 65-year-old woman with type 2 diabetes mellitus is feeling more fatigued than...

    Incorrect

    • A 65-year-old woman with type 2 diabetes mellitus is feeling more fatigued than usual. She has not attended the previous three annual check-ups and her blood glucose control has been poor. She has not been compliant with his medications. Blood pressure is 170/90 mmHg. Urinalysis shows microalbuminuria. A blood test reveals her glomerular filtration rate (GFR) is 26mL/min. If a renal biopsy was to be performed in this patient, what would be the expected findings?

      Your Answer:

      Correct Answer: Nodular glomerulosclerosis and hyaline arteriosclerosis

      Explanation:

      This patient has a poorly controlled T2DM with an underlying diabetic nephropathy. The histological findings are Kimmelstiel-Wilson lesions (nodular glomerulosclerosis) and hyaline arteriosclerosis. This is due to nonenzymatic glycosylation.

      Diabetic nephropathy is the chronic loss of kidney function occurring in those with diabetes mellitus. Protein loss in the urine due to damage to the glomeruli may become massive, and cause a low serum albumin with resulting generalized body swelling (edema) and result in the nephrotic syndrome. Likewise, the estimated glomerular filtration rate (eGFR) may progressively fall from a normal of over 90 ml/min/1.73m2 to less than 15, at which point the patient is said to have end-stage kidney disease (ESKD). It usually is slowly progressive over years.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 89 - Choose the wrong statement regarding hypocalcaemia: ...

    Incorrect

    • Choose the wrong statement regarding hypocalcaemia:

      Your Answer:

      Correct Answer: Chvostek's sign is more sensitive and specific than Trousseau's sign

      Explanation:

      Chvostek and Trousseau signs can be elicited in patients with hypocalcaemia. Chvostek sign is the twitching of the upper lip with tapping on the cheek 2 cm anterior to the earlobe, below the zygomatic process overlying the facial nerve. Trousseau sign (a more reliable sign present in 94% of hypokalaemic individuals and only 1% to 4% of healthy people) is the presence of carpopedal spasm observed following application of an inflated blood pressure cuff over systolic pressure for 3 minutes in hypokalaemic patients.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 90 - Which one of the following statements regarding epidemiological measures is correct? ...

    Incorrect

    • Which one of the following statements regarding epidemiological measures is correct?

      Your Answer:

      Correct Answer: Cross-sectional surveys can be used to estimate the prevalence of a condition in the population

      Explanation:

      The incidence rate is the number of new cases per population at risk in a given time period. For example, if a population initially contains 1,000 non-diseased persons and 28 develop a condition over two years of observation, the incidence proportion is 28 cases per 1,000 persons per two years, i.e. 2.8% per two years.
      Prevalence is the proportion of a particular population found to be affected by a medical condition (typically a disease or a risk factor such as smoking or seat-belt use). It is derived by comparing the number of people found to have the condition with the total number of people studied, and is usually expressed as a fraction, as a percentage, or as the number of cases per 10,000 or 100,000 people.
      Incidence should not be confused with prevalence, which is the proportion of cases in the population at a given time rather than rate of occurrence of new cases. Thus, incidence conveys information about the risk of contracting the disease, whereas prevalence indicates how widespread the disease is.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 91 - A 42-year-old man with a 6 month history of progressive weakness of both...

    Incorrect

    • A 42-year-old man with a 6 month history of progressive weakness of both lower limbs, complains of lethargy and of difficulties climbing stairs. He also claims he's experienced muscle loss in his lower limbs. History reveals type 2 diabetes mellitus and heavy alcohol use for the last 4 years. Clinical examination reveals marked loss of fine touch and proprioception. The distribution is in a stocking manner and bilateral. However, no evidence of ataxia is present. What is the most probable diagnosis?

      Your Answer:

      Correct Answer: Dry beriberi

      Explanation:

      Hypovitaminosis B1, consistent with dry beriberi is crucially a treatable condition, although sometimes with incomplete recovery, but it is probably under-recognized yet increasingly common given increasing levels of alcohol abuse in the western world. Dry beriberi or ‘acute nutritional polyneuropathy’ is considered to be rare in the western world. Rapid deterioration can occur, typically with weakness, paraesthesia and neuropathic pain. Striking motor nerve involvement can occur, mimicking Guillain-Barré syndrome (GBS). In the context of increasing alcohol abuse in the western world, it is possible that alcoholic neuropathy associated with abrupt deterioration due to concomitant nutritional hypovitaminosis B1 may be seen increasingly often.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 92 - Which is the most common chromosomal defect in Down's syndrome? ...

    Incorrect

    • Which is the most common chromosomal defect in Down's syndrome?

      Your Answer:

      Correct Answer: Non-dysjunction

      Explanation:

      Nondisjunction of chromosome 21 is the leading cause of Down syndrome. Two risk factors for maternal nondisjunction of chromosome 21 are increased maternal age and altered recombination.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 93 - A 45-year-old woman with a history of hypothyroidism, presents with ptosis and muscle...

    Incorrect

    • A 45-year-old woman with a history of hypothyroidism, presents with ptosis and muscle weakness. She's noticed that her muscle weakness becomes worse towards the end of the day. Clinical examination reveals fatigable ptosis and proximal limb weakness. Myasthenia gravis is suspected. Which receptor is implicated in the pathophysiology of this condition?

      Your Answer:

      Correct Answer: Nicotinic acetylcholine receptors

      Explanation:

      Myasthenia gravis (MG) is an organ-specific autoimmune disease caused by an antibody-mediated assault on the muscle nicotinic acetylcholine receptor (AChR) at the neuromuscular junction. Binding of antibodies to the AChR leads to loss of functional AChRs and impairs the neuromuscular signal transmission, resulting in muscular weakness.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 94 - A 34-year-old woman is admitted to the oncologist clinic for further investigations. She...

    Incorrect

    • A 34-year-old woman is admitted to the oncologist clinic for further investigations. She has experienced fever, sometimes glandular and night sweats. Clinical examination reveals lymphadenopathy and a biopsy is performed. The biopsy reveals the presence of Reed-Sternberg cells, confirming what was suspected to be a Hodgkin's lymphoma. Which cell surface marker is associated with this condition?

      Your Answer:

      Correct Answer: CD15

      Explanation:

      The CD15 antigen, also known as Lewis (hapten)X, serves as an immuno-phenotypic marker for Reed-Sternberg cells and its expression has diagnostic, but also prognostic significance in Hodgkin Lymphoma.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 95 - A study is developed to assess a new anti-hypertensive drug and two groups...

    Incorrect

    • A study is developed to assess a new anti-hypertensive drug and two groups of patients are randomly chosen. The first group takes an established anti-hypertensive drug for 3 months and the second group receives the new drug, again for 3 months. To assess the efficacy of the new drug, blood pressure is measured before and after taking the drug in both groups of patients. After a period of 1 month off medication, the groups swap medication and blood pressure is measured again, finally the difference in blood pressure after receiving each drug is calculated. Which of the following significance tests would you apply to assess the results of the study?

      Your Answer:

      Correct Answer: Student's paired t-test

      Explanation:

      A t test is a type of statistical test that is used to compare the means of two groups. It is one of the most widely used statistical hypothesis tests in pain studies. There are two types of statistical inferences: parametric and nonparametric methods. Parametric methods refer to a statistical technique in which one defines the probability distribution of probability variables and makes inferences about the parameters of the distribution. In cases in which the probability distribution cannot be defined, nonparametric methods are employed. T tests are a type of parametric method; they can be used when the samples satisfy the conditions of normality, equal variance, and independence. In this case the data is parametric, and they belong to the same patients, so a paired t test should be used.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 96 - What percentage of values lie within 3 standard deviations of the mean in...

    Incorrect

    • What percentage of values lie within 3 standard deviations of the mean in a normal distribution?

      Your Answer:

      Correct Answer: 99.70%

      Explanation:

      Normal distribution describes the spread of many biological and clinical measurements. Usually, 68.3% lies within 1 standard deviation (SD) of the mean, 95.4% lies within 2 SD of the mean and 99.7% lies within 3 SD of the mean.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 97 - An 18-year-old male was diagnosed with meningococcal meningitis, confirmed on lumbar puncture. After...

    Incorrect

    • An 18-year-old male was diagnosed with meningococcal meningitis, confirmed on lumbar puncture. After 6 months he presents in the infectious clinic with a second episode of meningitis. His past history is clear and he takes no regular medication. Which of the following is most probably deficient?

      Your Answer:

      Correct Answer: C5

      Explanation:

      Pneumococcal meningitis is the most common and severe form of bacterial meningitis. Fatality rates are substantial, and long-term sequelae develop in about half of survivors. Disease outcome has been related to the severity of the proinflammatory response in the subarachnoid space. The complement system, which mediates key inflammatory processes, has been implicated as a modulator of pneumococcal meningitis disease severity in animal studies. C5 fragment levels in cerebrospinal fluid (CSF) of patients with bacterial meningitis correlated with several clinical indicators of poor prognosis.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 98 - A 29-year-old male patient with a history of three previous chest infections in...

    Incorrect

    • A 29-year-old male patient with a history of three previous chest infections in the past seven months presents with fever, pleuritic pain and productive cough. Chest x-ray shows lobar consolidation and the diagnosis of a fourth chest infection is established, after sputum culture reveals Haemophilus influenzae. The previous chest infections were due to Streptococcus pneumoniae. After a period of six weeks, a full blood count, urea, CRP, electrolytes and chest x-ray turn out as normal. What is the investigation you would choose next?

      Your Answer:

      Correct Answer: Serum immunoglobulins

      Explanation:

      Hypogammaglobulinemia occurs due to a variety of underlying primary or secondary immunodeficient states, including HIV which is suspected in this case. The most commonly recognised clinical feature is recurrent infection.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 99 - A case-control study is being designed to look at the relationship between eczema...

    Incorrect

    • A case-control study is being designed to look at the relationship between eczema and a new vaccine for yellow fever. What is the usual outcome measure in a case-control study?

      Your Answer:

      Correct Answer: Odds ratio

      Explanation:

      A case–control study (also known as case–referent study) is a type of observational study in which two existing groups differing in outcome are identified and compared on the basis of some supposed causal attribute. Case–control studies are often used to identify factors that may contribute to a medical condition by comparing subjects who have that condition/disease (the cases) with patients who do not have the condition/disease but are otherwise similar (the controls).
      An odds ratio (OR) is a statistic that quantifies the strength of the association between two events, A and B. The odds ratio is defined as the ratio of the odds of A in the presence of B and the odds of A in the absence of B or vice versa.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 100 - Primarily, funnel plots are used to do what? ...

    Incorrect

    • Primarily, funnel plots are used to do what?

      Your Answer:

      Correct Answer: Demonstrate the existence of publication bias in meta-analyses

      Explanation:

      Funnel plots are graphical tools to assess and compare clinical performance of a group of care professionals or care institutions on a quality indicator against a benchmark. Incorrect construction of funnel plots may lead to erroneous assessment and incorrect decisions potentially with severe consequences.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 101 - Choose the correct stage in the cell cycle that vincristine acts on: ...

    Incorrect

    • Choose the correct stage in the cell cycle that vincristine acts on:

      Your Answer:

      Correct Answer: M

      Explanation:

      Vincristine is part of the antimitotic agents, cell cycle specific (M phase). It binds to microtubules in the spindle apparatus and prevents their proper function, finally arresting mitosis.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 102 - Choose the correct statement regarding relative risk: ...

    Incorrect

    • Choose the correct statement regarding relative risk:

      Your Answer:

      Correct Answer: It is the usual outcome measure of cohort studies

      Explanation:

      Relative Risk = (Probability of event in exposed group) / (Probability of event in not exposed group). The relative risk is mistaken by some, with the odds ratio and absolute risk. Relative risk is the ratio of the probability of an event occurring with an exposure versus the probability of the event occurring without the exposure. Thus to calculate the relative risk, we must know the exposure status of all individuals (either exposed or not exposed). This implies that relative risk is only appropriate for cases where the exposure status and incidence of disease can be accurately determined such as prospective cohort studies.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 103 - A study is developed to assess a new mandible advancement device designed to...

    Incorrect

    • A study is developed to assess a new mandible advancement device designed to reduce snoring. A 10 point scale was used to assess the severity of snoring before and after applying of the device by the respective partner. The number of the people involved in the study was 50. What test would you apply in this particular study?

      Your Answer:

      Correct Answer: Wilcoxon signed-rank test

      Explanation:

      Steps required in performing the Wilcoxon signed rank test:

      1 State the null hypothesis and, in particular, the hypothesized value for comparison
      2 Rank all observations in increasing order of magnitude, ignoring their sign. Ignore any observations that are equal to the hypothesized value. If two observations have the same magnitude, regardless of sign, then they are given an average ranking
      3 Allocate a sign (+ or -) to each observation according to whether it is greater or less than the hypothesized value (as in the sign test)
      4 Calculate:
      R+ = sum of all positive ranks
      R- = sum of all negative ranks
      R = smaller of R+ and R-
      5 Calculate an appropriate P value What makes this test the most appropriate for this study is that the data is non-parametric, paired and comes from the same population.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 104 - A 23-year-old male patient with a downward dislocation of the lens in his...

    Incorrect

    • A 23-year-old male patient with a downward dislocation of the lens in his right eye is experiencing visual problems. The ophthalmologist notes a constellation of symptoms resembling those of Marfan Syndrome. The patient's history reveals learning disabilities and a diagnosis of homocystinuria is suspected. What is the pathophysiology of homocystinuria?

      Your Answer:

      Correct Answer: Deficiency of cystathionine beta synthase

      Explanation:

      Inherited metabolic disorders are often characterized by the lack of an essential enzyme and are currently treated by dietary restriction and other strategies to replace the substrates or products of the missing enzyme. Patients with homocystinuria lack the enzyme cystathionine β-synthase (CBS), and many of these individuals do not respond to current treatment protocols.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 105 - Which one of the following statements regarding nitric oxide is incorrect? ...

    Incorrect

    • Which one of the following statements regarding nitric oxide is incorrect?

      Your Answer:

      Correct Answer: Promotes platelet aggregation

      Explanation:

      Nitric oxide, known as an endothelium-derived relaxing factor (EDRF), is biosynthesized endogenously from L-arginine, oxygen, and NADPH by various nitric oxide synthase (NOS) enzymes and is a signaling molecule in many physiological and pathological processes in humans.
      One of the main enzymatic targets of nitric oxide is guanylyl cyclase. The binding of nitric oxide to the haem region of the enzyme leads to activation, in the presence of iron.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 106 - Which one of the following is true regarding Escherichia coli infection? ...

    Incorrect

    • Which one of the following is true regarding Escherichia coli infection?

      Your Answer:

      Correct Answer: E coli is an important cause of neonatal meningitis

      Explanation:

      Escherichia coli (also known as E. coli) is a gram-negative, facultatively anaerobic, rod-shaped bacterium commonly found in the lower intestine of warm-blooded organisms. Most E. coli strains are harmless, but some serotypes can cause serious food poisoning in their hosts, and are occasionally responsible for product recalls due to food contamination. The harmless strains are part of the normal flora of the gut, and can benefit their hosts by producing vitamin K2, and preventing colonization of the intestine with pathogenic bacteria. Virulent strains can cause gastroenteritis, urinary tract infections, and neonatal meningitis.
      The most common causes of neonatal meningitis is bacterial infection of the blood, known as bacteremia (specifically Group B Streptococci (GBS; Streptococcus agalactiae), Escherichia coli, and Listeria monocytogenes). Although there is a low mortality rate in developed countries, there is a 50% prevalence rate of neurodevelopmental disabilities in E. coli and GBS meningitis

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 107 - A 55-year-old female with a history of osteoarthritis of the knee, obesity and...

    Incorrect

    • A 55-year-old female with a history of osteoarthritis of the knee, obesity and depression, presents with neck and right arm pain. She claims that the pain is present for two months and is triggered by flexing her neck. Clinical examination reveals sensory loss over the middle finger and palm of the hand without any obvious muscle atrophy or weakness. Which nerve root is most probably affected?

      Your Answer:

      Correct Answer: C7

      Explanation:

      The most common cause of cervical radiculopathy is degenerative disease in the cervical spine. In 80–90% of patients with cervical radiculopathy, the C5/C6 or C6/C7 motion segments are affected by degenerative disease and the nearby C6 and/or C7 nerve roots are producing the symptoms. Patients with cervical radiculopathy complain of neck pain and radiating pain in the arm sometimes combined with sensory and motor disturbances in the arm and/or hand. These symptoms are accepted as being caused by the nerve root compression. Middle finger and palm of the hand are mostly rising the suspicion for C7 nerve root and median nerve involvement.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 108 - Choose the correct statement regarding p53 gene: ...

    Incorrect

    • Choose the correct statement regarding p53 gene:

      Your Answer:

      Correct Answer: Li-Fraumeni syndrome predisposes to the development of sarcomas

      Explanation:

      Li-Fraumeni syndrome (LFS) is a cancer predisposition syndrome associated with the development of the following classic tumours: soft tissue sarcoma, osteosarcoma, pre-menopausal breast cancer, brain tumours, adrenocortical carcinoma (ACC), and leukaemia. LFS is diagnosed in individuals meeting established clinical criteria or in those who have a germline pathogenic variant in TP53 regardless of family cancer history.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 109 - A study is carried out to assess the efficacy of a new anti-epileptic...

    Incorrect

    • A study is carried out to assess the efficacy of a new anti-epileptic drug for children with absence seizures. The total number of the children selected for the study was 400, from which 150 children were assigned to take the new drug and 250 children were assigned in the control group. After a period of four months, only 15 children taking the new drug had a seizure compared to 100 children from the control group who had seizure. What is the correct value regarding the relative risk reduction?

      Your Answer:

      Correct Answer: 75%

      Explanation:

      Relative risk reduction (RRR) tells you by how much the treatment reduced the risk of bad outcomes relative to the control group who did not have the treatment. In the previous example, the relative risk reduction of fever and rash in the group of the children on the intervention was 40 per cent (1 – 0.6 = 0.4 or 40 per cent). RRR = (EER -CER) / CER = (0.1 – 0.4) / 0.4 = -0.75 or 75% reduction.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 110 - A 19-year-old woman is admitted with diabetic ketoacidosis (DKA). It is her fourth...

    Incorrect

    • A 19-year-old woman is admitted with diabetic ketoacidosis (DKA). It is her fourth episode in the past two months and she's known to be a type 1 diabetes mellitus patient. The doctors suspects she's non-compliant with her treatment to keep her weight down. She often self-discharges after 24 hours. What is the single most appropriate management?

      Your Answer:

      Correct Answer: Have a chat after the ward round about why she thinks her control is so bad

      Explanation:

      In many Western countries and health plans in the United States, patients have a primary care physician who acts as a formal gatekeeper for medical specialist care and thereby determines together with the patient whether or not a patient requires medical specialist care. Ideally in such systems, patients are treated in primary care if possible, and referred to medical specialist care if necessary. For the gatekeeper system to be effective, it is vital that adequate decisions are made about when and who to refer. But it is also important that referred patients comply with the referral by consulting a medical specialist. In this case, the GP should discuss with the patient the reasons why she cannot follow the treatment plan. In other words, the GP should detect why the patient is being non-compliant.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 111 - A study's objective is to find the normal reference range for IgE levels...

    Incorrect

    • A study's objective is to find the normal reference range for IgE levels in the adult population. What percentage of individuals will have IgE levels higher than 2 standard deviations from the mean, assuming that the IgE levels follow a normal distribution?

      Your Answer:

      Correct Answer: 2.30%

      Explanation:

      Normal distribution describes the spread of many biological and clinical measurements. Usually, 68.3% lies within 1 standard deviation (SD) of the mean, 95.4% lies within 2 SD of the mean and 99.7% lies within 3 SD of the mean.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 112 - Which one of the following statements regarding the normal distribution is correct? ...

    Incorrect

    • Which one of the following statements regarding the normal distribution is correct?

      Your Answer:

      Correct Answer: Mean = mode = median

      Explanation:

      Normal distribution, also known as the Gaussian distribution, is a probability distribution that is symmetric about the mean. The normal distribution has the following properties:
      – It is symmetric around the mode, the median and the mean of the distribution.
      – It is unimodal
      – The area under the curve and over the x-axis is unity (i.e. equal to one).
      – Its density has two inflection points.
      – Its density is log-concave.
      The standard deviation (SD) is a measure of how much dispersion exists from the mean. SD = square root (variance)

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 113 - Double-stranded DNA is found in which of the following cell organelles? ...

    Incorrect

    • Double-stranded DNA is found in which of the following cell organelles?

      Your Answer:

      Correct Answer: Mitochondria

      Explanation:

      Mitochondrial DNA (mtDNA) is a double-stranded molecule of 16.6 kb (Figure 1, lower panel). The two strands of mtDNA differ in their base composition, with one being rich in guanines, making it possible to separate a heavy (H) and a light (L) strand by density centrifugation in alkaline CsCl2 gradients.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 114 - A 32-year-old male has recently had a splenectomy following a motorcycle accident. He...

    Incorrect

    • A 32-year-old male has recently had a splenectomy following a motorcycle accident. He is up to date with all vaccinations which were offered as part of his childhood vaccination scheme. It is July. Which of the following vaccinations does he require in the first instance?

      Your Answer:

      Correct Answer: Pneumococcus, meningococcus type B and C, Haemophilus type B

      Explanation:

      Acquired asplenia or hyposlenia can occur following splenectomy. Hyposplenism is used to describe reduced (‘hypo-‘) splenic functioning and is associated with increased risk of sepsis from polysaccharide encapsulated bacteria. In particular, patients are at risk from Streptococcus pneumoniae, Haemophilus influenzae, and meningococcus. The risk is elevated as much as 350–fold.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 115 - You are a ST1 doctor working on a medical ward. You are struggling...

    Incorrect

    • You are a ST1 doctor working on a medical ward. You are struggling to cope with the workload and often leave the ward late. Who is the most appropriate action to take?

      Your Answer:

      Correct Answer: Speak to your consultant

      Explanation:

      Speaking to your consultant is the most appropriate first action to take in this scenario. They are best placed to be able to take action to try and amend the situation. The consultant is also ultimately responsible for patient care and hterefore have a right to know if you are struggling, as this may affect patient care.
      Arriving early and taking time off sick do not address the problem.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 116 - A 34-year-old male patient is admitted with hemisection of the spinal cord at...

    Incorrect

    • A 34-year-old male patient is admitted with hemisection of the spinal cord at the level T5, after being stabbed in the back. Which sign would you expect to see by assessing the patient's sensory function and muscle strength?

      Your Answer:

      Correct Answer: Contralateral loss of temperature, ipsilateral loss of fine touch and vibration, ipsilateral spastic paresis

      Explanation:

      Depending on the level of SCI, patients experience paraplegia or tetraplegia. Paraplegia is defined as the impairment of sensory or motor function in lower extremities. Patients with incomplete paraplegia generally have a good prognosis in regaining locomotor ability (,76% of patients) within a year. Complete paraplegic patients, however, experience limited recovery of lower limb function if their NLI is above T9. The spinothalamic tract is the one responsible for sensory information such as pain or temperature. However, it decussates at the same level the nerve root enters the spinal cord, meaning that the sensory loss will be contralateral. However, the dorsal column carries sensory fibres for fine touch and vibration and it decussates at the medulla which means that the sensory loss will be ipsilateral. The corticospinal tract is responsible for motor functions and it decussates at the medulla, meaning that the motor function loss will be ipsilateral.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 117 - A 19-year-old female is admitted with a headache, photophobia, fever and confusion. She...

    Incorrect

    • A 19-year-old female is admitted with a headache, photophobia, fever and confusion. She is managed with antibiotics. What is the mechanism of action of the most commonly used first line antibiotic class?

      Your Answer:

      Correct Answer: Inhibition of cell wall synthesis

      Explanation:

      In adults, the most common symptom of meningitis is a severe headache, occurring in almost 90% of cases of bacterial meningitis, followed by nuchal rigidity (the inability to flex the neck forward passively due to increased neck muscle tone and stiffness). Other signs commonly associated with meningitis include photophobia (intolerance to bright light) and phonophobia (intolerance to loud noises).
      In the United Kingdom empirical treatment consists of a third-generation cefalosporin such as cefotaxime or ceftriaxone. In the USA, where resistance to cefalosporins is increasingly found in streptococci, addition of vancomycin to the initial treatment is recommended. Penicillins, cephalosporins, carbapenems and monobactams all act via inhibition of cell wall synthesis.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 118 - A new study was developed to assess the benefit of omega-3 fish oils...

    Incorrect

    • A new study was developed to assess the benefit of omega-3 fish oils in patients with established ischaemic heart disease. The power of the study is equal to:

      Your Answer:

      Correct Answer: 1 - probability of making a type II error

      Explanation:

      The power of a test is defined as 1 − the probability of Type II error. The Type II error is concluding at no difference (the null is not rejected) when in fact there is a difference, and its probability is named β. Therefore, the power of a study reflects the probability of detecting a difference when this difference exists. It is also very important to medical research that studies are planned with an adequate power so that meaningful conclusions can be issued if no statistical difference has been shown between the treatments compared. More power means less risk for Type II errors and more chances to detect a difference when it exists.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 119 - A case-control study is developed to assess passive smoking as a risk factor...

    Incorrect

    • A case-control study is developed to assess passive smoking as a risk factor for the development of asthma in children. The total number of patients recruited for this study is 200. 40 out of the 200 patients report at least one parent smoking in the house when they were younger. 200 more people without asthma are recruited and 20 out of them report that at least one parent smoked in the house when they were younger. What is the odds ratio of patients with asthma having been exposed to passive smoking during their childhood?

      Your Answer:

      Correct Answer: 2.25

      Explanation:

      An odds ratio (OR) is a measure of association between an exposure and an outcome. The OR represents the odds that an outcome will occur given a particular exposure, compared to the odds of the outcome occurring in the absence of that exposure. Odds ratios are most commonly used in case-control studies, however they can also be used in cross-sectional and cohort study designs as well (with some modifications and/or assumptions). Where

      a = Number of exposed cases

      b = Number of exposed non-cases

      c = Number of unexposed cases

      d = Number of unexposed non-cases

      OR=(a/c) / (b/d) = ad/bc

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 120 - Choose the correct statement regarding interferon: ...

    Incorrect

    • Choose the correct statement regarding interferon:

      Your Answer:

      Correct Answer: Interferon-alpha and interferon-beta bind to the same type of receptor

      Explanation:

      Type I interferons (IFNs) form a network of homologous cytokines that bind to a shared, heterodimeric cell surface receptor and engage signalling pathways that activate innate and adaptive immune responses.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 121 - Which is the best source of vitamin D per average serving for a...

    Incorrect

    • Which is the best source of vitamin D per average serving for a woman with suspected Osteomalacia?

      Your Answer:

      Correct Answer: Cod liver oil

      Explanation:

      Serum vitamin D levels are influenced by sun exposure and diet. Cod liver oil is an important dietary vitamin D source in high-latitude countries like Norway where there is no sun-induced vitamin D production during the winter. 14 Norwegian Health Authorities have recommended 5 ml of cod liver oil daily (400 IU of vitamin D) for more than 60 years to prevent diseases like rickets, formerly more prevalent in areas with little access to vitamin D-rich fatty fish.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 122 - A 24-year-old male is admitted with worsening shortness of breath with signs of...

    Incorrect

    • A 24-year-old male is admitted with worsening shortness of breath with signs of left ventricular failure. He has a known genetic condition. On examination, there is an ejection systolic murmur loudest over the aortic area radiating to the carotids, bibasal crepitations and pitting oedema to the knees bilaterally. On closer inspection of the patient, you note a wide vermillion border, small spaced teeth and a flat nasal bridge. The patient also has a disinhibited friendly demeanour. What is the likely precipitating valvular issue?

      Your Answer:

      Correct Answer: Supravalvular aortic stenosis

      Explanation:

      Supravalvular aortic stenosis, is associated with a condition called William’s syndrome.
      William’s syndrome is an inherited neurodevelopmental disorder caused by a microdeletion on chromosome 7. The most common symptoms of Williams syndrome are heart defects and unusual facial features. Other symptoms include failure to gain weight appropriately in infancy (failure to thrive) and low muscle tone. Individuals with Williams syndrome tend to have widely spaced teeth, a long philtrum, and a flattened nasal bridge.
      Most individuals with Williams syndrome are highly verbal relative to their IQ, and are overly sociable, having what has been described as a cocktail party type personality.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 123 - Which of the following phases determines the length of the cell cycle? ...

    Incorrect

    • Which of the following phases determines the length of the cell cycle?

      Your Answer:

      Correct Answer: G1

      Explanation:

      The duration of these cell cycle phases varies considerably in different kinds of cells. For a typical rapidly proliferating human cell with a total cycle time of 24 hours, the G1 phase might last about 11 hours, S phase about 8 hours, G2 about 4 hours, and M about 1 hour. The proliferation of most animal cells is similarly regulated in the G1 phase of the cell cycle. In particular, a decision point in late G1, called the restriction point in animal cells, is the point at which the cell becomes committed to the cell cycle and after which extracellular proliferation stimulants are no longer required.. Although the proliferation of most cells is regulated primarily in G1, some cell cycles are instead controlled principally in G2.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 124 - A literature review of a number of studies was conducted to assess the...

    Incorrect

    • A literature review of a number of studies was conducted to assess the potential efficacy of a new drug, which may reduce the chance of patients with chronic kidney disease (CKD) developing gout. In one study 120 out of 1,200 patients receiving the new drug developed gout. The total number of the patients were 2,000 and the remaining 800 individuals received a placebo. From the patients that had received the placebo, 200 developed gout. What is the absolute risk reduction of developing gout?

      Your Answer:

      Correct Answer: 15%

      Explanation:

      Absolute risk reduction (ARR) – also called risk difference (RD) – is the most useful way of presenting research results to help your decision-making. Absolute risk reduction = (Control event rate) – (Experimental event rate) = 0.15 = 15%

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 125 - A cohort study is being designed to look at the relationship between smoking...

    Incorrect

    • A cohort study is being designed to look at the relationship between smoking and prostate cancer. What is the usual outcome measure in a cohort study?

      Your Answer:

      Correct Answer: Relative risk

      Explanation:

      A cohort study is a particular form of longitudinal study that samples a cohort (a group of people who share a defining characteristic, typically those who experienced a common event in a selected period, such as birth or graduation), performing a cross-section at intervals through time.
      The relative risk (RR) or risk ratio is the ratio of the probability of an outcome in an exposed group to the probability of an outcome in an unexposed group. Relative risk is used in the statistical analysis of the data of experimental, cohort and cross-sectional studies, to estimate the strength of the association between treatments or risk factors, and outcomes.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 126 - Choose the hormone secreted only by the adrenal medulla: ...

    Incorrect

    • Choose the hormone secreted only by the adrenal medulla:

      Your Answer:

      Correct Answer: Adrenaline

      Explanation:

      The major endocrine functions of adrenal gland are to produce catecholamines and steroids. Catecholamine, synthesized by the adrenal medulla, is responsible for blood pressure and blood flow regulation whereas steroids produced by the cortex control energy and water homeostasis and immune responses. Glucocorticoids, a major group of adrenal steroids, have a stimulatory effect on catecholamine synthesis in the medulla.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 127 - A 13-year-old girl presents with a swollen left knee following a fall. Her...

    Incorrect

    • A 13-year-old girl presents with a swollen left knee following a fall. Her parents state she suffers from haemophilia and has been treated for a right-sided haemarthrosis previously. What other condition is she most likely to have?

      Your Answer:

      Correct Answer: Turner's syndrome

      Explanation:

      Haemophilia is a X-linked recessive disorder. In X-linked recessive inheritance only males are affected. An exception to this seen in examinations are patients with Turner’s syndrome, who are affected due to only having one X chromosome. X-linked recessive disorders are transmitted by heterozygote females (carriers) and male-to-male transmission is not seen. Affected males can only have unaffected sons and carrier daughters.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 128 - Supplementation of which one of the following might help a patient diagnosed with...

    Incorrect

    • Supplementation of which one of the following might help a patient diagnosed with homocystinuria?

      Your Answer:

      Correct Answer: Pyridoxine

      Explanation:

      In general, the aim is to keep the homocysteine (Hcy) concentration as close to normal as possible. In patients who are fully-responsive to pyridoxine, standard doses can lead to tHcy levels below 50 μmol/L (and sometimes within the normal range). Some patients who are partially-responsive to pyridoxine may be able to achieve a tHcy level below 50 μmol/L if they are also on a low-Met diet; for others it is not a realistic goal.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 129 - A 69-year-old woman is admitted with confusion. She's known to have a history...

    Incorrect

    • A 69-year-old woman is admitted with confusion. She's known to have a history of multiple myeloma. Blood exam reveals the following: Na+ = 147 mmol/l, K+ = 4.7 mmol/l, Urea = 14.2 mmol/l, Creatinine = 102 μmol/l, Adjusted calcium = 3.9 mmol/l. What is the single most appropriate management?

      Your Answer:

      Correct Answer: IV 0.9% saline

      Explanation:

      NICE guidelines on hypercalcemia recommend that maintaining good hydration equals drinking 3-4 L of fluid/day, provided there are no contraindications. A low calcium diet is not necessary because intestinal absorption of calcium is reduced. The patient should avoid any other drugs or vitamins that could worsen the hypercalcemia. Mobilization is encouraged and any symptoms of hypercalcemia should be reported.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 130 - A 62year-old manpresents with exertional chest pain and is found to have extensive...

    Incorrect

    • A 62year-old manpresents with exertional chest pain and is found to have extensive coronary artery disease on angiogram. Which of the following cell types is most implicated in the development of coronary artery plaques?

      Your Answer:

      Correct Answer: Macrophages

      Explanation:

      An atheroma is an accumulation of degenerative material in the tunica intima (inner layer) of artery walls. The material consists of (mostly) macrophage cells, or debris, containing lipids (cholesterol and fatty acids), calcium and a variable amount of fibrous connective tissue.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 131 - Choose the karyotype associated with short stature: ...

    Incorrect

    • Choose the karyotype associated with short stature:

      Your Answer:

      Correct Answer: 45,XO

      Explanation:

      Turner syndrome (TS) is one of the most common genetic disorders; occurs with an incidence of I: 2,500 female live births. It results from complete or partial chromosome X monosomy. TS is associated with abnormalities of the X chromosome and characteristic clinical features of short stature, gonadal dysgenesis, sexual developmental deficiencies, cardiac and/or renal defects, webbed neck, low-set ears, skeletal deformities including cubitus valgus, a propensity to ear infections and hearing deficits.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 132 - A 58-year-old woman has multiple non-healing leg ulcers. She reports feeling unwell for...

    Incorrect

    • A 58-year-old woman has multiple non-healing leg ulcers. She reports feeling unwell for several months. Examination findings include a normal blood pressure, pulse 90 bpm, pale conjunctivae and poor dentition associated with bleeding gums. What is the most likely underlying diagnosis?

      Your Answer:

      Correct Answer: Vitamin C deficiency

      Explanation:

      Severe vitamin C deficiency results in scurvy, a disorder characterized by hemorrhagic manifestations and abnormal osteoid and dentin formation.
      Vitamin C plays a role in collagen, carnitine, hormone, and amino acid formation. It is essential for bone and blood vessel health and wound healing and facilitates recovery from burns. Vitamin C is also an antioxidant, supports immune function, and facilitates the absorption of iron (see table Sources, Functions, and Effects of Vitamins).
      Dietary sources of vitamin C include citrus fruits, tomatoes, potatoes, broccoli, strawberries, and sweet peppers. (See also Overview of Vitamins.)

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 133 - Which one of the following congenital infections is most characteristically associated with chorioretinitis?...

    Incorrect

    • Which one of the following congenital infections is most characteristically associated with chorioretinitis?

      Your Answer:

      Correct Answer: Toxoplasma gondii

      Explanation:

      The common congenital infections encountered are rubella, toxoplasmosis and cytomegalovirus. Cytomegalovirus is the most common congenital infection in the UK. Maternal infection is usually asymptomatic.
      Congenital toxoplasmosis is associated with fetal death and abortion, and in infants, it is associated with neurologic deficits, neurocognitive deficits, and chorioretinitis.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 134 - A 54-year-old man is found collapsed in the street and is brought to...

    Incorrect

    • A 54-year-old man is found collapsed in the street and is brought to the A&E. The results from the blood tests reveal Calcium = 1.62mmol/l and Albumin = 33g/l. The man is known to have a history of alcoholic liver disease. Which of the following is the best management regarding his calcium levels?

      Your Answer:

      Correct Answer: 10ml of 10% calcium gluconate over 10 minutes

      Explanation:

      Acute, symptomatic hypocalcaemia is treated with 10ml of 10% calcium gluconate over 10 minutes.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 135 - A 24-year-old man was hit on the lateral aspect of his head by...

    Incorrect

    • A 24-year-old man was hit on the lateral aspect of his head by a high velocity cricket ball and lost consciousness immediately. Paramedics found him to have a Glasgow coma score of 15 but take him to the A&E for further investigation. His Glasgow coma score on examination in the A&E is 13 (M5, V4, E4) and he has anterograde and retrograde amnesia to recent events. The doctors arrange an urgent CT scan. Which clinical sign would be most concerning if present?

      Your Answer:

      Correct Answer: Bradycardia

      Explanation:

      Intracranial pressure (ICP) is a complex brain modality that determines cerebral perfusion pressure (CPP), which is the difference between arterial blood pressure (ABP), and ICP. Raised ICP reduces CPP and blood delivery to the brain. This jeopardizes cerebral function and organismal survival in many species. A massive rise in ICP is also known to produce an increase in ABP, bradycardia and respiratory irregularities termed Cushing response. This mechanism is generally considered to be an agonal and terminal event occurring in extreme condition of brainstem ischaemia leading to a sympatho-adrenal response.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 136 - A 13-year-old girl is brought by her mother to the A&E with breathlessness,...

    Incorrect

    • A 13-year-old girl is brought by her mother to the A&E with breathlessness, fatigue and palpitations. Anamnesis does not reveal any syncope or chest pain in the past. on the other hand, these symptoms were present intermittently for a year. Clinical examination reveals a pan-systolic murmur associated with giant V waves in the jugular venous pulse. Chest auscultation and resting ECG are normal. 24 hour ECG tape shows a short burst of supraventricular tachycardia. What is the most probable diagnosis?

      Your Answer:

      Correct Answer: Ebstein's anomaly

      Explanation:

      Ebstein’s anomaly is characterised by apical displacement and adherence of the septal and posterior leaflets of the tricuspid valve to the underlying myocardium, thereby displacing the functional tricuspid orifice apically and dividing the right ventricle into two portions. The main haemodynamic abnormality leading to symptoms is tricuspid valve incompetence. The clinical spectrum is broad; patients may be asymptomatic or experience right-sided heart failure, cyanosis, arrhythmias and sudden cardiac death (SCD). Many Ebstein’s anomaly patients have an interatrial communication (secundum atrial septal defect (ASD II) or patent foramen ovale). Other structural anomalies may also be present, including a bicuspid aortic valve (BAV), ventricular septal defect (VSD), and pulmonary stenosis. The morphology of the tricuspid valve in Ebstein anomaly, and consequently the clinical presentation, is highly variable. The tricuspid valve leaflets demonstrate variable degrees of failed delamination (separation of the valve tissue from the myocardium) with fibrous attachments to the right ventricular endocardium.
      The displacement of annular attachments of septal and posterior (inferior) leaflets into the right ventricle toward the apex and right ventricular outflow tract is the hallmark finding of Ebstein anomaly.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 137 - Choose the correct statement regarding standard polymerase chain reaction: ...

    Incorrect

    • Choose the correct statement regarding standard polymerase chain reaction:

      Your Answer:

      Correct Answer: A thermostable DNA polymerase is required

      Explanation:

      In the PCR, DNA amplification is performed by thermostable enzymes; invariably either family A DNA polymerases from thermophilic and hyperthermophilic Bacteria or family B DNA polymerases from hyperthermophilic Archaea. Family Y DNA polymerase from the hyperthermophilic archaeon Sulfolobus solfataricus, Sso-polY, is also an enzyme marketed for PCR, but with specialist applications. Each thermostable DNA polymerases has different characteristics and to achieve optimal results, the choice of a PCR enzyme depends on the application itself.

    • This question is part of the following fields:

      • Clinical Sciences
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  • Question 138 - A 52-year-old man presents with numbness and tingling in his left hand. On...

    Incorrect

    • A 52-year-old man presents with numbness and tingling in his left hand. On examination he has weakness of elbow extension, metacarpophalangeal joint flexion and extension and distal interphalangeal joint flexion. All other movements and reflexes are normal. Sensation is normal apart from reduced pin-prick sensation over the medial aspect of the hand. An MRI scan of the cervical spine is performed due to suspicion of a nerve lesion. Which of the following pathologies is most likely to be found on the scan based on the clinical findings?

      Your Answer:

      Correct Answer: Disc herniation between C7 and T1

      Explanation:

      The C8 nerve forms part of the radial and ulnar nerves via the brachial plexus, and therefore has motor and sensory function in the upper limb. It originates from the spinal column from below the cervical vertebra 7 (C7).
      The C8 nerve receives sensory afferents from the C8 dermatome. This consists of all the skin on the little finger, and continuing up slightly past the wrist on the palmar and dorsal aspects of the hand and forearm.
      The other options available correspond to the C6 or C7 roots and these are unaffected as evidenced by normal elbow flexion and thumb sensation (C6) and normal sensation over the middle finger (C7). Elbow extension is weak as it has roots from both C7 and C8 and so cannot be used alone to decide between the two levels clinically.
      The C8 nerve contributes to the motor innervation of many of the muscles in the trunk and upper limb. Its primary function is the flexion of the fingers, and this is used as the clinical test for C8 integrity, in conjunction with the finger jerk reflex.

      Trunk:
      – Pectoralis major – Medial and lateral pectoral nerves (C5, C6, C7, C8, T1)
      – Pectoralis minor – Medial pectoral nerve (C5, C6, C7,C8, T1)
      – Latissimus dorsi – Thoracodorsal nerve (C6, C7, C8)
      Upper arm:
      – Triceps brachii – Radial nerve (C6, C7,C8)
      Forearm
      – Flexor carpi ulnaris – Ulnar nerve (C7, C8, T1)
      – Palmaris longus – Median nerve (C7,C8)
      – Flexor digitorum superficialis – Median nerve (C8, T1)
      – Flexor digitorum profundus – Median and Ulnar nerves (C8, T1)
      – Flexor pollicis longus – Median nerve (C7,C8)
      – Pronator quadratus – Median nerve (C7,C8)
      – Extensor carpi radialis brevis – Deep branch of the radial nerve (C7,C8)
      – Extensor digitorum – Posterior interosseous nerve (C7,C8)
      – Extensor digiti minimi – Posterior interosseous nerve (C7,C8)
      – Extensor carpi ulnaris – Posterior interosseous nerve (C7,C8)
      – Anconeus – Radial nerve (C6, C7,C8)
      – Abductor pollicis longus – Posterior interosseous nerve (C7,C8)
      – Extensor pollicis brevis – Posterior interosseous nerve (C7,C8)
      – Extensor pollicis longus – Posterior interosseous nerve (C7,C8)
      – Extensor indicis – Posterior interosseous nerve (C7,C8)
      Hand
      – Palmaris brevis – Superficial branch of ulnar nerve (C8, T1)
      – Dorsal interossei – Deep branch of ulnar nerve (C8, T1)
      – Palmar interossei – Deep branch of ulnar nerve (C8, T1)
      – Adductor pollicis – Deep branch of ulnar nerve (C8, T1)
      – Lumbricals – Deep branch of ulnar, Digital branches of median nerve
      – Opponens pollicis – Recurrent branch of median nerve (C8, T1)
      – Abductor pollicis brevis – Recurrent branch of median nerve (C8, T1)
      – Flexor pollicis brevis – Recurrent branch of median nerve (C8, T1)
      – Opponens digiti minimi – Deep branch of ulnar nerve (C8, T1)
      – Abductor digiti minimi – Deep branch of ulnar nerve (C8, T1)
      – Flexor digiti minimi brevis – Deep branch of ulnar nerve (C8, T1)

    • This question is part of the following fields:

      • Clinical Sciences
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