00
Correct
00
Incorrect
00 : 00 : 00
Session Time
00 : 00
Average Question Time ( Secs)
  • Question 1 - Which of the following options will likely play a major role in falling...

    Correct

    • Which of the following options will likely play a major role in falling coronary blood flow?

      Your Answer: Intracoronary artery infusion of endothelin-1

      Explanation:

      Endothelin-1 is considered as a powerful coronary vasoconstrictor, produced by the endothelium. It acts to counter the effects of Nitric oxide (NO).
      Neuropeptide-Y, angiotensin1, cocaine, vasopressin, and nicotine are some other coronary vasoconstrictors.

      Chronotrophy and inotrophy occur after the activation of sympathetic nerve fibres, which in turn results in increasing the myocardial oxygen consumption, leading to increased coronary blood flow via local metabolic processes.

      An alpha-receptor mediated coronary vasoconstrictor effect is also initiated that usually competes with vasodilation, resulting in decreased coronary vascular resistance. Some of the other dilators include hydrogen ions, CO2, potassium, and lactic acid. The action of endothelial NO synthase (eNOS) on L-arginine results in the formation of NO. This messenger also plays a vital role in the regulation of coronary blood flow via vasodilation, inhibition of platelet aggression, and decreasing vascular resistance.
      Adenosine is considered as purine nucleoside that forms after the breakdown of adenosine triphosphate (ATP). Adenosine binds to adenosine type 2A (A2A) receptors in coronary vascular smooth muscles. These are coupled to the Gs protein. This mechanism leads to hyperpolarisation of muscle cells, resulting in relaxation and increased coronary blood flow.

      GTN is an veno and arteriolar dilator, which behaves as pro-drug with NO.

    • This question is part of the following fields:

      • Pathophysiology
      70.8
      Seconds
  • Question 2 - A 42 year old man came to the out-patient department with attacks of...

    Correct

    • A 42 year old man came to the out-patient department with attacks of facial pain. Upon further questioning, he reported that the pain was intermittent, often occurring spontaneously. The quality of the pain was sharp, and severity was moderate to moderately severe. The pain was non-radiating, and often involved the left maxillary and mandibular areas. Other medical information of the patient, such as allergies and co-morbidities, were unremarkable. Which of the following is the most probable diagnosis of the patient?

      Your Answer: Trigeminal neuralgia

      Explanation:

      Trigeminal neuralgia is characterized by excruciating paroxysms of pain in the lips, gums, cheek, or chin and, very rarely, in the distribution of the fifth nerve. The pain seldom lasts more than a few seconds or a minute or two but may be so intense that the patient winces, hence the term tic. The paroxysms, experienced as single jabs or clusters, tend to recur frequently, both day and night, for several weeks at a time. They may occur spontaneously or with movements of affected areas evoked by speaking, chewing, or smiling. Another characteristic feature is the presence of trigger zones, typically on the face, lips, or tongue, that provoke attacks; patients may report that tactile stimuli – e.g., washing the face, brushing the teeth, or exposure to a draft of air – generate excruciating pain. An essential feature of trigeminal neuralgia is that objective signs of sensory loss cannot be demonstrated on examination.

      Trigeminal neuralgia is relatively common, with an estimated annual incidence of 4€“8 per 100,000 individuals. Middle-aged and elderly persons are affected primarily, and ,60% of cases occur in women. Onset is typically sudden, and bouts tend to persist for weeks or months before remitting spontaneously. Remissions may be long-lasting, but in most patients, the disorder ultimately recurs.

      An ESR or CRP is indicated if temporal arteritis is suspected. In typical cases of trigeminal neuralgia, neuroimaging studies are usually unnecessary but may be valuable if MS is a consideration or in assessing overlying vascular lesions in order to plan for decompression surgery.

    • This question is part of the following fields:

      • Pathophysiology
      29
      Seconds
  • Question 3 - A 40-year old farmer came into the emergency room with a chief complaint...

    Correct

    • A 40-year old farmer came into the emergency room with a chief complaint of 4 episodes of non-bloody diarrhoea. This was associated with frequent urination, vomiting and salivation. History also revealed frequent use of insecticides. Upon physical examination, there was miosis and bradycardia. Given the different types of bonds, which is the most likely bond formed between insecticide poisoning and receptors?

      Your Answer: Covalent

      Explanation:

      Organophosphate poisoning occurs most often due to accidental exposure to toxic amounts of pesticides. Signs and symptoms include diarrhoea, urination, miosis, bradycardia, emesis, lacrimation, lethargy and salivation.

      Organophosphates are classified as indirect acting cholinomimetics, and their mode of action involves: (1) the inhibition of acetylcholinesterase (AChE) by forming a stable covalent bond on the active site serine; and, (2) amplification of endogenously release acetylcholine (ACh), hence the clinical manifestation.

      There are 4 types of bonds or interactions: ionic, covalent, hydrogen bonds, and van der Waals interactions. Ionic and covalent bonds are strong interactions that require a larger energy input to break apart. When an element donates an electron from its outer shell, a positive ion is formed. The element accepting the electron is now negatively charged. Because positive and negative charges attract, these ions stay together and form an ionic bond. Covalent bonds form when an electron is shared between two elements and are the strongest and most common form of chemical bond in living organisms. Covalent bonds form between the elements that make up the biological molecules in our cells. Unlike ionic bonds, covalent bonds do not dissociate in water.

      When polar covalent bonds containing a hydrogen atom form, the hydrogen atom in that bond has a slightly positive charge. This is because the shared electron is pulled more strongly toward the other element and away from the hydrogen nucleus. Because the hydrogen atom is slightly positive, it will be attracted to neighbouring negative partial charges. When this happens, a weak interaction occurs between the slightly positive charge of the hydrogen atom of one molecule and the slightly negative charge of the other molecule. This interaction is called a hydrogen bond.

    • This question is part of the following fields:

      • Pathophysiology
      21.7
      Seconds
  • Question 4 - The liver plays a major role in drug metabolism. Which of the following...

    Incorrect

    • The liver plays a major role in drug metabolism. Which of the following liver cells is most important in phase I of drug metabolism?

      Your Answer: Periportal cells

      Correct Answer: Centrilobular cells

      Explanation:

      The metabolism of drugs in the liver occurs in 3 phases

      Phase I: This involves functionalization reactions, which are of 3 types, namely hydrolysis, oxidation and reduction reactions catalysed by the cytochrome P450 (CYP) enzymes.

      Phase II: This involves conjugation or acetylation reactions. The goal is to create water soluble metabolites that can be excreted from the body.

      The liver is the second largest organ. It’s smallest functional unit is the acinus which is divided into 3 zones:

      Zone I (periportal): This zone receives the largest amount of oxygen supply as it is the closest to the blood vessels. It is the site of plasma protein synthesis.

      Zone II (mediolobular): This is located between the portal triad and central vein.

      Zone III (centrilobular): This is closest to the central vein and receives the least amount of oxygen supply.

      Kupffer cells are specialized macrophages found in the periportal zone of the liver, and function to remove foreign particles and breakdown red blood cells via phagocytosis.

      Ito cells are fat-storing liver cells found in the space of Disse. Their function is to take-uo, store and secrete retinoids, as well as manufacture and release proteins that make up the extracellular matrix.

    • This question is part of the following fields:

      • Pathophysiology
      10.6
      Seconds
  • Question 5 - A 27-year-old woman is admitted to the emergency room with an ectopic pregnancy...

    Correct

    • A 27-year-old woman is admitted to the emergency room with an ectopic pregnancy that has ruptured. The following is a description of the clinical examination: Anxious, Capillary refill time of 3 seconds, Cool peripheries, Pulse 120 beats per minute, Blood pressure 120/95 mmHg, Respiratory rate 22 breaths per minute. Which of the following is the most likely explanation for these clinical findings?

      Your Answer: Reduction in blood volume of 15-30%

      Explanation:

      The following is the Advanced Trauma Life Support (ATLS) classification of haemorrhagic shock:

      Class I haemorrhage:
      It has blood loss up to 15%. There is very less tachycardia, and no changes in blood pressure, RR or pulse pressure. Usually, fluid replacement is not required.

      Class II haemorrhage:
      It has 15-30% blood loss, equivalent to 750 – 1500 ml. There is tachycardia, tachypnoea and a decrease in pulse pressure. Patient may be frightened, hostile and anxious. It can be stabilised by crystalloid and blood transfusion.

      Class III haemorrhage:
      There is 30-40% blood loss. It portrays inadequate perfusion, marked tachycardia, tachypnoea, altered mental state and fall in systolic pressure. It requires blood transfusion.

      Class IV haemorrhage:
      There is > 40% blood volume loss. It is a preterminal event, and the patient will die in minutes. It portrays tachycardia, significant depression in systolic pressure and pulse pressure, altered mental state, and cold clammy skin. There is need for rapid transfusion and surgical intervention.

    • This question is part of the following fields:

      • Physiology
      18.6
      Seconds
  • Question 6 - A 60 year old non insulin dependent diabetic on metformin undergoes hip arthroscopy...

    Correct

    • A 60 year old non insulin dependent diabetic on metformin undergoes hip arthroscopy under general anaesthesia. Her preoperative blood glucose is 6.5mmol/L. Anaesthesia is induced with 200 mg propofol and 100 mcg fentanyl and maintained with sevoflurane and air/oxygen mixture. she is given 8 mg dexamethasone, 40 mg parecoxib, 1 g paracetamol and 500 mL Hartmann's solution Intraoperatively. The procedure took thirty minutes and her blood glucose in recovery is 14 mmol/L. What is the most likely cause for her rise in blood sugar?

      Your Answer: Stress response

      Explanation:

      A significant early feature of the metabolic response to trauma and surgery is hyperglycaemia. It is due to an increased glucose production and decreased glucose utilisation bought on by neuroendocrine stimulation. Catecholamines, Growth hormone, ACTH and cortisol, and Glucagon are all increased.

      There is also a decreased insulin sensitivity peripherally and an inhibition of insulin production from the beta cells of the pancreas. These changes lead to hyperglycaemia.

      The stress response to endoscopic surgery will only be prevented with use of high dose opioids or central neuraxial block at anaesthesia.
      To reduce the risk of inducing hyperchloremic acidosis, Ringer’s lactate/acetate or Hartmann’s solution is preferred to 0.9% sodium chloride as routine maintenance fluids.

      Though it has been suggested that administration of Hartmann’s solution to patients with type 2 diabetes leads to hyperglycaemia, one Litre of Hartmann’s solution would yield a maximum of 14.5 mmol of glucose. A rapid infusion of this volume would increase the plasma glucose by no more than 1 mmol/L..

      Dexamethasone, a glucocorticoid, produces hyperglycaemia by stimulating gluconeogenesis . Glucocorticoids are agonists of intracellular glucocorticoid receptors. Their effects are mainly mediated via altered protein synthesis via gene transcription and so the onset of action is slow. The onset of action of dexamethasone is about one to four hours and therefore would NOT contribute to the hyperglycaemia in this patient in the time given.

      0.9% Normal saline with or without adrenaline is the usual irrigation fluid. With this type of surgery, systemic absorption is unlikely to occur.

      Fentanyl is not likely the primary cause of hyperglycaemia in this patient. In high doses (50 mcg/Kg) it has been shown to reduce the hyperglycaemic responses to surgery.

    • This question is part of the following fields:

      • Pathophysiology
      30.2
      Seconds
  • Question 7 - Which of the following is not used in the treatment of Neuroleptic Malignant...

    Incorrect

    • Which of the following is not used in the treatment of Neuroleptic Malignant Syndrome?

      Your Answer: Dantrolene

      Correct Answer: Olanzapine

      Explanation:

      The neuroleptic malignant syndrome (NMS) is a rare complication in response to neuroleptic or antipsychotic medication.

      The main features are:
      – Elevated creatinine kinase
      – Hyperthermia and tachycardia
      – Altered mental state
      – Increased white cell count
      – Insidious onset over 1-3 days
      – Extrapyramidal dysfunction (muscle rigidity, tremor, dystonia)
      – Autonomic dysfunction (Labile blood pressure, sweating, salivation, urinary incontinence)

      Management is supportive of ICU care, anticholinergic drugs, increasing dopaminergic activity with Amantadine, L-dopa, and dantrolene, and non- depolarising neuromuscular blockade drugs.

      Since Olanzapine is a potential cause of NMS it is not a treatment.

    • This question is part of the following fields:

      • Pharmacology
      16.7
      Seconds
  • Question 8 - Which of the following is correct regarding correlation? ...

    Correct

    • Which of the following is correct regarding correlation?

      Your Answer: Complete absence of correlation is expressed by a value of 0

      Explanation:

      In statistical terms, correlation is used to denote association between two quantitative variables.

      The degree of association is measured by a correlation coefficient, denoted by r. The correlation coefficient is measured on a scale that varies from + 1 through 0 to €“ 1. Complete correlation between two variables is expressed by either + 1 or -1. When one variable increases as the other increases the correlation is positive; when one decreases as the other increases it is negative. Complete absence of correlation is represented by 0.

      The two methods are not synonymous as correlation measures the degree of relationship between two variables whereas regression analysis is about how one variable affects another or what changes it has on the other variable. Both are also shown by a different graphical representation.

    • This question is part of the following fields:

      • Statistical Methods
      13.1
      Seconds
  • Question 9 - A 4-year-old boy with status epilepticus was brought to ER and has already...

    Correct

    • A 4-year-old boy with status epilepticus was brought to ER and has already received two doses of intravenous lorazepam but is still continuing to have seizures. Which of the following drug would be best for his treatment?

      Your Answer: Phenytoin 20 mg/kg IV

      Explanation:

      When the convulsion lasts for five or more than five minutes, or if there are recurrent episodes of convulsions in a 5 minute period without returning to the baseline, it is termed as Status Epilepticus.
      The first priority in the patient with seizures is maintaining the airway, breathing, and circulation.

      Guideline for the management of Status Epilepticus in children by Advanced Life Support Group is as follow:

      Step 1 (Five minutes after the start of seizures):

      If intravascular access is available start treatment with lorazepam 0.1 mg/kg IV
      If no intravascular access then give buccal midazolam 0.5 mg/kg or rectal diazepam 0.5 mg/kg.

      Step 2 (Ten minutes after the start of seizure):

      If the convulsions continue then a second dose of benzodiazepine should be given. Senior should be called on-site and phenytoin should be prepared.
      No more than two doses or benzodiazepines should be given (including any doses given before arrival at the hospital)
      If still no IV access then obtain intraosseous access (IO).

      Step 3 (Ten minutes after step 2)

      Senior help along with anaesthetic/ICU help should be sought
      Phenytoin 20 mg/kg IV over 20 minutes
      If the seizure stops before the full dose of phenytoin is given then the infusion should be completed as this provides up to 24 hours of anticonvulsant effect
      In children already receiving phenytoin as treatment for epilepsy then an alternative is phenobarbitone 20 mg/kg IV over five minutes
      Once the phenytoin is started, senior staff may wish to give rectal paraldehyde 0.4 mg/kg although this is no longer included in the routine algorithm recommended by APLS.

      Step 4 (20 minutes after step 3)

      If 20 minutes after starting phenytoin the child remains in status epilepticus then rapid sequence induction of anaesthesia with thiopentone and a short acting paralysing agent is needed and the child transferred to paediatric intensive care.

    • This question is part of the following fields:

      • Pathophysiology
      14.9
      Seconds
  • Question 10 - For a rapid sequence induction of anaesthesia, you are pre-oxygenating a patient using...

    Incorrect

    • For a rapid sequence induction of anaesthesia, you are pre-oxygenating a patient using 100% oxygen and a fresh gas flow equal to the patient's minute ventilation. Which would be the most suitable choice of anaesthetic breathing system in this situation?

      Your Answer: Mapleson D system

      Correct Answer: Mapleson A system

      Explanation:

      The Mapleson A (Magill) and coaxial version of the Mapleson A system (Lack circuit) are more efficient for spontaneous breathing than any of the other Mapleson circuits. The fresh gas flow (FGF) required to prevent rebreathing is slightly greater than the alveolar minute ventilation (4-5 litres/minute). This is delivered to the patient through the outer coaxial tube and exhaust gases are moved to the scavenging system through the inner tube. In the Lack circuit, the expiratory valve is located close to the common gas outlet away from the patient end. This is the main advantage of the Lack circuit over the Mapleson A circuit.

      The Mapleson E circuit is a modification of the Ayres T piece and the FGF required to prevent rebreathing is 1.5-2 times the patient’s minute volume.

      The Bain circuit is the coaxial version of the Mapleson D circuit.

      The FGF for spontaneous respiration to avoid rebreathing is 160-200 ml/kg/minute.

      The FGF for controlled ventilation to avoid rebreathing is 70-100 ml/kg/min.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      16
      Seconds
  • Question 11 - Which of the following statements is true about oxygen face masks? ...

    Incorrect

    • Which of the following statements is true about oxygen face masks?

      Your Answer: In healthy patients, the peak inspiratory flow rate rarely exceeds 15 litres per minute during normal tidal ventilation

      Correct Answer: The oxygen concentration delivered by high air flow oxygen enrichment devices is not dependent on the respiratory pattern of the patient

      Explanation:

      The normal peak inspiratory flow in healthy individuals is 20-30 L/min during each normal tidal ventilation. This is expected to increase with greater respiratory rate and deeper inspiration.

      Face masks are used to facilitate the delivery of oxygen from a breathing system to a patient. Face masks can be divided into two types: fixed performance or variable performance devices.

      In fixed performance devices (also known as high air flow oxygen enrichment or HAFOE), fixed inspired oxygen concentration is delivered to the patent, independent and greater than that of the patient’s peak inspiratory flow rate (PIFR). No random entrainment is expected to occur at the time of PIFR, hence, the oxygen concentration in HAFOE devices is not dependent on the patient’s respiratory pattern.

      Moreover, in HAFOE masks, the concentration of oxygen at a given oxygen flow rate is determined by the size of the constriction; a device with a greater entrainment aperture delivers a lower oxygen concentration. Therefore, a 40% Venturi device will have lesser entrainment aperture when compared to a 31% Venturi. Venturi masks allow relatively fixed concentrations of supplemental oxygen to be inspired e.g. 24%, 28%, 31%, 35%, 40% and 60% oxygen. These are colour coded and marked with the recommended oxygen flow rate.

      Variable performance devices deliver variable inspired oxygen concentration to the patient, and is dependent on the PIFR. The PIFR can often exceed the flow rate at which oxygen or an oxygen/air mixture is supplied by the device, depending on a patient’s inspiratory effort. In addition, these masks allow expired air to be released through the holes in the sides of the mask. Thus, with increased respiratory rate, rebreathing of alveolar gas from inside the mask may occur.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      62.8
      Seconds
  • Question 12 - A survey aimed at finding out mean glucose level in individuals that took...

    Correct

    • A survey aimed at finding out mean glucose level in individuals that took antipsychotics medicines was conducted. The results were as follows: Mean Value: 7mmol/L, Standard Deviation: 6mmol/L, Sample Size: 9, Standard Error: 2mmol/L. For a confidence interval of 95%, which of the option presents the correct range up to the nearest value?

      Your Answer: 3-11 mmol/L

      Explanation:

      Key Point: While finding out confidence intervals, standard errors are used. Standard error and Standard deviation are two distinct entities and should not be confused.

      For 99.7% confidence interval, you can find the range as follows:

      Multiply the standard error by 3.

      Subtract the answer from mean value to get the lower limit.

      Add the answer obtained in step 1 from the mean value to get the upper limit.

      The range turns out to be 1-13 mmol/L.

      For a confidence interval of 68%, multiply the standard error with 1 and repeat the process. The range found for this interval is 3-11 mmol/L.

      For a 95% confidence interval. Standard Error is multiplied by 1.96 which gives us the limit ranging from 3.08 to 10.92 mmol/L which could be approximated to 3-11 mmol/L.

    • This question is part of the following fields:

      • Statistical Methods
      24.3
      Seconds
  • Question 13 - Considering research studies, which of the following is considered as a limitation of...

    Correct

    • Considering research studies, which of the following is considered as a limitation of the Delphi method?

      Your Answer: Potential low response rates

      Explanation:

      The Delphi technique was developed in the 1950s and is a widely used and accepted method for achieving convergence of opinion concerning real-world knowledge solicited from experts within certain topic areas. Choosing the appropriate subjects is the most important step in the entire process because it directly relates to the quality of the results generated, despite this, there is no exact criterion currently listed in the literature concerning the selection of Delphi participants.

      Therefore, due to the potential scarcity of qualified participants and the relatively small number of subjects used in a Delphi study, the ability to achieve and maintain an ideal response rate can either ensure or jeopardize the validity of a Delphi study.

    • This question is part of the following fields:

      • Statistical Methods
      10.2
      Seconds
  • Question 14 - Which of the following is true when testing for statistical significance? ...

    Correct

    • Which of the following is true when testing for statistical significance?

      Your Answer: The probability associated with a type I error is the significance level

      Explanation:

      The null hypothesis states that there is no significant difference between two groups.

      The alternative hypothesis states that there is a significant difference between two groups.

      A type I error (false positive) occurs when a null hypothesis is rejected when it should be accepted.

      A type II error (false negative) occurs when the alternative hypothesis is rejected when it should be accepted.

      The probability determines the rejection of a null hypothesis.

      The level of significance is set at p <0.05.

    • This question is part of the following fields:

      • Statistical Methods
      32.5
      Seconds
  • Question 15 - A study aimed at assessing a novel proton pump inhibitor (PPI) in aged...

    Correct

    • A study aimed at assessing a novel proton pump inhibitor (PPI) in aged patients taking aspirin. The new PPI is prescribed to 120 patients and the already prevalent PPI is given to the 240 members of the control group. In the next 5 years, the instances of upper GI bleed reported in the experimental and control group were 24 and 60 respectively. What is the value of absolute risk reduction?

      Your Answer: 5%

      Explanation:

      ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)

      So,

      ARR= (24/120)-(60/240)

      ARR= 0.2-0.25

      ARR= 0.05 (Numerical Value)

      ARR= 5%

    • This question is part of the following fields:

      • Statistical Methods
      62.6
      Seconds
  • Question 16 - A radiologist is conducting an arch aortogram. She begins by entering the brachiocephalic...

    Incorrect

    • A radiologist is conducting an arch aortogram. She begins by entering the brachiocephalic artery using the angiography catheter. As she continues to advance the catheter, what vessels will the catheter enter?

      Your Answer: None of the above

      Correct Answer: Right subclavian artery

      Explanation:

      As there is no brachiocephalic artery on the left side, the artery is entered by the catheter on the right side.

      The brachiocephalic artery branches into the common carotid and the right subclavian artery, so the catheter is most likely to enter the right subclavian artery, or also possibly the right carotid.

    • This question is part of the following fields:

      • Anatomy
      58.1
      Seconds
  • Question 17 - Which of the following structures does the vertebral artery NOT traverse? ...

    Incorrect

    • Which of the following structures does the vertebral artery NOT traverse?

      Your Answer: Transverse process of C6

      Correct Answer: Intervertebral foramen

      Explanation:

      The vertebral artery originates from the subclavian artery and ascends through the neck in the transverse foramen of the C1-C6 vertebrae. C2 vertebra is called the axis vertebra. A part of the vertebral artery lies in a groove on the upper surface of the atlas’s (C1) posterior arch. It enters the vertebral canal below the inferior border of the posterior atlantooccipital membrane. The vertebral arteries then enter the skull via the foramen magnum.

    • This question is part of the following fields:

      • Anatomy
      20.8
      Seconds
  • Question 18 - A 47-year old man and known alcoholic suffered a fall that resulted to...

    Correct

    • A 47-year old man and known alcoholic suffered a fall that resulted to a fracture on his right leg. Radiographic imaging showed a fractured tibial shaft. Following surgery, you were instructed to prescribe intravenous paracetamol as an analgesic. If the patient weighs 49 kg, which of the following would be the best regimen for the patient?

      Your Answer: 15 mg/kg with a maximum daily dose of 60 mg/kg (not exceeding 3 g)

      Explanation:

      A stock dose of Intravenous paracetamol available in the market is 10mg/ml. There is a recommended dose of IV paracetamol according to the profile of the patient (age, co-morbidities, weight).

      Weight Recommended Dose Maximum per day
      ‰¤10 kg 7.5 mg/kg 30 mg/kg
      >10 kg to ‰¤33 kg 15 mg/kg 60 mg/kg (not exceeding 2 g)
      >33 kg to ‰¤50 kg 15 mg/kg 60 mg/kg (not exceeding 3 g)
      >50 kg with additional risk factors for hepatotoxicity 1g 3 g
      >50 kg with no additional risk factors for hepatotoxicity 1g 4 g

      Special precaution must be observed for patients with hepatocellular insufficiency. The maximum dose per day should not exceed 3g.

    • This question is part of the following fields:

      • Pharmacology
      40.3
      Seconds
  • Question 19 - Out of the following, which therapy for acute severe asthma or life-threatening asthma...

    Incorrect

    • Out of the following, which therapy for acute severe asthma or life-threatening asthma has been NOT been approved in recent guidelines?

      Your Answer: Bolus dose of intravenous Salbutamol

      Correct Answer: Heliox

      Explanation:

      Recommendations from the British Thoracic Society for acute severe asthma or life-threatening asthma are:

      1. Give controlled supplementary oxygen to all hypoxemic patients with acute severe asthma titrated to maintain a SpO‚‚ level of 94 98%.
      2. Use high-dose inhaled β‚‚ agonists as first-line agents in patients with acute asthma and administer them as early as possible. Reserve
      intravenous β‚‚ agonists for those patients in whom inhaled therapy cannot be used reliably.
      3. Give steroids in adequate doses to all patients with an acute asthma attack.
      4. Add nebulized ipratropium bromide (0.5 mg 4€“6 hourly) to β‚‚ agonist treatment for acute severe or life-threatening asthma or those with a poor initial response to β‚‚ agonist therapy.
      5. Consider aminophylline for children with severe or life-threatening asthma unresponsive to maximal doses of bronchodilators and steroids.

      A review (including 12 case reports, three RCTs, and five other observational studies) of ketamine use in adults and children in status asthmaticus reported that ketamine is a potential bronchodilator. Still, prospective trials are needed before conclusions about effectiveness can be drawn.

      Heliox has no place in the current guidelines issued by the British Thoracic Society.

    • This question is part of the following fields:

      • Anatomy
      11.7
      Seconds
  • Question 20 - A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a...

    Correct

    • A pre-operative evaluation for a trans-sphenoidal pituitary adenectomy is being performed on a 57-year-old woman. Her vision is causing her problems. A macroadenoma compressing the optic chiasm is visible on MRI. What is the most likely visual field defect to be discovered during an examination?

      Your Answer: Bitemporal hemianopia

      Explanation:

      The pituitary gland plays a crucial role in the neuro-endocrine axis. It is located at the base of the skull in the sella turcica of the sphenoid bone. It is connected superiorly to the hypothalamus, third ventricle, and visual pathways, and laterally to the cavernous sinuses, internal carotid arteries, and cranial nerves III, IV, V, and VI.

      Pituitary tumours make up about 10-15% of all intracranial tumours. The majority of adenomas are benign. Over-secretion of pituitary hormones (most commonly prolactin, growth hormone, or ACTH), under-secretion of hormones, or localised or generalised pressure effects can all cause symptoms.

      Compression of the optic chiasm can result in visual field defects, the most common of which is bitemporal hemianopia. This is caused by compression of the nasal retinal fibres, which carry visual impulses from temporal vision across the optic chiasm to the contralateral sides before continuing to the optic tracts.

      The interruption of the visual pathways distal to the optic chiasm causes a homonymous visual field defect. The loss of the right or left halves of each eye’s visual field is referred to as homonymous hemianopia. It’s usually caused by a middle or posterior cerebral artery territory stroke that affects the occipital lobe’s optic radiation or visual cortex.

      Binasal hemianopia is a condition in which vision is lost in the inner half of both eyes (nasal or medial). It’s caused by compression of the temporal visual pathways, which don’t cross at the optic chiasm and instead continue to the ipsilateral optic tracts. Binasal hemianopia is a rare complication caused by the internal carotid artery impinging on the temporal (lateral) visual fibres.

      A monocular visual loss (that is, loss of vision in only one eye) can be caused by a variety of factors, but if caused by nerve damage, the damage would be proximal to the optic chiasm on the ipsilateral side.

      A central scotoma is another name for central visual field loss. Every normal mammalian eye has a scotoma, also known as a blind spot, in its field of vision. The optic disc is a region of the retina that lacks photoreceptor cells and is where the retinal ganglion cell axons that make up the optic nerve exit the retina. When both eyes are open, visual signals that are absent in one eye’s blind spot are provided for the other eye by the opposite visual cortex, even if the other eye is closed.

      Scotomata can be caused by a variety of factors, including demyelinating disease such as multiple sclerosis, damage to nerve fibre layer in the retina, methyl alcohol, ethambutol, quinine, nutritional deficiencies, and vascular blockages either in the retina or in the optic nerve.

      Bilateral scotoma can occur when a pituitary tumour compresses the optic chiasm, causing a bitemporal paracentral scotoma, which then spreads out to the periphery, causing bitemporal hemianopsia. A central scotoma in a pregnant woman could be a sign of severe pre-eclampsia.

    • This question is part of the following fields:

      • Pathophysiology
      11.7
      Seconds
  • Question 21 - A 30-year-old woman with a BMI of 24 kg/m2 consumes four glasses of...

    Correct

    • A 30-year-old woman with a BMI of 24 kg/m2 consumes four glasses of wine on an empty stomach. Her serum alcohol are levels measured over the following five hours. The serum alcohol level of 30-year-old man with the same BMI and alcohol consumption is also measured over the same duration. The peak concentration of alcohol is found to be greater in the woman than in the man. Which of these offers best explanation for this observation?

      Your Answer: Lower volume of distribution

      Explanation:

      The blood alcohol concentration depends on:

      -The rate of alcohol absorption from the gastrointestinal tract
      -The volume of distribution of alcohol in the body, and
      -The rate of elimination of alcohol from the body.

      Total body water is approximately 50% in a female as compared to 60% in a typical male. This means that the volume of distribution of alcohol is lower in female compared with men. This is the principal reason for higher peak in alcohol levels.

      About 4% of ingested alcohol is metabolised by the liver accounting for first pass metabolism and 0.4% is metabolised by gastric alcohol dehydrogenase (ADH). The absorbed alcohol is NOT distributed to fat cells but it is distributed throughout the water compartments (plasma, interstitial and intracellular) of the body. Women have very little gastric ADH, which further influences this exaggerated rise.

      85-98% of the alcohol is oxidised by the liver to acetaldehyde and then to acetate. The metabolic pathway initially observes first order kinetics and then saturation or zero order kinetics leading to peaks in alcohol levels.

      Clearance of ethanol per unit lean body mass is lower in male. The calculated alcohol elimination rate and liver volume per kilogram of lean body mass were 33% and 38% higher in women than in men, respectively.

      Available evidence in the literature about the relationship of alcohol metabolism to the phases of the menstrual cycle is conflicting.

    • This question is part of the following fields:

      • Pathophysiology
      36.8
      Seconds
  • Question 22 - A 70-year-old female is on bisoprolol, amitriptyline, and gabapentin medication and required hemiarthroplasty...

    Incorrect

    • A 70-year-old female is on bisoprolol, amitriptyline, and gabapentin medication and required hemiarthroplasty for a fractured neck of the femur. Spinal anaesthesia using 10 mg of IV ketamine to aid positioning was decided to be used. This resulting block extended to T8 and she required boluses of metaraminol for hypotension. She became profoundly hypertensive and had multiple ventricular ectopic beats on ECG following positioning in theatre. Which of the following is the cause for this?

      Your Answer: Metaraminol

      Correct Answer: Ketamine

      Explanation:

      Ketamine is primarily used for the induction and maintenance of anaesthesia. It induces dissociative anaesthesia. But it is contraindicated in cardiovascular diseases such as unstable angina or poorly controlled hypertension.

      Tricyclic antidepressants (TCA) are primarily used as antidepressants which is important for the management of depression. These are second-line drugs next to SSRI. They work by competitively preventing re-uptake of amines (noradrenaline and serotonin) from the synaptic cleft so increasing their concentration. But TCA overdoses are toxic and have cardiovascular effects, central effects, and anticholinergics effects. Cardiovascular effects like prolonged QT and widened QRS at lower doses progressing to ventricular arrhythmias and refractory hypotension at higher doses can be life-threatening. When used in the perioperative period, it can lead to increased sensitivity to circulating catecholamines therefore care is needed perioperatively.

    • This question is part of the following fields:

      • Pharmacology
      36.1
      Seconds
  • Question 23 - Which of the following anaesthetic is the least powerful trigger of malignant hyperthermia?...

    Incorrect

    • Which of the following anaesthetic is the least powerful trigger of malignant hyperthermia?

      Your Answer: Halothane

      Correct Answer: Sevoflurane

      Explanation:

      Desflurane is a highly fluorinated methyl ethyl ether used for the maintenance of general anaesthesia. It has been identified as a weak triggering anaesthetic of malignant hyperthermia. That, in the absence of succinylcholine, may produce a delayed onset of symptoms.

    • This question is part of the following fields:

      • Pharmacology
      9.1
      Seconds
  • Question 24 - Which compound is secreted only from the adrenal medulla? ...

    Correct

    • Which compound is secreted only from the adrenal medulla?

      Your Answer: Adrenaline

      Explanation:

      The adrenal medulla comprises chromaffin cells (pheochromocytes), which are functionally equivalent to postganglionic sympathetic neurons. They synthesize, store and release the catecholamines noradrenaline (norepinephrine) and adrenaline (epinephrine) into the venous sinusoids.
      The majority of the chromaffin cells synthesize adrenaline.

    • This question is part of the following fields:

      • Anatomy
      8.6
      Seconds
  • Question 25 - Which of the following intravenous induction agents is best for the patient with...

    Correct

    • Which of the following intravenous induction agents is best for the patient with acute intermittent porphyria requiring rapid sequence induction for emergency surgery?

      Your Answer: Propofol

      Explanation:

      Propofol is considered a safe drug to use in porphyria because even if causes mild elevation of porphyrins inpatient, it does not cause any symptoms.

      Since barbiturates are inducers of ALA synthetase, they are contraindicated in porphyria patients. So, thiopentone most not be used.

      Etomidate is a potent inhibitor of adrenal 11 beta-hydroxylase and 17 alpha-hydroxylase reducing cortisol and aldosterone synthesis in the adrenal cortex and has been associated with exacerbations of porphyria in animal studies and it is advisable not to use it in this condition.

      Ketamine should be reserved for the hemodynamically unstable patient, however, it is a safe drug.

      Diazepam is safe in porphyria but is not usually used for a rapid sequence induction.

    • This question is part of the following fields:

      • Pharmacology
      12.8
      Seconds
  • Question 26 - The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised...

    Incorrect

    • The physiological properties of a fast glycolytic (fast twitch) muscle fibre are characterised by which of the following?

      Your Answer: Small diameter to initiate short term intense contractions

      Correct Answer: Synthesis of ATP is brought about by anaerobic respiration

      Explanation:

      Muscle fibre myosin ATPase histochemistry is used to divide the biochemical classification into two groups: type 1 and type II.

      Type I (slow twitch) muscle fibres rely on aerobic glycolytic and aerobic oxidative metabolism to function. They have a lot of mitochondria, a good blood supply, a lot of myoglobin, and they don’t get tired easily.

      Because they contain more motor units, Type II (fast twitch) muscle fibres are thicker. They are more easily fatigued, but produce powerful bursts. The capillary networks and mitochondria are less dense in these white muscle fibres than in type I fibres. They have a low myoglobin content as well.

      Muscle fibres of type II (fast twitch) are divided into three types:

      Type IIa – aerobic/oxidative metabolism is used.
      Type IIb – anaerobic/glycolytic metabolism is used by these fibres.

      When compared to skeletal muscle, cardiac and smooth muscle twitch at a slower rate.

    • This question is part of the following fields:

      • Pharmacology
      19.4
      Seconds
  • Question 27 - A 30-year-old man has been stabbed in an area of the groin that...

    Correct

    • A 30-year-old man has been stabbed in an area of the groin that contains the femoral triangle. He will undergo explorative surgery. Which of the following makes the lateral wall of the femoral triangle?

      Your Answer: Sartorius

      Explanation:

      The femoral triangle is a wedge-shaped area found within the superomedial aspect of the anterior thigh. It is a passageway for structures to leave and enter the anterior thigh.

      Superior: Inguinal ligament
      Medial: Adductor longus
      Lateral: Sartorius
      Floor: Iliopsoas, adductor longus and pectineus

      The contents include: (medial to lateral)
      Femoral vein
      Femoral artery-pulse palpated at the mid inguinal point
      Femoral nerve
      Deep and superficial inguinal lymph nodes
      Lateral cutaneous nerve
      Great saphenous vein
      Femoral branch of the genitofemoral nerve.

    • This question is part of the following fields:

      • Anatomy
      11.8
      Seconds
  • Question 28 - One of the following sets of arterial blood gases best demonstrates compensated respiratory...

    Correct

    • One of the following sets of arterial blood gases best demonstrates compensated respiratory acidosis?

      Your Answer: pH=7.36, PaCO2=8.5kPa, PaO2=7.5kPa, HCO3- = 43mmol/L

      Explanation:

      pH=7.36, PaCO2=8.5kPa, PaO2=7.5kPa, HCO3- = 43mmol/L is the correct answer.

      Since the pH is the lower limit of normal, it is compensated despite a raised PaCO2. Retention of bicarbonate ions by the renal system suggests this process is chronic.

      pH=7.24, PaCO2=3.5kPa, PaO2=8.5kPa, HCO3- =18mmol/L represents an acute uncompensated metabolic acidosis

      The remaining stems are degrees of uncompensated respiratory acidosis and therefore incorrect.

    • This question is part of the following fields:

      • Pathophysiology
      14
      Seconds
  • Question 29 - A 74-year-old with a VVI pacemaker is undergoing a hip replacement. Which of...

    Correct

    • A 74-year-old with a VVI pacemaker is undergoing a hip replacement. Which of the following is most likely to predispose him to an electrical hazard?

      Your Answer: Use of cutting unipolar diathermy

      Explanation:

      A single chamber pacemaker was implanted in the patient. In VVI mode, a pacemaker paces and senses the ventricle while being inhibited by a perceived ventricular event. The most likely electrical hazard from diathermy is electromagnetic interference (EMI).

      EMI has the potential to cause the following: Inhibition of pacing
      Asynchronous pacing
      Reset to backup mode
      Myocardial burns, and
      Trigger VF.

      Diathermy entails the implementation of high-frequency electrical currents to produce heat and either make incisions or induce coagulation. Monopolar cautery involves disposable cautery pencils and electrosurgical diathermy units. In typical monopolar cautery, an electrical plate is placed on the patient’s skin and acts as an electrode, while the current passes between the instrument and the plate. Monopolar diathermy can therefore interfere with implanted metal devices and pacemaker function.

      Bipolar diathermy, where the current passes between the forceps tips and not through the patient and is less likely to generate EMI.

      Whilst the presence of a CVP line may in theory predispose the patient to microshock, the use of prerequisite CF electrical equipment makes this very unlikely. The presence of a CVP line and pacemaker does not therefore unduly increase the risk of an electrical hazard.

      Isolating transformers are used to protect secondary circuits and individuals from electrical shocks. There is no step-up or step-down voltage (i.e. there is a ratio of 1 to 1 between the primary and secondary windings).

      A ground (or earth) wire is normally connected to the metal case of an operating table to protect patients from accidental electrocution. In the event that a fault allows a live wire to make contact with the metal table (broken cable, loose connection etc.) it becomes live. The earth will provide an immediate path for current to safely flow through and so the table remains safe to touch. Being a low resistance path, the earth lets a large current flow through it when the fault occurs ensuring that the fuse or RCD will quickly blow. Without an operating table earth, the patient is not at more risk of an electrical hazard because of the pacemaker.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      9.5
      Seconds
  • Question 30 - Which of the following facts about IgE is true? ...

    Incorrect

    • Which of the following facts about IgE is true?

      Your Answer: Is increased acutely in an asthmatic attack

      Correct Answer: Is increased in the serum of atopic individuals

      Explanation:

      Immunoglobulin E (IgE) are an antibody subtype produced by the immune system. They are the least abundant type and function in parasitic infections and allergy responses.

      The most predominant type of immunoglobulin is IgG. It is able to be transmitted across the placenta to provide immunity to the foetus.

      IgE is involved in the type I hypersensitivity reaction as it stimulates mast cells to release histamine. It has no role in type 2 hypersensitivity.

      Its concentration in the serum is normally the least abundant, however certain reactions cause a rise in its concentration, such as atopy, but not in acute asthma.

    • This question is part of the following fields:

      • Pathophysiology
      13.1
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Pathophysiology (8/10) 80%
Physiology (1/1) 100%
Pharmacology (2/6) 33%
Statistical Methods (5/5) 100%
Anaesthesia Related Apparatus (1/3) 33%
Anatomy (2/5) 40%
Passmed