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  • Question 1 - A radiologist is conducting an arch aortogram. She begins by entering the brachiocephalic...

    Correct

    • A radiologist is conducting an arch aortogram. She begins by entering the brachiocephalic artery using the angiography catheter. As she continues to advance the catheter, what vessels will the catheter enter?

      Your Answer: Right subclavian artery

      Explanation:

      As there is no brachiocephalic artery on the left side, the artery is entered by the catheter on the right side.

      The brachiocephalic artery branches into the common carotid and the right subclavian artery, so the catheter is most likely to enter the right subclavian artery, or also possibly the right carotid.

    • This question is part of the following fields:

      • Anatomy
      32.1
      Seconds
  • Question 2 - Rocuronium is substituted for succinylcholine during induction of anaesthesia for a caesarean section...

    Correct

    • Rocuronium is substituted for succinylcholine during induction of anaesthesia for a caesarean section delivery. Which of the following feature of rocuronium ensures the neonate shows no clinical signs of muscle relaxation?

      Your Answer: Highly ionised

      Explanation:

      Drugs cross the placenta by Simple, Ion channel and Facilitated diffusion; Exocytosis and Endocytosis, Osmosis, and Active transport (primary and secondary)

      The following factors influence rate of diffusion across the placenta:

      Protein binding
      Degree of ionisation
      Placental blood flow
      Maternal and foetal blood pH
      Materno-foetal concentration gradient.
      Thickness of placental membrane
      Molecular weight of drug <600 Daltons cross by diffusion
      Lipid solubility (lipid soluble molecules readily diffuse across the placenta)

      Rocuronium has a F/M ratios of 0.16, a 30% plasma protein binding, low lipid solubility, a low volume of distribution (0.25L/kg), and a high molecular weight (530Da).

    • This question is part of the following fields:

      • Pharmacology
      22
      Seconds
  • Question 3 - A transport ventilator is powered by an air/oxygen mix using a full oxygen...

    Correct

    • A transport ventilator is powered by an air/oxygen mix using a full oxygen cylinder (class CD) with an internal capacity of 2 litres, and pressure of 23,000 kPa, with a gas flow of 4 litres/minute. The ventilator also has a control resulting in an additional gas consumption of 1 litre/minute. How long will it take for the cylinder to empty?

      Your Answer: 92 minutes

      Explanation:

      The Drager Oxylog® 1000 is a pneumatically powered, time-dependent, volume-titrated emergency ventilator with a pressure limit. It is compatible with CD cylinder oxygen. The CD cylinder is a strong and lightweight cylinder usually composed of aluminium or Kevlar. The internal cylinder volume is 2 litres, and the pressure of a full cylinder is 230 bar. The volume of the full cylinder is determined by applying Boyle’s law: P1 × V1 = P2 × V2

      Where:
      P1= pressure of a full cylinder (230 bar)
      V1= volume of oxygen at that pressure (2 litres)
      P2= final pressure (1 bar), and
      V2= volume of oxygen in the full cylinder.

      Substituting values into the equation:

      230 × 2 = 1 x V2
      V2 = 460 litres. The flow of fresh gas is 4 litres/minute + 1 litre/minute required by the control, making a total of 5 litres/minute. The amount of time it takes for the cylinder to empty would be the total volume of oxygen in the full cylinder divided by the amount of oxygen expelled per minute: 460/5 = 92, meaning it would take 92 minutes for the cylinder to empty.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      2.6
      Seconds
  • Question 4 - A 21-year-old female was brought to the Emergency department with a ruptured ectopic...

    Correct

    • A 21-year-old female was brought to the Emergency department with a ruptured ectopic pregnancy. On clinical examination, the following were the findings: Pulse: 120 beats per minute, BP: 120/95 mmHg, Respiratory rate: 22 breaths per minute, Capillary refill time: three seconds, Cool peripheries. Which of the following best describes the cause for this clinical finding?

      Your Answer: Reduction in blood volume of 15-30%

      Explanation:

      Classification of hemorrhagic shock according to Advanced Trauma Life Support is as follows:

      – Class I haemorrhage (blood loss up to 15%) in which there is no change in blood pressure, RR, or pulse pressure.

      – Class II haemorrhage (15-30% blood volume loss) where there is tachycardia, tachypnoea, and a decrease in pulse pressure.

      – Class III haemorrhage (30-40% blood volume loss) where clinical signs of inadequate perfusion, marked tachycardia, tachypnoea, significant changes in mental state, and measurable fall in systolic pressure is seen. It almost always requires a blood transfusion.

      – Class IV haemorrhage (> 40% blood volume loss) in which marked tachycardia, significant depression in systolic pressure and very narrow pulse pressure, and markedly depressed mental state with cold and pale skin are seen.

      Loss of >50% results in loss of consciousness, pulse, and blood pressure.

    • This question is part of the following fields:

      • Pathophysiology
      7.2
      Seconds
  • Question 5 - One of the non-pharmacologic management of COPD is smoking cessation. Given a case...

    Incorrect

    • One of the non-pharmacologic management of COPD is smoking cessation. Given a case of a 60-year old patient with history of smoking for 30 years and a FEV1 of 70%, what would be the most probable five-year course of his FEV1 if he ceases to smoke?

      Your Answer: The FEV1 will decrease at the same rate as a smoker

      Correct Answer: The FEV1 will decrease at the same rate as a non-smoker

      Explanation:

      For this patient, his forced expiratory volume in 1 second (FEV1) will decrease at the same rate as a non-smoker.

      There is a notable, but slow, decline in FEV1 when an individual reaches the age of 26. An average reduction of 30 mls every year in non-smokers, while a more significant reduction of 50-70 mls is observed in approximately 20% of smokers.

      Considering the age of the patient, individuals who begin smoking cessation by the age of 60 are far less likely to achieve normal FEV1 levels, even in the next five years. It is expected that their FEV1 will be approximately 14% less than their peers of the same age.

    • This question is part of the following fields:

      • Physiology
      5.6
      Seconds
  • Question 6 - With regards to devices for temperature management, all of these are used EXCEPT:...

    Correct

    • With regards to devices for temperature management, all of these are used EXCEPT:

      Your Answer: Thermistors use the resistance of a semiconductor bead which increases exponentially as the temperature increases

      Explanation:

      There are different types of temperature measurement. These include:

      Thermistor – this is a type of semiconductor, meaning they have greater resistance than conducting materials, but lower resistance than insulating materials. There are small beads of semiconductor material (e.g. metal oxide) which are incorporated into a Wheatstone bridge circuit. As the temperature increases, the resistance of the bead decreases exponentially

      Thermocouple – Two different metals make up a thermocouple. Generally, in the form of two wires twisted, welded, or crimped together. Temperature is sensed by measuring the voltage. A potential difference is created that is proportional to the temperature at the junction (Seebeck effect)

      Platinum resistance thermometers (PTR) – uses platinum for determining the temperature. The principle used is that the resistance of platinum changes with the change of temperature. The thermometer measures the temperature over the range of 200°C to1200°C. Resistance in metals show a linear increase with temperature

      Tympanic thermometers – uses infrared radiation which is emitted by all living beings. It analyses the intensity and wavelength and then transduces the heat energy into a measurable electrical output

      Gauge/dial thermometers – Uses coils of different metals with different co-efficient of expansion. These either tighten or relax with changes in temperature, moving a lever on a calibrated dial.

    • This question is part of the following fields:

      • Clinical Measurement
      3.6
      Seconds
  • Question 7 - Which of the following statements is true regarding dopamine? ...

    Incorrect

    • Which of the following statements is true regarding dopamine?

      Your Answer: Decreases gastric transit time

      Correct Answer: It can increase or decrease cAMP levels

      Explanation:

      Dopamine (DA) is a dopaminergic (D1 and D2) as well as adrenergic α and β1 (but not β2 ) agonist.

      The D1 receptors in renal and mesenteric blood vessels are the most sensitive: i.v. infusion of a low dose of DA dilates these vessels (by raising intracellular cAMP). This increases g.f.r. In addition, DA exerts a natriuretic effect by D1 receptors on proximal tubular cells.

      Moderately high doses produce a positive inotropic (direct β1 and D1 action + that due to NA release), but the little chronotropic effect on the heart.

      Vasoconstriction (α1 action) occurs only when large doses are infused.

      At doses normally employed, it raises cardiac output and systolic BP with little effect on diastolic BP. It has practically no effect on nonvascular α and β receptors; does not penetrate the blood-brain barrier€”no CNS effects.

      Dopamine is used in patients with cardiogenic or septic shock and severe CHF wherein it increases BP and urine outflow.

      It is administered by i.v. infusion (0.2€“1 mg/min) which is regulated by monitoring BP and rate of urine formation

    • This question is part of the following fields:

      • Pharmacology
      3.2
      Seconds
  • Question 8 - Concerning the physical principles of temperature measurement by a thermocouple, which of the...

    Correct

    • Concerning the physical principles of temperature measurement by a thermocouple, which of the following best describes it?

      Your Answer: The bimetallic strip has a junction potential proportional to temperature

      Explanation:

      A thermocouple, or a thermal junction, is temperature measuring device consisting of a pair of dissimilar metal (bimetallic) wires or strips joined together. Typically, copper and constantan (an alloy of 55% copper and 45% nickel) are used. When there is contact between these metals, a small voltage is generated in the order of millivolts. The magnitude of the thermojunction electromotive force (emf) is proportional to applied temperature (the Seebeck effect). This physical principle is applied in the measurement of temperature. The electromotive force at the measuring junction is proportional to temperature.

      Two wires with different coefficients of expansion, joined together, can be used as a switch for thermostatic control.

      Semiconductors are NOT used in thermocouple. The resistance of the measuring junction of a thermocouple is irrelevant.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      20
      Seconds
  • Question 9 - The child-Pugh scoring system can be used, if risk classifying a patient with...

    Correct

    • The child-Pugh scoring system can be used, if risk classifying a patient with chronic liver disorder earlier to anaesthesia. Which one is the best combination of clinical signs and examinations used within the Child-Pugh scoring system?

      Your Answer: Ascites, grade of encephalopathy, albumin, bilirubin and INR

      Explanation:

      In the Child-Pugh classification system, the following 5 components are determined or calculated in order:

      Ascites

      Grade of encephalopathy

      Serum bilirubin (μmol/L)

      Serum Albumin (g/L)

      Prothrombin time or INR

      Raised liver enzymes are not the component of the classification system.

    • This question is part of the following fields:

      • Basic Physics
      24.7
      Seconds
  • Question 10 - Which of the following correctly explains the mechanism of lowering blood pressure by...

    Incorrect

    • Which of the following correctly explains the mechanism of lowering blood pressure by nitroglycerine?

      Your Answer: Nitric oxide

      Correct Answer: Acetylcholine

      Explanation:

      Nitroglycerine is rapidly denitrated enzymatically in the smooth muscle cell to release the free radical nitric oxide (NO).
      Released NO activated cytosolic guanylyl cyclase which increases cGMP (cyclin guanosine monophosphate) which causes dephosphorylation of myosin light chain kinase (MLCK) through a cGMP-dependent protein kinase.
      Reduced availability of phosphorylated (active) MLCK interferes with activation of myosin and in turn, it fails to interact with actin to cause contraction. Consequently, relaxation occurs.

    • This question is part of the following fields:

      • Pharmacology
      9.2
      Seconds
  • Question 11 - The required sample size in a trial of a new therapeutic agent varies...

    Correct

    • The required sample size in a trial of a new therapeutic agent varies with?

      Your Answer: Level of statistical significance required

      Explanation:

      The level of statistical significance required influences the sample size used. This is because sample size is used in the calculation of SD/SE.

      Sample size does not affect

      The level of acceptance
      The alternative hypothesis with a general level set at p<0.05
      The test to be used.

      Experience of the investigator and the type of patient recruited should have no bearing on the required sample size.

    • This question is part of the following fields:

      • Statistical Methods
      2.7
      Seconds
  • Question 12 - Regarding pre-eclampsia with warning signs, which of the following laboratory tests is the...

    Incorrect

    • Regarding pre-eclampsia with warning signs, which of the following laboratory tests is the most appropriate to establish a platelet dysfunction or disorder?

      Your Answer: Template bleeding time

      Correct Answer: Platelet count

      Explanation:

      Decreased platelet concentrations with eclampsia were described as early as 1922 by Stancke. The platelet count is routinely measured in women with any form of gestational hypertension. The frequency and intensity of thrombocytopenia vary and are dependent on the severity and duration of the preeclampsia syndrome and the frequency with which platelet counts are performed.

      Overt thrombocytopenia defined by a platelet count < 100,000/microliter - indicates severe disease. In general, the lower the platelet count, the higher the rates of maternal and fetal morbidity and mortality. In most cases, delivery is advisable because thrombocytopenia usually continues to worsen. After delivery, the platelet count may continue to decline for the first day or so. It then usually increases progressively to reach a normal level within 3-5 days. In some instances with HELLP syndrome, the platelet count continues to fall after delivery. If these do not reach a nadir until 48 to 72 hours, then preeclampsia syndrome may be incorrectly attributed to one of the thrombotic microangiopathies. The following are other severe features associated with preeclampsia: Proteinuria: >/= 300 mg/24 hours; or urine protein: creatinine ratio >/= 0.3; or dipstick 1+

      Renal insufficiency: serum creatinine > 1.1 mg/dL or doubling of creatinine in the absence of other renal disease

      Impaired liver function: two times elevated AST/ALT or unexplained right upper quadrant pain or epigastric pain unresponsive to medications

      Pulmonary oedema

      Cerebral or visual symptoms: headache, visual disturbances.

    • This question is part of the following fields:

      • Pathophysiology
      13.9
      Seconds
  • Question 13 - While administering a general anaesthetic to a 65-year-old man booked for a hip...

    Incorrect

    • While administering a general anaesthetic to a 65-year-old man booked for a hip hemiarthroplasty, with a weight 70 kg, and an ASA 1 score, you give 1 g of paracetamol IV but notice that he had received the same dose on the ward one hour prior. What is the most appropriate subsequent management of this patient?

      Your Answer: Measure aspartate transaminase levels on a daily basis and manage accordingly

      Correct Answer: Do nothing and give the next doses of paracetamol at standard 6 hour intervals

      Explanation:

      After ingestion of more than 150 mg/kg paracetamol within 24 hours, hepatotoxicity can occur but can also develop rarely after ingestion of doses as low as 75 mg/kg within 24 hours. Hepatocellular damage will not occur in this patient and therefore no need to engage management pathway for paracetamol overdose. If his weight was <33 kg or he already had a history of impaired liver function, then the management would bde different.

      Subsequent post-operative doses will be a standard dose of 1 g 6 hourly.

      This is a drug administration error and should be reported as an incident even though the patient will not be harmed.

    • This question is part of the following fields:

      • Pharmacology
      12.7
      Seconds
  • Question 14 - Radical prostatectomy is being performed on a 60-year-old man for carcinoma of the...

    Incorrect

    • Radical prostatectomy is being performed on a 60-year-old man for carcinoma of the prostate gland. What is the direct blood supply of the prostate?

      Your Answer: Common iliac artery

      Correct Answer: Inferior vesical artery

      Explanation:

      The prostate gland is primarily supplied by the inferior vesical artery, which branches off from the anterior division of the internal iliac artery. The inferior vesical artery supplies the base of the bladder, the distal ureters, and the prostate. The branches to the prostate communicate with the corresponding vessels of the opposite side.

      The inferior vesical artery branches into two main arteries:
      1. Urethral artery – supplies the transition zone and is the main arterial supply for the adenomas in BPH
      2. Capsular artery – supplies the glandular tissue

      The venous drainage of the prostate is from the prostatic venous plexus, which drains into the paravertebral veins.

    • This question is part of the following fields:

      • Anatomy
      16.2
      Seconds
  • Question 15 - Gag reflex was assessed as a part of brain stem death in a...

    Incorrect

    • Gag reflex was assessed as a part of brain stem death in a 22-year-old man with severe traumatic brain injury. Which of the following nerves forms the afferent limb of this reflex?

      Your Answer: Accessory nerve

      Correct Answer: Glossopharyngeal nerve

      Explanation:

      The gag reflex is a protective mechanism that prevents any foreign material to enter the aerodigestive tract.

      This reflex has afferent (sensory) and effect (motor) components.
      – Glossopharyngeal nerve form the afferent limb
      – Vagus nerve form the efferent limb.

    • This question is part of the following fields:

      • Pathophysiology
      23.7
      Seconds
  • Question 16 - A 68-year-old man has suffered a myocardial infarction. He has a heart rate...

    Incorrect

    • A 68-year-old man has suffered a myocardial infarction. He has a heart rate of 40 beats per minute currently. Your senior attending explains that the slow heart rate is due to the damage to the conduction pathways between the sinoatrial and atrioventricular nodes. His ventricles are being paced by the AV node alone. What artery supplies the AV node in the majority of patients?

      Your Answer: Posterior descending artery

      Correct Answer: Right coronary artery

      Explanation:

      The AV node has an intrinsic firing rate of 40-60 beats per minute which is clinically significant in cases of damage to the conducting pathways as patients continue to have a ventricular rate of 40-60. Patients who have an AV node supplied by the right coronary are said to be right dominant. The remaining 10% are left dominant and supplied by the left circumflex.

      The right coronary artery supplies the right atrium, right ventricle, interatrial septum, and the inferior posterior third of the interventricular septum. It also supplies the atrioventricular node + sinoatrial node in most patients. The posterior descending artery supplies the posterior third of the interventricular septum.

      The heart receives blood supply from coronary arteries. The right and left coronary arteries branch off the aorta and supply oxygenated blood to all heart muscle parts.

      The left main coronary artery branches into:
      1. Circumflex artery – supplies the left atrium, side, and back of the left ventricle. The left marginal artery arises from the left circumflex artery. It travels along the obtuse margin of the heart.
      The left marginal artery, a branch of the circumflex artery, supplies the left ventricle.
      2. Left Anterior Descending (LAD) artery – supplies the front and bottom of the left ventricle and front of the interventricular septum

      The right coronary artery branches into:
      1. Right marginal artery
      2. Posterior descending artery.

    • This question is part of the following fields:

      • Anatomy
      17.2
      Seconds
  • Question 17 - A 28-year-old girl complained of severe abdominal pain and hematemesis and was rushed...

    Incorrect

    • A 28-year-old girl complained of severe abdominal pain and hematemesis and was rushed into the emergency department. She has an increased heart rate of 120 beats per minute and blood pressure of 90/65. She has a history of taking Naproxen for her Achilles tendinopathy. On urgent endoscopy, she is diagnosed with a bleeding peptic ulcer. The immediate treatment is to permanently stop the bleeding by performing embolization of the left gastric artery via an angiogram. What level of the vertebra will be used as a radiological marker for the origin of the artery that supplies the left gastric artery during the angiogram?

      Your Answer: T10

      Correct Answer: T12

      Explanation:

      The left gastric artery is the smallest branch that originates from the coeliac trunk€”the coeliac trunk branches of the abdominal aorta at the vertebral level of T12.

      The left gastric artery runs along the superior portion of the lesser curvature of the stomach. A peptic ulcer that is serious enough to erode through the stomach mucosa into a branch of the left gastric artery can cause massive blood loss in the stomach, leading to hematemesis. The patient also takes Naproxen, a non-steroidal anti-inflammatory drug that is a common cause for peptic ulcers in otherwise healthy patients.

      The left gastric artery is responsible for 85% of upper GI bleeds. In cases refractory to initial treatment, angiography is sometimes needed to embolise the vessel at its origin and stop bleeding. During an angiogram, the radiologist will enter the aorta via the femoral artery, ascend to the level of the 12th vertebrae and then enter the left gastric artery via the coeliac trunk.

      The important landmarks of vessels arising from the abdominal aorta at different levels of vertebrae are:

      T12 – Coeliac trunk

      L1 – Left renal artery

      L2 – Testicular or ovarian arteries

      L3 – Inferior mesenteric artery

      L4 – Bifurcation of the abdominal aorta.

    • This question is part of the following fields:

      • Anatomy
      6.7
      Seconds
  • Question 18 - A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck...

    Incorrect

    • A 50-year old man for septoplasty has a BMI of 32kg/m2 and neck circumference of 44 cm. He is troubled by intermittent nasal obstruction which causes his partner sleeps in a separate bedroom because of snoring. He currently on ramipril for hypertension. Which of the following best approximates to his STOP-BANG score from the information above?

      Your Answer: 6

      Correct Answer: 5

      Explanation:

      The STOP-BANG questionnaire is used to screen patients for obstructive sleep apnoea (OSA).

      The scoring system assigns one point for each feature.

      S: Snoring (louder than talking or loud enough to be heard through closed doors)
      T: Feeling tired, fatigued, or sleepy during daytime
      O: Observed apnoeas during sleep
      P: Hypertension
      B: BMI more than 35 kg/m2
      A: Age 50-years of age or greater
      N: Neck circumference (male 17 inches / 43cm or greater and female 16 inches / 41 or greater)
      G: Gender: Male

      Our patient has a score of 5 ( O, P, A, N, G)

      The score helps clinicians stratify patients for unrecognized OSA and target appropriate clinical management. It can also help triage patients for further investigation. A STOP-BANG score of 5-8 will identify patients with high probability of moderate to severe OSA in the surgical population.

    • This question is part of the following fields:

      • Clinical Measurement
      10.9
      Seconds
  • Question 19 - A caudal epidural block is planned for a 6-year-old child scheduled for an...

    Incorrect

    • A caudal epidural block is planned for a 6-year-old child scheduled for an inguinoscrotal hernia repair under general anaesthesia. The weight of the child is 20kg. The most important safety aspect the anaesthetist must keep in mind while performing the block is?

      Your Answer: Using electrostimulation to elicit the correct motor response

      Correct Answer: Limiting the bupivacaine dose to no more than 40 mg

      Explanation:

      Choosing an appropriate dose of local anaesthetic to reduce the chance of toxicity is the most important safety aspect in performing a caudal block.

      The caudal will have to be inserted following induction of anaesthesia as performing it in an awake child is not a viable option.

      The patient is placed in the lateral position and the sacral hiatus is identified. Under strict asepsis, a needle ( usually a 21-23FG needle) is advanced at an angle of approximately 55-65° to the coronal plane at the apex of the sacrococcygeal membrane. When there is loss of resistance, thats the endpoint. The needle must first be aspirated before anaesthetic agent is injected because there is a risk (1 in 2000) of perforating the dura or vascular puncture.

      Alternatively, a 22-gauge plastic cannula can be used. Following perforation of the sacrococcygeal membrane, the stilette is removed and only the blunter plastic cannula is advanced. This reduces the risk of intravascular perforation.

      Eliciting an appropriate end motor response at an appropriate current strength when the caudal and epidural spaces are stimulated helps in improving the efficacy and safety of neural blockade. A 22G insulated needle is advanced in the caudal canal until a pop is felt. If the needle is placed correctly, an anal sphincter contractions (S2 to S4) is seen when an electrical stimulation of 1-10 mA is applied.

      The application of ultrasound guidance in identification of the caudal epidural space has been shown to prevent inadvertent dural puncture and to increase the safety and efficacy of the block in children.

    • This question is part of the following fields:

      • Pharmacology
      12.2
      Seconds
  • Question 20 - A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise....

    Incorrect

    • A 47-year-old woman presented with chief complaints of dysuria, urinary frequency, and malaise. On urine culture and sensitivity testing, E.coli was detected with resistance to ampicillin. What is the mechanism of resistance to ampicillin?

      Your Answer: Efflux pump removing antibiotic from bacteria

      Correct Answer: Beta-lactamase production

      Explanation:

      Ampicillin belongs to the family of penicillin. Resistance to this group of drugs is due to β-lactamase production which opens the β-lactam ring and inactivates Penicillin G and some closely related congeners. The majority of Staphylococci and some strains of gonococci, B. subtilis, E. coli, and a few other bacteria produce penicillinase.

      Resistance to cephalosporins is due to changes in penicillin-binding proteins.

      Resistance to macrolides are due to post-transcriptional methylation of 23s bacterial ribosomal RNA

      Resistance to fluoroquinolones is due to mutations in DNA gyrase.

    • This question is part of the following fields:

      • Pharmacology
      17
      Seconds
  • Question 21 - A 25-year old lady is in the operating room and has had general...

    Incorrect

    • A 25-year old lady is in the operating room and has had general anaesthesia for a knee arthroscopy. Induction was done with fentanyl 1mcg/kg and propofol 2mg/kg. A supra-glottic airway was inserted and using and air oxygen mixture with 2.5% sevoflurane, her anaesthesia was maintained. The patient is allowed to spontaneously breathe using a Bain circuit, and the fresh gas flow is 9L/min. Over the next 30 minutes, the end-tidal Co2 rises from 4.5kPa to 8.4kPa, and the baseline reading on the capnograph is 0kPa. The most appropriate initial action is which of the following?

      Your Answer: Malignant hyperthermia

      Correct Answer: Hypoventilation

      Explanation:

      The commonest and most likely cause of a gradual rise in end-tidal CO2 (EtCO2) occurring during anaesthesia in a spontaneously breathing patient is hypoventilation. This occurs from the respiratory depressant effects of the opioid and sevoflurane.

      Malignant hyperthermia should be sought if the EtCO2 shows further progressive rise.

      Causes of rebreathing and a rise in the baseline of the capnograph can be caused by exhausted soda lime and inadequate fresh gas flow into the Bain circuit.

      A sudden rise in EtCO2 can be caused deflation of the tourniquet.

    • This question is part of the following fields:

      • Physiology
      7.2
      Seconds
  • Question 22 - Arterial pressure waveforms give an indication of the operation of the heart and...

    Correct

    • Arterial pressure waveforms give an indication of the operation of the heart and the patient's clinical state. Which of the following listed characteristics of arterial waveforms is most indicative of myocardial contractility?

      Your Answer: Slope of the upstroke of the curve.

      Explanation:

      Arterial pressure waveforms is an invasive form of monitoring cardiac parameters. It provides a lot of information on the performance of the heart from different sections, including:

      Cardiac measurements:

      Heart rate
      Systolic pressure
      Diastolic pressure
      Mean arterial pressure
      Pulse pressure
      Change in pulse amplitude corresponding to respiratory changes
      Slope of anacrotic limb associated with aortic stenosis

      From the shape of the arterial waveform displayed:

      Slope of anacrotic limb represents aortic valve and LVOT flow
      Indications of aortic stenosis (AS): Slurred wave, collapsing wave
      Rapid systolic decline in LVOTO
      Bisferiens wave in HOCM
      Low dicrotic notch in states with poor peripheral resistance
      Position and quality of dicrotic notch as a reflection of the damping coefficient

      For this question, the upstroke slope of the pressure wave is indicative of myocardial contractility and is mathematically represented as:

      dP/dt, which represents a change of pressure with regards to time.

    • This question is part of the following fields:

      • Clinical Measurement
      8.9
      Seconds
  • Question 23 - A trail has analysed that a new screening test may increase the survival...

    Incorrect

    • A trail has analysed that a new screening test may increase the survival time of ovarian cancer patients. But analyst say that the apparent increase in the patients survival time is just because of earlier detection instead of actual improvement. What kind of bias is in this experiment?

      Your Answer: Observation bias (Hawthorne effect)

      Correct Answer: Lead time bias

      Explanation:

      Observation bias occurs when the behaviour of an individual changes that results from their awareness of being observed.

      Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status.

      Attrition bias is a systematic error caused by unequal loss of participants from a randomized controlled trial (RCT). In clinical trials, participants might dropout due to unsatisfactory treatment or efficacy, intolerable adverse events, or even death.

      Selection bias introduced when the individuals are not chosen randomly to take a part in the study. It usually occurs when the research decides who is going to be studied, they are not the representative of the population.

      Lead-time bias occurs when a disease is detected by a screening test at an earlier time point rather than it would have been diagnosed by its clinical appearance. In this bias, earlier detection improves the survival time in the intervention group.

    • This question is part of the following fields:

      • Statistical Methods
      28.3
      Seconds
  • Question 24 - A 52-year old man was placed under general anaesthesia for an emergent open...

    Correct

    • A 52-year old man was placed under general anaesthesia for an emergent open cholecystectomy. As part of the induction, suxamethonium was administered at 1.5mg/kg. Post-operatively, there was failure to restore muscle twitch responses over a course of five hours. Clinical chemistry studies were obtained and showed the following results: Butrylcholinesterase (BChE) activity: 49 U/L (Reference range: 3300-10,300 U/L), Dibucaine number: <4% (Reference range: 83-88%). The attending physician gave an initial diagnosis of Suxamethonium Apnoea. What is the most probable phenotype of BChE of the patient?

      Your Answer: S (silent)

      Explanation:

      Silent (S) is the most probable phenotype of the patient. In S phenotype, patients have significantly reduced levels of BChE, the lowest among the four phenotypes. Because of this, individuals with S phenotype are subjected to long periods of apnoea. In addition, their dibucaine number is very low.

      Other BChE phenotypes are the following:

      Usual (U)
      Atypical (A)
      Fluoride-resistant (F).

    • This question is part of the following fields:

      • Pathophysiology
      12.3
      Seconds
  • Question 25 - A 30-year old lady has a sub total thyroidectomy. On the 5th post-operative...

    Incorrect

    • A 30-year old lady has a sub total thyroidectomy. On the 5th post-operative day, the wound becomes erythematous and there is a purulent discharge. The most likely organism causing this is:

      Your Answer: Pseudomonas aeruginosa

      Correct Answer: Staphylococcus aureus

      Explanation:

      Staphylococcus aureus infection is the most likely cause.

      Surgical site infections (SSI) occur when there is a breach in tissue surfaces and allow normal commensals and other pathogens to initiate infection. They are a major cause of morbidity and mortality.

      SSI comprise up to 20% of healthcare associated infections and approximately 5% of patients undergoing surgery will develop an SSI as a result.
      The organisms are usually derived from the patient’s own body.

      Measures that may increase the risk of SSI include:
      -Shaving the wound using a single use electrical razor with a disposable head
      -Using a non iodine impregnated surgical drape if one is needed
      -Tissue hypoxia
      -Delayed prophylactic antibiotics administration in tourniquet surgery, patients with a prosthesis or valve, in clean-contaminated surgery of in contaminated surgery.

      Measures that may decrease the risk of SSI include:
      1. Intraoperatively
      – Prepare the skin with alcoholic chlorhexidine (Lowest incidence of SSI)
      -Cover surgical site with dressing

      In contrast to previous individual RCT’s, a recent meta analysis has confirmed that administration of supplementary oxygen does not reduce the risk of wound infection and wound edge protectors do not appear to confer benefit.

      2. Post operatively
      Tissue viability advice for management of surgical wounds healing by secondary intention

      Use of diathermy for skin incisions
      In the NICE guidelines the use of diathermy for skin incisions is not advocated. Several randomised controlled trials have been undertaken and demonstrated no increase in risk of SSI when diathermy is used.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      5.6
      Seconds
  • Question 26 - Which of the following statement is true regarding the mechanism of action of...

    Incorrect

    • Which of the following statement is true regarding the mechanism of action of rifampicin?

      Your Answer: Inhibit 50S subunit of ribosomes

      Correct Answer: Inhibit RNA synthesis

      Explanation:

      Rifampicin is a derivative of a rifamycin (other derivatives are rifabutin and rifapentine). It is bactericidal against both dividing and non-dividing mycobacterium and acts by inhibiting DNA-dependent RNA polymerase. Thus this drug inhibits RNA synthesis.

    • This question is part of the following fields:

      • Pharmacology
      19.4
      Seconds
  • Question 27 - Regarding gas laws, which one best explains the ability of a Bourdon gauge...

    Correct

    • Regarding gas laws, which one best explains the ability of a Bourdon gauge to measure temperature?

      Your Answer: Charles's law

      Explanation:

      Charles’ Law states that there is a direct correlation between temperature and volume, where pressure and amount gas are constant. As temperature increases, volume also increases.

      Boyle’s Law states that Pressure is inversely proportional to volume, assuming that temperature and amount of gas are constant. As volume increases, pressure decreases. In Dalton’s law of partial pressure, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressure of the gases in mixture.

      According to Henry’s Law for concentration of dissolved gases, at a constant temperature, the amount of a given gas that dissolves in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid. An equivalent way of stating the law is that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.

      Gay-Lussac’s Law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant. This law is very similar to Charles’ Law, with the only difference being the type of container. Whereas the container in a Charles’ Law experiment is flexible, it is rigid in a Gay-Lussac’s Law experiment.

    • This question is part of the following fields:

      • Basic Physics
      52.4
      Seconds
  • Question 28 - A graph was plotted after administration of fentanyl infusion to a patient. The...

    Incorrect

    • A graph was plotted after administration of fentanyl infusion to a patient. The following are the x- and y-axis of the graph: X-axis: Dose of fentanyl, Y-axis: Mu receptor occupancy, measured using positron emission tomography. Given the data above, what would be the best representation of the graph if the data on the x-axis are converted to logarithms?

      Your Answer: Wash-out exponential curve to a straight line

      Correct Answer: Rectangular hyperbola to sigmoid curve

      Explanation:

      The dose-response curve plots the graph of the dose (drug concentration) versus the response. As doses increase, the response increment diminishes; finally, doses may be reached at which no further increase in response can be achieved. This relation between drug concentration and effect is traditionally described by a hyperbolic curve. When the x-axis is plotted in log scale, the graph yields a sigmoid curve.

      Efficacy (Emax) and potency (EC50) can be derived from this curve. Emax is the maximal effect achievable, with increasing concentration of a drug. EC50 is the concentration of the drug, wherein half of the maximal effect is achieved.

      When the graph is plotted using a log [response/1-response] against log dose, the sigmoid curve becomes a straight line (Hill plot). A graph that transforms from a straight line to exponential curve is mathematically incorrect. A graph that transforms from either a wash-in or wash-out exponential curve to a straight line comes from an initial set of data plotted against time, to a logarithmic transformation of the initial data set against time.

    • This question is part of the following fields:

      • Statistical Methods
      31.4
      Seconds
  • Question 29 - In medical testing, there are true negative, true positive, false positive and false...

    Incorrect

    • In medical testing, there are true negative, true positive, false positive and false negative results for some test. How are the sensitivity of these predictive tests calculated?

      Your Answer: True negatives / (true negatives + false positives)

      Correct Answer: True positives / (true positives + false negatives)

      Explanation:

      The following terms are used in medical testing:

      True negative – The test is negative and the patient does not have the disease.
      True positive – The test is positive and the patient has the disease.
      False positive – The test is positive but the patient does not have the disease.
      False negative – The test is negative but the patient has the disease.

      The sensitivity of a predictive test = true positives / (true positives + false negatives).

      The specificity of a test = true negatives / (false positives + true negatives).

      The negative predictive value of a test = true negatives / (false negatives + true negatives).

    • This question is part of the following fields:

      • Statistical Methods
      30.9
      Seconds
  • Question 30 - Because this benzodiazepine has a half-life of 2-4 hours, it is preferred for...

    Incorrect

    • Because this benzodiazepine has a half-life of 2-4 hours, it is preferred for clinical use. This benzodiazepine has which of the following properties that no other benzodiazepine has?

      Your Answer:

      Correct Answer: It is water soluble at a pH of 3.5 and lipid soluble at a pH of 7.4

      Explanation:

      Midazolam is the benzodiazepine in question. It’s the only benzodiazepine that undergoes tautomeric transformation (dynamic isomerism). The molecule is ionised and water soluble at pH 3.5, but when injected into the body at pH 7.4, it becomes unionised and lipid soluble, allowing it to easily pass through the blood brain barrier.

      The half-life of midazolam is only 2-4 hours.

      It is a GABAA receptor agonist because it is a benzodiazepine. GABAA receptors are found in abundance throughout the central nervous system, particularly in the cerebral cortex, hippocampus, thalamus, basal ganglia, and limbic system. GABAA receptors are ligand-gated ion channels, with the inhibitory neurotransmitter gamma-aminobutyric acid as the endogenous agonist. It is a pentameric protein (2, 2 and one subunit) that spans the cell membrane, and when the agonist interacts with the alpha subunit, a conformational change occurs, allowing chloride ions to enter the cell, resulting in neuronal hyperpolarization.

      For status epilepticus, midazolam is not the drug of choice. Lorazepam is the benzodiazepine of choice for status epilepticus.

    • This question is part of the following fields:

      • Pharmacology
      0
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SESSION STATS - PERFORMANCE PER SPECIALTY

Anatomy (3/4) 75%
Pharmacology (2/8) 25%
Anaesthesia Related Apparatus (2/2) 100%
Pathophysiology (1/3) 33%
Physiology (0/2) 0%
Clinical Measurement (3/3) 100%
Basic Physics (2/2) 100%
Statistical Methods (3/4) 75%
Physiology And Biochemistry (1/1) 100%
Passmed