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Question 1
Incorrect
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An 80-year-old woman came in with an acute myocardial infarction. The ECG revealed ST segment elevation in leads II, III, and aVF. Which coronary artery is the most probable to be blocked?
Your Answer: Left coronary artery
Correct Answer: Right coronary artery
Explanation:Localisation of Myocardial Infarction
Myocardial infarction (MI) is a medical emergency that occurs when there is a blockage in the blood flow to the heart muscle. The location of the blockage determines the type of MI and the treatment required. An inferior MI is caused by the occlusion of the right coronary artery, which supplies blood to the bottom of the heart. This type of MI can cause symptoms such as chest pain, shortness of breath, and nausea. It is important to identify the location of the MI quickly to provide appropriate treatment and prevent further damage to the heart muscle. Proper diagnosis and management can improve the patient’s chances of survival and reduce the risk of complications.
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This question is part of the following fields:
- Cardiovascular System
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Question 2
Incorrect
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A 6-year-old boy is brought to the paediatrician by his parents due to a fever and sore throat that has been bothering him for the past 24 hours. The boy is experiencing significant discomfort in his throat and has been refusing to eat or drink. He does not report having a cough or a runny nose. The boy was delivered via spontaneous vaginal delivery and has been developing normally. He has two healthy older siblings. During the examination, the doctor observes that the boy's tonsils are inflamed and enlarged, with some white exudates, as well as enlarged cervical lymph nodes. The boy's temperature is 38.2 °C. The doctor informs the parents that the boy requires antibiotics to treat the current infection and prevent the risk of a severe complication commonly associated with this particular infection. What complication can be prevented with prompt antibiotic treatment?
Your Answer: Scarlet fever
Correct Answer: Acute rheumatic fever
Explanation:Pharyngitis is the likely diagnosis for this patient based on their presenting symptoms. Group A streptococcus, also known as Streptococcus pyogenes, is a common cause of pharyngitis in young patients. One of the most concerning complications of this infection is acute rheumatic fever, which can lead to damage to the heart valves. Early antibiotic treatment can prevent the development of this serious condition.
1: Septicemia can result from various bacterial infections, but it is not typically associated with Group A streptococcal pharyngitis. Additionally, septicemia is rare in patients with this type of pharyngitis, as the condition usually resolves on its own without treatment.
2: Acute rheumatic fever is a serious complication of Group A streptococcal pharyngitis. It is an immune system reaction that damages the heart valves, particularly the mitral valve. Mitral valve regurgitation is common in the early stages of the disease, followed by mitral stenosis later on.
3: Post-streptococcal glomerulonephritis is another possible complication of Group A streptococcal pharyngitis. Unlike acute rheumatic fever, however, prompt antibiotic treatment does not prevent its development.
4: While Group A streptococcus can cause cellulitis, this is a separate condition from pharyngitis and is not a complication of the same bacterial infection.
5:
Rheumatic fever is a condition that occurs as a result of an immune response to a recent Streptococcus pyogenes infection, typically occurring 2-4 weeks after the initial infection. The pathogenesis of rheumatic fever involves the activation of the innate immune system, leading to antigen presentation to T cells. B and T cells then produce IgG and IgM antibodies, and CD4+ T cells are activated. This immune response is thought to be cross-reactive, mediated by molecular mimicry, where antibodies against M protein cross-react with myosin and the smooth muscle of arteries. This response leads to the clinical features of rheumatic fever, including Aschoff bodies, which are granulomatous nodules found in rheumatic heart fever.
To diagnose rheumatic fever, evidence of recent streptococcal infection must be present, along with 2 major criteria or 1 major criterion and 2 minor criteria. Major criteria include erythema marginatum, Sydenham’s chorea, polyarthritis, carditis and valvulitis, and subcutaneous nodules. Minor criteria include raised ESR or CRP, pyrexia, arthralgia, and prolonged PR interval.
Management of rheumatic fever involves antibiotics, typically oral penicillin V, as well as anti-inflammatories such as NSAIDs as first-line treatment. Any complications that develop, such as heart failure, should also be treated. It is important to diagnose and treat rheumatic fever promptly to prevent long-term complications such as rheumatic heart disease.
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This question is part of the following fields:
- Cardiovascular System
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Question 3
Correct
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A 65-year-old man was effectively cardioverted for an unstable broad complex tachycardia. The physician opts to initiate oral amiodarone at 200 mg thrice daily, and gradually decrease at weekly intervals until a maintenance dose of 200 mg once daily.
What is the rationale behind this dosing plan?Your Answer: Amiodarone has a very long half-life
Explanation:Amiodarone’s long half-life is due to its high lipophilicity and extensive tissue absorption, resulting in reduced bioavailability in serum. To achieve stable therapeutic levels, a prolonged loading regimen is necessary.
To quickly achieve therapeutic levels, high doses of oral amiodarone are required due to poor absorption. Once achieved, a once-daily regimen can be continued. Amiodarone’s plasma half-life ranges from 20 to 100 days, meaning its effects persist long after discontinuation. Patients should be counseled on this and advised to recognize adverse effects and avoid drugs that interact with amiodarone even after stopping it.
The statement that amiodarone has a short half-life is incorrect; it has a long half-life.
Patients do not need to stay admitted for monitoring during the loading regimen. However, thyroid and liver function tests should be performed every 6 months for up to 12 months after discontinuation due to the long half-life.
Amiodarone is excreted via the liver and biliary system, not rapidly metabolized and eliminated by the kidneys. Therefore, patients with amiodarone overdose or toxicity are not suitable for dialysis.
Amiodarone is a medication used to treat various types of abnormal heart rhythms. It works by blocking potassium channels, which prolongs the action potential and helps to regulate the heartbeat. However, it also has other effects, such as blocking sodium channels. Amiodarone has a very long half-life, which means that loading doses are often necessary. It should ideally be given into central veins to avoid thrombophlebitis. Amiodarone can cause proarrhythmic effects due to lengthening of the QT interval and can interact with other drugs commonly used at the same time. Long-term use of amiodarone can lead to various adverse effects, including thyroid dysfunction, corneal deposits, pulmonary fibrosis/pneumonitis, liver fibrosis/hepatitis, peripheral neuropathy, myopathy, photosensitivity, a ‘slate-grey’ appearance, thrombophlebitis, injection site reactions, and bradycardia. Patients taking amiodarone should be monitored regularly with tests such as TFT, LFT, U&E, and CXR.
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This question is part of the following fields:
- Cardiovascular System
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Question 4
Incorrect
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A 67-year-old woman arrives at the emergency department complaining of palpitations. Upon examination, her ECG reveals tall tented T waves. What causes the distinctive shape of the T wave, which corresponds to phase 3 of the cardiac action potential?
Your Answer: Fast depolarisation due to influx of potassium
Correct Answer: Repolarisation due to efflux of potassium
Explanation:Understanding the Cardiac Action Potential and Conduction Velocity
The cardiac action potential is a series of electrical events that occur in the heart during each heartbeat. It is responsible for the contraction of the heart muscle and the pumping of blood throughout the body. The action potential is divided into five phases, each with a specific mechanism. The first phase is rapid depolarization, which is caused by the influx of sodium ions. The second phase is early repolarization, which is caused by the efflux of potassium ions. The third phase is the plateau phase, which is caused by the slow influx of calcium ions. The fourth phase is final repolarization, which is caused by the efflux of potassium ions. The final phase is the restoration of ionic concentrations, which is achieved by the Na+/K+ ATPase pump.
Conduction velocity is the speed at which the electrical signal travels through the heart. The speed varies depending on the location of the signal. Atrial conduction spreads along ordinary atrial myocardial fibers at a speed of 1 m/sec. AV node conduction is much slower, at 0.05 m/sec. Ventricular conduction is the fastest in the heart, achieved by the large diameter of the Purkinje fibers, which can achieve velocities of 2-4 m/sec. This allows for a rapid and coordinated contraction of the ventricles, which is essential for the proper functioning of the heart. Understanding the cardiac action potential and conduction velocity is crucial for diagnosing and treating heart conditions.
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This question is part of the following fields:
- Cardiovascular System
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Question 5
Correct
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A 16-year-old competitive swimmer visits the paediatric clinic after experiencing palpitations during races or intense training. She has never had shortness of breath or chest pain, but one persistent episode led her to the emergency department where an ECG was taken. Based on the shortening of one of the ECG intervals, a provisional diagnosis of Wolff-Parkinson-White syndrome was made. What does this abnormal section of the ECG represent in terms of electrical activity?
Your Answer: The time between atrial depolarisation and ventricular depolarisation
Explanation:The PR interval on an ECG represents the duration between atrial depolarisation and ventricular depolarisation. In Wolff-Parkinson-White syndrome, an accessory pathway called the Bundle of Kent exists between the atrium and ventricle, allowing electrical signals to bypass the atrioventricular node and potentially leading to tachyarrhythmias. This results in a shorter PR interval on the ECG. Atrial repolarisation is not visible on the ECG, while the depolarisation of the sinoatrial node is represented by the p wave. The QT interval on the ECG represents the time between ventricular depolarisation and repolarisation, while the QRS complex represents ventricular depolarisation, not the PR interval.
Understanding the Normal ECG
The electrocardiogram (ECG) is a diagnostic tool used to assess the electrical activity of the heart. The normal ECG consists of several waves and intervals that represent different phases of the cardiac cycle. The P wave represents atrial depolarization, while the QRS complex represents ventricular depolarization. The ST segment represents the plateau phase of the ventricular action potential, and the T wave represents ventricular repolarization. The Q-T interval represents the time for both ventricular depolarization and repolarization to occur.
The P-R interval represents the time between the onset of atrial depolarization and the onset of ventricular depolarization. The duration of the QRS complex is normally 0.06 to 0.1 seconds, while the duration of the P wave is 0.08 to 0.1 seconds. The Q-T interval ranges from 0.2 to 0.4 seconds depending upon heart rate. At high heart rates, the Q-T interval is expressed as a ‘corrected Q-T (QTc)’ by taking the Q-T interval and dividing it by the square root of the R-R interval.
Understanding the normal ECG is important for healthcare professionals to accurately interpret ECG results and diagnose cardiac conditions. By analyzing the different waves and intervals, healthcare professionals can identify abnormalities in the electrical activity of the heart and provide appropriate treatment.
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This question is part of the following fields:
- Cardiovascular System
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Question 6
Correct
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A woman is expecting a baby with Down's syndrome. At the routine 22-week scan, a congenital anomaly was detected. The doctor explained to her and her partner that the defect resolves spontaneously in approximately 50% of cases but can present with a pansystolic murmur after birth. What is the probable congenital defect being described?
Your Answer: Ventricular septal defect
Explanation:Understanding Ventricular Septal Defect
Ventricular septal defect (VSD) is a common congenital heart disease that affects many individuals. It is caused by a hole in the wall that separates the two lower chambers of the heart. In some cases, VSDs may close on their own, but in other cases, they require specialized management.
There are various causes of VSDs, including chromosomal disorders such as Down’s syndrome, Edward’s syndrome, Patau syndrome, and cri-du-chat syndrome. Congenital infections and post-myocardial infarction can also lead to VSDs. The condition can be detected during routine scans in utero or may present post-natally with symptoms such as failure to thrive, heart failure, hepatomegaly, tachypnea, tachycardia, pallor, and a pansystolic murmur.
Management of VSDs depends on the size and symptoms of the defect. Small VSDs that are asymptomatic may require monitoring, while moderate to large VSDs may result in heart failure and require nutritional support, medication for heart failure, and surgical closure of the defect.
Complications of VSDs include aortic regurgitation, infective endocarditis, Eisenmenger’s complex, right heart failure, and pulmonary hypertension. Eisenmenger’s complex is a severe complication that results in cyanosis and clubbing and is an indication for a heart-lung transplant. Women with pulmonary hypertension are advised against pregnancy as it carries a high risk of mortality.
In conclusion, VSD is a common congenital heart disease that requires specialized management. Early detection and appropriate treatment can prevent severe complications and improve outcomes for affected individuals.
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This question is part of the following fields:
- Cardiovascular System
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Question 7
Incorrect
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A 75-year-old man with confirmed heart failure visits the GP clinic for wound dressing on his left leg. During the visit, the nurse informs the GP that she suspects the patient's legs are swollen. Upon examination, the GP observes bilateral pitting edema that extends up to the knee and decides to prescribe a diuretic. Which diuretic inhibits the sodium-potassium-chloride cotransporter?
Your Answer: Bendroflumethiazide (thiazide diuretic)
Correct Answer: Furosemide (loop diuretic)
Explanation:Loop Diuretics: Mechanism of Action and Clinical Applications
Loop diuretics, such as furosemide and bumetanide, are medications that inhibit the Na-K-Cl cotransporter (NKCC) in the thick ascending limb of the loop of Henle. By doing so, they reduce the absorption of NaCl, resulting in increased urine output. Loop diuretics act on NKCC2, which is more prevalent in the kidneys. These medications work on the apical membrane and must first be filtered into the tubules by the glomerulus before they can have an effect. Patients with poor renal function may require higher doses to ensure sufficient concentration in the tubules.
Loop diuretics are commonly used in the treatment of heart failure, both acutely (usually intravenously) and chronically (usually orally). They are also indicated for resistant hypertension, particularly in patients with renal impairment. However, loop diuretics can cause adverse effects such as hypotension, hyponatremia, hypokalemia, hypomagnesemia, hypochloremic alkalosis, ototoxicity, hypocalcemia, renal impairment, hyperglycemia (less common than with thiazides), and gout. Therefore, careful monitoring of electrolyte levels and renal function is necessary when using loop diuretics.
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This question is part of the following fields:
- Cardiovascular System
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Question 8
Correct
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A young man in his early twenties collapses during a game of basketball and is declared dead upon arrival at the hospital. The autopsy shows irregularities in his heart. What is the probable cause of the irregularities?
Your Answer: Hypertrophic cardiomyopathy
Explanation:The condition that is most commonly associated with sudden death is hypertrophic cardiomyopathy, making the other options less likely.
Symptoms of acute myocarditis may include chest pain, fever, palpitations, tachycardia, and difficulty breathing.
Dilated cardiomyopathy may cause right ventricular failure, leading to symptoms such as difficulty breathing, pulmonary edema, and atrial fibrillation.
Restrictive cardiomyopathy and constrictive pericarditis have similar presentations, with right heart failure symptoms such as elevated JVP, hepatomegaly, edema, and ascites being predominant.
Hypertrophic obstructive cardiomyopathy (HOCM) is a genetic disorder that affects muscle tissue and is inherited in an autosomal dominant manner. It is caused by mutations in genes that encode contractile proteins, with the most common defects involving the β-myosin heavy chain protein or myosin-binding protein C. HOCM is characterized by left ventricle hypertrophy, which leads to decreased compliance and cardiac output, resulting in predominantly diastolic dysfunction. Biopsy findings show myofibrillar hypertrophy with disorganized myocytes and fibrosis. HOCM is often asymptomatic, but exertional dyspnea, angina, syncope, and sudden death can occur. Jerky pulse, systolic murmurs, and double apex beat are also common features. HOCM is associated with Friedreich’s ataxia and Wolff-Parkinson White. ECG findings include left ventricular hypertrophy, non-specific ST segment and T-wave abnormalities, and deep Q waves. Atrial fibrillation may occasionally be seen.
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This question is part of the following fields:
- Cardiovascular System
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Question 9
Incorrect
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An 80-year-old man visits his GP complaining of progressive breathlessness that has been worsening over the past 6 months. During the examination, the GP observes pitting oedema in the mid-shins. The patient has a medical history of type 2 diabetes mellitus and a myocardial infarction that occurred 5 years ago. The GP orders a blood test to investigate the cause of the patient's symptoms.
The blood test reveals a B-type natriuretic peptide (BNP) level of 907 pg/mL, which is significantly higher than the normal range (< 100). Can you identify the source of BNP secretion?Your Answer: Pulmonary artery endothelium
Correct Answer: Ventricular myocardium
Explanation:BNP is primarily secreted by the ventricular myocardium in response to stretching, making it a valuable indicator of heart failure. While it can be used for screening and prognostic scoring, it is not secreted by the atrial endocardium, distal convoluted tubule, pulmonary artery endothelium, or renal mesangial cells.
B-type natriuretic peptide (BNP) is a hormone that is primarily produced by the left ventricular myocardium in response to strain. Although heart failure is the most common cause of elevated BNP levels, any condition that causes left ventricular dysfunction, such as myocardial ischemia or valvular disease, may also raise levels. In patients with chronic kidney disease, reduced excretion may also lead to elevated BNP levels. Conversely, treatment with ACE inhibitors, angiotensin-2 receptor blockers, and diuretics can lower BNP levels.
BNP has several effects, including vasodilation, diuresis, natriuresis, and suppression of both sympathetic tone and the renin-angiotensin-aldosterone system. Clinically, BNP is useful in diagnosing patients with acute dyspnea. A low concentration of BNP (<100 pg/mL) makes a diagnosis of heart failure unlikely, but elevated levels should prompt further investigation to confirm the diagnosis. Currently, NICE recommends BNP as a helpful test to rule out a diagnosis of heart failure. In patients with chronic heart failure, initial evidence suggests that BNP is an extremely useful marker of prognosis and can guide treatment. However, BNP is not currently recommended for population screening for cardiac dysfunction.
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This question is part of the following fields:
- Cardiovascular System
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Question 10
Incorrect
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A 72-year-old man visits the clinic with complaints of palpitations and dizziness that started a day ago. He has been experiencing weakness and fatigue for the past month. During the physical examination, you observe generalized hypotonia and hyporeflexia. After conducting an ECG, you notice indications of hypokalemia. What is an ECG manifestation of hypokalemia?
Your Answer: Tall tented T waves
Correct Answer: Prominent U waves
Explanation:Hypokalaemia can be identified by the presence of U waves on an ECG. Other ECG signs of hypokalaemia include small or absent P waves, tall tented T waves, and broad bizarre QRS complexes. On the other hand, hyperkalaemia can be identified by ECG signs such as a long PR interval and a sine wave pattern, as well as small or absent P waves, tall tented T waves, and broad bizarre QRS complexes. A prolonged PR interval may be found in both hypokalaemia and hyperkalaemia, while a short PR interval suggests pre-excitation or an AV nodal rhythm. Abnormalities in serum potassium are often discovered incidentally, but symptoms of hypokalaemia include fatigue, muscle weakness, myalgia, muscle cramps, constipation, hyporeflexia, and rarely paralysis. If a patient presents with palpitations and light-headedness, along with a history of weakness and fatigue, and examination findings of hypotonia and hyporeflexia, hypokalaemia should be considered as a possible cause.
Hypokalaemia, a condition characterized by low levels of potassium in the blood, can be detected through ECG features. These include the presence of U waves, small or absent T waves (which may occasionally be inverted), a prolonged PR interval, ST depression, and a long QT interval. The ECG image provided shows typical U waves and a borderline PR interval. To remember these features, one user suggests the following rhyme: In Hypokalaemia, U have no Pot and no T, but a long PR and a long QT.
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This question is part of the following fields:
- Cardiovascular System
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Question 11
Incorrect
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These thyroid function tests were obtained on a 55-year-old female who has recently been treated for hypertension:
Free T4 28.5 pmol/L (9.8-23.1)
TSH <0.02 mU/L (0.35-5.5)
Free T3 10.8 pmol/L (3.5-6.5)
She now presents with typical symptoms of hyperthyroidism.
Which medication is likely to have caused this?Your Answer: Amlodipine
Correct Answer: Amiodarone
Explanation:Amiodarone and its Effects on Thyroid Function
Amiodarone is a medication that can have an impact on thyroid function, resulting in both hypo- and hyperthyroidism. This is due to the high iodine content in the drug, which contributes to its antiarrhythmic effects. Atenolol, on the other hand, is a beta blocker that is commonly used to treat thyrotoxicosis. Warfarin is another medication that is used to treat atrial fibrillation.
There are two types of thyrotoxicosis that can be caused by amiodarone. Type 1 results in excess thyroxine synthesis, while type 2 leads to the release of excess thyroxine but normal levels of synthesis. It is important for healthcare professionals to monitor thyroid function in patients taking amiodarone and adjust treatment as necessary to prevent complications.
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This question is part of the following fields:
- Cardiovascular System
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Question 12
Incorrect
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A 25-year-old man is scheduled for cardiac catheterisation to repair a possible atrial septal defect. What is the typical oxygen saturation level in the right atrium for a person in good health?
Your Answer: 50%
Correct Answer: 70%
Explanation:Understanding Oxygen Saturation Levels in Cardiac Catheterisation
Cardiac catheterisation and oxygen saturation levels can be confusing, but with a few basic rules and logical deduction, it can be easily understood. Deoxygenated blood returns to the right side of the heart through the superior and inferior vena cava with an oxygen saturation level of around 70%. The right atrium, right ventricle, and pulmonary artery also have oxygen saturation levels of around 70%. The lungs oxygenate the blood to a level of around 98-100%, resulting in the left atrium, left ventricle, and aorta having oxygen saturation levels of 98-100%.
Different scenarios can affect oxygen saturation levels. For instance, in an atrial septal defect (ASD), the oxygenated blood in the left atrium mixes with the deoxygenated blood in the right atrium, resulting in intermediate levels of oxygenation from the right atrium onwards. In a ventricular septal defect (VSD), the oxygenated blood in the left ventricle mixes with the deoxygenated blood in the right ventricle, resulting in intermediate levels of oxygenation from the right ventricle onwards. In a patent ductus arteriosus (PDA), the higher pressure aorta connects with the lower pressure pulmonary artery, resulting in only the pulmonary artery having intermediate oxygenation levels.
Understanding the expected oxygen saturation levels in different scenarios can help in diagnosing and treating cardiac conditions. The table above shows the oxygen saturation levels that would be expected in different diagnoses, including VSD with Eisenmenger’s and ASD with Eisenmenger’s. By understanding these levels, healthcare professionals can provide better care for their patients.
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This question is part of the following fields:
- Cardiovascular System
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Question 13
Correct
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An 68-year-old patient visits the GP complaining of a cough that produces green sputum, fever and shortness of breath. After being treated with antibiotics, her symptoms improve. However, three weeks later, she experiences painful joints, chest pain, fever and an erythema marginatum rash. What is the probable causative organism responsible for the initial infection?
Your Answer: Streptococcus pyogenes
Explanation:An immunological reaction is responsible for the development of rheumatic fever.
Rheumatic fever is a condition that occurs as a result of an immune response to a recent Streptococcus pyogenes infection, typically occurring 2-4 weeks after the initial infection. The pathogenesis of rheumatic fever involves the activation of the innate immune system, leading to antigen presentation to T cells. B and T cells then produce IgG and IgM antibodies, and CD4+ T cells are activated. This immune response is thought to be cross-reactive, mediated by molecular mimicry, where antibodies against M protein cross-react with myosin and the smooth muscle of arteries. This response leads to the clinical features of rheumatic fever, including Aschoff bodies, which are granulomatous nodules found in rheumatic heart fever.
To diagnose rheumatic fever, evidence of recent streptococcal infection must be present, along with 2 major criteria or 1 major criterion and 2 minor criteria. Major criteria include erythema marginatum, Sydenham’s chorea, polyarthritis, carditis and valvulitis, and subcutaneous nodules. Minor criteria include raised ESR or CRP, pyrexia, arthralgia, and prolonged PR interval.
Management of rheumatic fever involves antibiotics, typically oral penicillin V, as well as anti-inflammatories such as NSAIDs as first-line treatment. Any complications that develop, such as heart failure, should also be treated. It is important to diagnose and treat rheumatic fever promptly to prevent long-term complications such as rheumatic heart disease.
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This question is part of the following fields:
- Cardiovascular System
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Question 14
Incorrect
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A 54-year-old man visits his GP for a routine check-up and physical examination. He has a medical history of hypertension and asthma but currently has no immediate concerns. He reports feeling healthy.
During the examination, the man appears to be in good health, with normal vital signs except for a high blood pressure reading of 160/90 mmHg. While listening to his heart, the GP detects an S4 heart sound and orders an ECG.
Which segment of the ECG corresponds to the S4 heart sound?Your Answer: U wave
Correct Answer: P wave
Explanation:The S4 heart sound coincides with the P wave on an ECG. This is because the S4 sound is caused by the contraction of the atria against a stiff ventricle, which occurs just before the S1 sound. It is commonly heard in conditions such as aortic stenosis, hypertrophic cardiomyopathy, or hypertension. As the P wave represents atrial depolarization, it is the ECG wave that coincides with the S4 heart sound.
It is important to note that the QRS complex, which represents ventricular depolarization, is not associated with the S4 heart sound. Similarly, the ST segment, which is the interval between ventricular depolarization and repolarization, and T waves, which indicate ventricular repolarization, are not linked to the S4 heart sound.
Heart sounds are the sounds produced by the heart during its normal functioning. The first heart sound (S1) is caused by the closure of the mitral and tricuspid valves, while the second heart sound (S2) is due to the closure of the aortic and pulmonary valves. The intensity of these sounds can vary depending on the condition of the valves and the heart. The third heart sound (S3) is caused by the diastolic filling of the ventricle and is considered normal in young individuals. However, it may indicate left ventricular failure, constrictive pericarditis, or mitral regurgitation in older individuals. The fourth heart sound (S4) may be heard in conditions such as aortic stenosis, HOCM, and hypertension, and is caused by atrial contraction against a stiff ventricle. The different valves can be best heard at specific sites on the chest wall, such as the left second intercostal space for the pulmonary valve and the right second intercostal space for the aortic valve.
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This question is part of the following fields:
- Cardiovascular System
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Question 15
Correct
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A 50-year-old male is diagnosed with hypertension with a blood pressure reading of 180/100 mmHg during ambulatory blood pressure monitoring. The physician prescribes Ramipril, an ACE inhibitor. What is the most frequent adverse effect associated with this medication?
Your Answer: A dry cough
Explanation:Hypotension, particularly on the first dose, and deterioration of renal function are common side effects of ACE inhibitors in patients. Although angioedema is a rare side effect of ACE inhibitors, oedema is typically associated with calcium channel blockers. Diuretics may cause excessive urine output, while shortness of breath and headaches are uncommon.
Angiotensin-converting enzyme (ACE) inhibitors are commonly used as the first-line treatment for hypertension and heart failure in younger patients. However, they may not be as effective in treating hypertensive Afro-Caribbean patients. ACE inhibitors are also used to treat diabetic nephropathy and prevent ischaemic heart disease. These drugs work by inhibiting the conversion of angiotensin I to angiotensin II and are metabolized in the liver.
While ACE inhibitors are generally well-tolerated, they can cause side effects such as cough, angioedema, hyperkalaemia, and first-dose hypotension. Patients with certain conditions, such as renovascular disease, aortic stenosis, or hereditary or idiopathic angioedema, should use ACE inhibitors with caution or avoid them altogether. Pregnant and breastfeeding women should also avoid these drugs.
Patients taking high-dose diuretics may be at increased risk of hypotension when using ACE inhibitors. Therefore, it is important to monitor urea and electrolyte levels before and after starting treatment, as well as any changes in creatinine and potassium levels. Acceptable changes include a 30% increase in serum creatinine from baseline and an increase in potassium up to 5.5 mmol/l. Patients with undiagnosed bilateral renal artery stenosis may experience significant renal impairment when using ACE inhibitors.
The current NICE guidelines recommend using a flow chart to manage hypertension, with ACE inhibitors as the first-line treatment for patients under 55 years old. However, individual patient factors and comorbidities should be taken into account when deciding on the best treatment plan.
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This question is part of the following fields:
- Cardiovascular System
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Question 16
Correct
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As a junior doctor, you are taking the medical history of a patient who is scheduled for an elective knee replacement. During the physical examination, you hear a diastolic murmur and observe a collapsing pulse while checking the heart rate. Upon examining the hands, you notice pulsations of red coloration on the nail beds. Other than these findings, the examination appears normal.
What could be the probable reason behind these examination results if the patient is slightly older?Your Answer: Aortic regurgitation
Explanation:The patient’s examination findings suggest aortic regurgitation, which is characterized by an early diastolic, high-pitched, blowing murmur that is louder when the patient sits forward and at the left sternal edge. Aortic regurgitation can also cause a collapsing pulse, dyspnoea, orthopnoea, paroxysmal nocturnal dyspnoea, and visible pulsing red colouration of the nails (quincke’s sign).
It is important to note that aortic stenosis does not cause a diastolic murmur or collapsing pulse. Instead, it typically produces an ejection systolic murmur that is louder on expiration and may cause a slow rising pulse.
Similarly, mitral regurgitation does not cause a diastolic murmur or collapsing pulse. It typically produces a pansystolic murmur.
Mitral stenosis causes a mid-late diastolic murmur but does not commonly cause a collapsing pulse.
Pulmonary stenosis causes an ejection systolic murmur but does not commonly cause a collapsing pulse or diastolic murmur.
Aortic regurgitation is a condition where the aortic valve of the heart leaks, causing blood to flow in the opposite direction during ventricular diastole. This can be caused by disease of the aortic valve or by distortion or dilation of the aortic root and ascending aorta. The most common causes of AR due to valve disease include rheumatic fever, calcific valve disease, and infective endocarditis. On the other hand, AR due to aortic root disease can be caused by conditions such as aortic dissection, hypertension, and connective tissue diseases like Marfan’s and Ehler-Danlos syndrome.
The features of AR include an early diastolic murmur, a collapsing pulse, wide pulse pressure, Quincke’s sign, and De Musset’s sign. In severe cases, a mid-diastolic Austin-Flint murmur may also be present. Suspected AR should be investigated with echocardiography.
Management of AR involves medical management of any associated heart failure and surgery in symptomatic patients with severe AR or asymptomatic patients with severe AR who have LV systolic dysfunction.
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This question is part of the following fields:
- Cardiovascular System
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Question 17
Incorrect
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A 72-year-old male with urinary incontinence visits the urogynaecology clinic and is diagnosed with overactive bladder incontinence. He is prescribed a medication that works by blocking the parasympathetic pathway. What other drugs have a similar mechanism of action to the one he was prescribed?
Your Answer: Alfuzosin
Correct Answer: Atropine
Explanation:Atropine is classified as an antimuscarinic drug that works by inhibiting the M1 to M5 muscarinic receptors. While oxybutynin is commonly prescribed for urinary incontinence due to its ability to block the M3 muscarinic receptors, atropine is more frequently used in anesthesia to reduce salivation before intubation.
Alfuzosin, on the other hand, is an alpha blocker that is primarily used to treat benign prostate hyperplasia.
Meropenem is an antibiotic that is reserved for infections caused by bacteria that are resistant to most beta-lactams. However, it is typically used as a last resort due to its potential adverse effects.
Mirabegron is another medication used to treat urinary incontinence, but it works by activating the β3 adrenergic receptors.
Understanding Atropine and Its Uses
Atropine is a medication that works against the muscarinic acetylcholine receptor. It is commonly used to treat symptomatic bradycardia and organophosphate poisoning. In cases of bradycardia with adverse signs, IV atropine is the first-line treatment. However, it is no longer recommended for routine use in asystole or pulseless electrical activity (PEA) during advanced life support.
Atropine has several physiological effects, including tachycardia and mydriasis. However, it is important to note that it may trigger acute angle-closure glaucoma in susceptible patients. Therefore, it is crucial to use atropine with caution and under the guidance of a healthcare professional. Understanding the uses and effects of atropine can help individuals make informed decisions about their healthcare.
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This question is part of the following fields:
- Cardiovascular System
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Question 18
Incorrect
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Electrophysiology studies are being conducted in a young boy with suspected Wolff-Parkinson-White syndrome, who has experienced recurrent episodes of sudden palpitations. The procedure involves catheterization within the heart to evaluate the electrical activity and determine the conduction velocity of various parts of the conduction pathway.
Which segment of this pathway exhibits the highest conduction velocity?Your Answer: Atrioventricular node
Correct Answer: Purkinje fibres
Explanation:The Purkinje fibres have the fastest conduction velocities in the heart, at approximately 4m/sec, due to different connexins in their gap junctions. They allow depolarisation throughout the ventricular muscle. Atrial muscle conducts at around 0.5m/sec, the atrioventricular node conducts at a slow rate, and the Bundle of His conducts at 2m/sec, but not as rapidly as the Purkinje fibres.
Understanding the Cardiac Action Potential and Conduction Velocity
The cardiac action potential is a series of electrical events that occur in the heart during each heartbeat. It is responsible for the contraction of the heart muscle and the pumping of blood throughout the body. The action potential is divided into five phases, each with a specific mechanism. The first phase is rapid depolarization, which is caused by the influx of sodium ions. The second phase is early repolarization, which is caused by the efflux of potassium ions. The third phase is the plateau phase, which is caused by the slow influx of calcium ions. The fourth phase is final repolarization, which is caused by the efflux of potassium ions. The final phase is the restoration of ionic concentrations, which is achieved by the Na+/K+ ATPase pump.
Conduction velocity is the speed at which the electrical signal travels through the heart. The speed varies depending on the location of the signal. Atrial conduction spreads along ordinary atrial myocardial fibers at a speed of 1 m/sec. AV node conduction is much slower, at 0.05 m/sec. Ventricular conduction is the fastest in the heart, achieved by the large diameter of the Purkinje fibers, which can achieve velocities of 2-4 m/sec. This allows for a rapid and coordinated contraction of the ventricles, which is essential for the proper functioning of the heart. Understanding the cardiac action potential and conduction velocity is crucial for diagnosing and treating heart conditions.
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This question is part of the following fields:
- Cardiovascular System
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Question 19
Incorrect
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Which one of the following is not considered a major branch of the ascending thoracic aorta?
Your Answer: Oesophageal artery
Correct Answer: Inferior thyroid artery
Explanation:The thyrocervical trunk, which is a branch of the subclavian artery, is typically the source of the inferior thyroid artery.
Anatomy of the Thoracic Aorta
The thoracic aorta is a major blood vessel that originates from the fourth thoracic vertebrae and terminates at the twelfth thoracic vertebrae. It is located in the chest cavity and has several important relations with surrounding structures. Anteriorly, it is related to the root of the left lung, the pericardium, the oesophagus, and the diaphragm. Posteriorly, it is related to the vertebral column and the azygos vein. On the right side, it is related to the hemiazygos veins and the thoracic duct, while on the left side, it is related to the left pleura and lung.
The thoracic aorta has several branches that supply blood to different parts of the body. The lateral segmental branches are the posterior intercostal arteries, which supply blood to the muscles and skin of the back. The lateral visceral branches are the bronchial arteries, which supply blood to the bronchial walls and lung, excluding the alveoli. The midline branches are the oesophageal arteries, which supply blood to the oesophagus.
In summary, the thoracic aorta is an important blood vessel that supplies blood to various structures in the chest cavity. Its anatomy and relations with surrounding structures are crucial for understanding its function and potential clinical implications.
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This question is part of the following fields:
- Cardiovascular System
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Question 20
Incorrect
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A 22-year-old male arrives at the emergency department complaining of palpitations and feeling lightheaded. The electrocardiogram reveals supraventricular tachycardia, and the registrar administers adenosine to try and correct the abnormal rhythm.
What is the mechanism of action of adenosine?Your Answer: Beta-2 receptor agonist
Correct Answer: A1 receptor agonist
Explanation:Adenosine is an agonist of the A1 receptor in the AV node, which inhibits adenylyl cyclase and reduces cAMP levels. This leads to hyperpolarisation by increasing potassium outflow, effectively preventing supraventricular tachycardia from continuing. It is important to note that adenosine is not an alpha receptor antagonist, beta-2 receptor agonist, or beta receptor antagonist.
Adenosine is commonly used to stop supraventricular tachycardias. Its effects are boosted by dipyridamole, an antiplatelet agent, but blocked by theophyllines. However, asthmatics should avoid it due to the risk of bronchospasm. Adenosine works by causing a temporary heart block in the AV node. It activates the A1 receptor in the atrioventricular node, which inhibits adenylyl cyclase, reducing cAMP and causing hyperpolarization by increasing outward potassium flux. Adenosine has a very short half-life of about 8-10 seconds and should be infused through a large-caliber cannula.
Adenosine can cause chest pain, bronchospasm, and transient flushing. It can also enhance conduction down accessory pathways, leading to an increased ventricular rate in conditions such as WPW syndrome.
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This question is part of the following fields:
- Cardiovascular System
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Question 21
Correct
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Ella, a 69-year-old female, arrives at the emergency department with abrupt tearing abdominal pain that radiates to her back.
Ella has a medical history of hypertension, hypercholesterolemia, and diabetes. Her body mass index is 31 kg/m². She smokes 10 cigarettes a day.
The emergency physician orders an ECG and MRI, which confirm the diagnosis of an aortic dissection.
Which layer or layers of the aorta are impacted?Your Answer: Tear in tunica intima
Explanation:An aortic dissection occurs when there is a tear in the innermost layer (tunica intima) of the aorta’s wall. This tear allows blood to flow into the space between the tunica intima and the middle layer (tunica media), causing pooling. The tear only affects the tunica intima layer and does not involve the outermost layer (tunica externa) or all three layers of the aortic wall.
Aortic dissection is a serious condition that can cause chest pain. It occurs when there is a tear in the inner layer of the aorta’s wall. Hypertension is the most significant risk factor, but it can also be associated with trauma, bicuspid aortic valve, and certain genetic disorders. Symptoms of aortic dissection include severe and sharp chest or back pain, weak or absent pulses, hypertension, and aortic regurgitation. Specific arteries’ involvement can cause other symptoms such as angina, paraplegia, or limb ischemia. The Stanford classification divides aortic dissection into type A, which affects the ascending aorta, and type B, which affects the descending aorta. The DeBakey classification further divides type A into type I, which extends to the aortic arch and beyond, and type II, which is confined to the ascending aorta. Type III originates in the descending aorta and rarely extends proximally.
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This question is part of the following fields:
- Cardiovascular System
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Question 22
Correct
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A 78-year-old woman has recently been diagnosed with heart failure following 10 months of progressive breathlessness and swelling in her ankles. She has been prescribed several medications and provided with lifestyle recommendations. What are the two types of infections that she is most susceptible to due to her recent diagnosis?
Your Answer: Chest infections and ulcerated cellulitic legs
Explanation:As a result of the volume overload caused by heart failure, she will have a higher susceptibility to chest infections due to pulmonary edema and leg infections due to peripheral edema.
Chronic heart failure can be managed through drug treatment, according to updated guidelines issued by NICE in 2018. While loop diuretics are useful in managing fluid overload, they do not reduce mortality in the long term. The first-line treatment for all patients is a combination of an ACE-inhibitor and a beta-blocker, with clinical judgement used to determine which one to start first. Aldosterone antagonists are recommended as second-line treatment, but potassium levels should be monitored as both ACE inhibitors and aldosterone antagonists can cause hyperkalaemia. Third-line treatment should be initiated by a specialist and may include ivabradine, sacubitril-valsartan, hydralazine in combination with nitrate, digoxin, and cardiac resynchronisation therapy. Other treatments include annual influenzae and one-off pneumococcal vaccines. Those with asplenia, splenic dysfunction, or chronic kidney disease may require a booster every 5 years.
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This question is part of the following fields:
- Cardiovascular System
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Question 23
Correct
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A 65-year-old male comes to the GP complaining of mild chest pain and dyspnoea. The patient has no significant medical history but has a family history of heart disease, with his father passing away following a heart attack last year. The GP suspects atrial flutter and decides to perform an ECG to confirm the diagnosis. What ECG findings would you anticipate given the diagnosis?
Your Answer: Narrow complex tachycardia
Explanation:Atrial flutter is characterized by a sawtooth pattern on ECG and typically presents as a narrow complex tachycardia. The regular atrial activity in atrial flutter is typically 300 bpm, and the ventricular rate is a fraction of this. For example, a 2:1 block would result in a ventricular rate of 150/min, a 3:1 block would result in a ventricular rate of 100/min, and a 4:1 block would result in a ventricular rate of 75/min.
Atrial flutter is a type of supraventricular tachycardia that is characterized by a series of rapid atrial depolarization waves. This condition can be identified through ECG findings, which show a sawtooth appearance. The underlying atrial rate is typically around 300 beats per minute, which can affect the ventricular or heart rate depending on the degree of AV block. For instance, if there is a 2:1 block, the ventricular rate will be 150 beats per minute. Flutter waves may also be visible following carotid sinus massage or adenosine.
Managing atrial flutter is similar to managing atrial fibrillation, although medication may be less effective. However, atrial flutter is more sensitive to cardioversion, so lower energy levels may be used. For most patients, radiofrequency ablation of the tricuspid valve isthmus is curative.
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This question is part of the following fields:
- Cardiovascular System
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Question 24
Incorrect
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A man in his 50s arrives at the emergency department exhibiting signs of a stroke. After undergoing a CT angiogram, it is revealed that there is a constriction in the artery that provides blood to the right common carotid.
What is the name of the affected artery?Your Answer: Aortic arch
Correct Answer: Brachiocephalic artery
Explanation:The largest branch from the aortic arch is the brachiocephalic artery, which originates from it. This artery gives rise to both the right subclavian artery and the right common carotid arteries. The brachiocephalic artery is supplied by the aortic arch, while the coronary arteries are supplied by the ascending aorta. Additionally, the coeliac trunk is a branch that stems from the abdominal aorta.
The Brachiocephalic Artery: Anatomy and Relations
The brachiocephalic artery is the largest branch of the aortic arch, originating at the apex of the midline. It ascends superiorly and posteriorly to the right, lying initially anterior to the trachea and then on its right-hand side. At the level of the sternoclavicular joint, it divides into the right subclavian and right common carotid arteries.
In terms of its relations, the brachiocephalic artery is anterior to the sternohyoid, sterno-thyroid, thymic remnants, left brachiocephalic vein, and right inferior thyroid veins. Posteriorly, it is related to the trachea, right pleura, right lateral, right brachiocephalic vein, superior part of the SVC, left lateral, thymic remnants, origin of left common carotid, inferior thyroid veins, and trachea at a higher level.
The brachiocephalic artery typically has no branches, but it may have the thyroidea ima artery. Understanding the anatomy and relations of the brachiocephalic artery is important for medical professionals, as it is a crucial vessel in the human body.
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This question is part of the following fields:
- Cardiovascular System
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Question 25
Correct
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A 50-year-old UK born patient with end-stage kidney failure arrives at the emergency department complaining of sharp chest pain that subsides when sitting forward. The patient has not undergone dialysis yet. Upon conducting an ECG, it is observed that there is a widespread 'saddle-shaped' ST elevation and PR depression, leading to a diagnosis of pericarditis. What could be the probable cause of this pericarditis?
Your Answer: Uraemia
Explanation:There is no indication of trauma in patients with advanced renal failure prior to dialysis initiation.
ECG results do not indicate a recent heart attack.
The patient’s age decreases the likelihood of malignancy.
Acute Pericarditis: Causes, Features, Investigations, and Management
Acute pericarditis is a possible diagnosis for patients presenting with chest pain. The condition is characterized by chest pain, which may be pleuritic and relieved by sitting forwards. Other symptoms include non-productive cough, dyspnoea, and flu-like symptoms. Tachypnoea and tachycardia may also be present, along with a pericardial rub.
The causes of acute pericarditis include viral infections, tuberculosis, uraemia, trauma, post-myocardial infarction, Dressler’s syndrome, connective tissue disease, hypothyroidism, and malignancy.
Investigations for acute pericarditis include ECG changes, which are often global/widespread, as opposed to the ‘territories’ seen in ischaemic events. The ECG may show ‘saddle-shaped’ ST elevation and PR depression, which is the most specific ECG marker for pericarditis. All patients with suspected acute pericarditis should have transthoracic echocardiography.
Management of acute pericarditis involves treating the underlying cause. A combination of NSAIDs and colchicine is now generally used as first-line treatment for patients with acute idiopathic or viral pericarditis.
In summary, acute pericarditis is a possible diagnosis for patients presenting with chest pain. The condition is characterized by chest pain, which may be pleuritic and relieved by sitting forwards, along with other symptoms. The causes of acute pericarditis are varied, and investigations include ECG changes and transthoracic echocardiography. Management involves treating the underlying cause and using a combination of NSAIDs and colchicine as first-line treatment.
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This question is part of the following fields:
- Cardiovascular System
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Question 26
Incorrect
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A 65-year-old woman experiences chest discomfort during physical activity and is diagnosed with angina.
What alterations are expected to be observed in her arteries?Your Answer: Proliferation of monocytes leading to increased inflammation
Correct Answer: Smooth muscle proliferation and migration from the tunica media to the intima
Explanation:The final stage in the development of an atheroma involves the proliferation and migration of smooth muscle from the tunica media into the intima. While monocytes do migrate, they differentiate into macrophages which then phagocytose LDLs and form foam cells. Additionally, there is infiltration of LDLs. The formation of fibrous capsules is a result of the smooth muscle proliferation and migration. Atherosclerosis is also associated with a reduction in nitric oxide availability.
Understanding Atherosclerosis and its Complications
Atherosclerosis is a complex process that occurs over several years. It begins with endothelial dysfunction triggered by factors such as smoking, hypertension, and hyperglycemia. This leads to changes in the endothelium, including inflammation, oxidation, proliferation, and reduced nitric oxide bioavailability. As a result, low-density lipoprotein (LDL) particles infiltrate the subendothelial space, and monocytes migrate from the blood and differentiate into macrophages. These macrophages then phagocytose oxidized LDL, slowly turning into large ‘foam cells’. Smooth muscle proliferation and migration from the tunica media into the intima result in the formation of a fibrous capsule covering the fatty plaque.
Once a plaque has formed, it can cause several complications. For example, it can form a physical blockage in the lumen of the coronary artery, leading to reduced blood flow and oxygen to the myocardium, resulting in angina. Alternatively, the plaque may rupture, potentially causing a complete occlusion of the coronary artery and resulting in a myocardial infarction. It is essential to understand the process of atherosclerosis and its complications to prevent and manage cardiovascular diseases effectively.
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This question is part of the following fields:
- Cardiovascular System
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Question 27
Correct
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A woman visits her physician and undergoes lying and standing blood pressure tests. Upon standing, her baroreceptors sense reduced stretch, triggering the baroreceptor reflex. This results in a decrease in baroreceptor activity, leading to an elevation in sympathetic discharge.
What is the function of the neurotransmitter that is released?Your Answer: Noradrenaline binds to β 1 receptors in the SA node increasing depolarisation
Explanation:The binding of noradrenaline to β 1 receptors in the SA node is responsible for an increase in heart rate due to an increase in depolarisation in the pacemaker action potential, allowing for more frequent firing of action potentials. As the SA node is the pacemaker in a healthy individual, the predominant β receptor found in the heart, β 1, is the one that noradrenaline acts on more than β 2 and α 2 receptors. Therefore, the correct answer is that noradrenaline binds to β 1 receptors in the SA node.
The heart has four chambers and generates pressures of 0-25 mmHg on the right side and 0-120 mmHg on the left. The cardiac output is the product of heart rate and stroke volume, typically 5-6L per minute. The cardiac impulse is generated in the sino atrial node and conveyed to the ventricles via the atrioventricular node. Parasympathetic and sympathetic fibers project to the heart via the vagus and release acetylcholine and noradrenaline, respectively. The cardiac cycle includes mid diastole, late diastole, early systole, late systole, and early diastole. Preload is the end diastolic volume and afterload is the aortic pressure. Laplace’s law explains the rise in ventricular pressure during the ejection phase and why a dilated diseased heart will have impaired systolic function. Starling’s law states that an increase in end-diastolic volume will produce a larger stroke volume up to a point beyond which stroke volume will fall. Baroreceptor reflexes and atrial stretch receptors are involved in regulating cardiac output.
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This question is part of the following fields:
- Cardiovascular System
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Question 28
Incorrect
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A 25-year-old man has been diagnosed with an abnormal electrical connection in his heart, resulting in frequent palpitations, dizzy spells, and shortness of breath. Delta waves are also evident on his ECG. Would ablation of the coronary sinus be a viable treatment option for this condition?
From which embryological structure is the target for this surgery derived?Your Answer: Ductus arteriosus
Correct Answer: Left horn of the sinus venosus
Explanation:The sinus venosus has two horns, left and right. The left horn gives rise to the coronary sinus, while the right horn forms the smooth part of the right atrium. In patients with Wolff-Parkinson-White syndrome, an abnormal conduction pathway exists in the heart. To eliminate this pathway, a treatment called ablation of the coronary sinus is used. This involves destroying the conducting pathway that runs through the coronary sinus, which is formed from the left horn of the sinus venosus during embryonic development.
During cardiovascular embryology, the heart undergoes significant development and differentiation. At around 14 days gestation, the heart consists of primitive structures such as the truncus arteriosus, bulbus cordis, primitive atria, and primitive ventricle. These structures give rise to various parts of the heart, including the ascending aorta and pulmonary trunk, right ventricle, left and right atria, and majority of the left ventricle. The division of the truncus arteriosus is triggered by neural crest cell migration from the pharyngeal arches, and any issues with this migration can lead to congenital heart defects such as transposition of the great arteries or tetralogy of Fallot. Other structures derived from the primitive heart include the coronary sinus, superior vena cava, fossa ovalis, and various ligaments such as the ligamentum arteriosum and ligamentum venosum. The allantois gives rise to the urachus, while the umbilical artery becomes the medial umbilical ligaments and the umbilical vein becomes the ligamentum teres hepatis inside the falciform ligament. Overall, cardiovascular embryology is a complex process that involves the differentiation and development of various structures that ultimately form the mature heart.
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This question is part of the following fields:
- Cardiovascular System
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Question 29
Correct
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A 65-year-old male with chronic cardiac failure visits his doctor and reports experiencing dyspnoea even with minimal physical exertion, and only feeling comfortable when at rest. What class of the New York Heart Association scale does he fall under?
Your Answer: III
Explanation:The NYHA Scale for Cardiac Failure Patients
The NYHA scale is a tool used to standardize the description of the severity of cardiac failure patients. It classifies patients into four categories based on their symptoms and limitations of activities. Class I patients have no limitations and do not experience any symptoms during ordinary activities. Class II patients have mild limitations and are comfortable with rest or mild exertion. Class III patients have marked limitations and are only comfortable at rest. Finally, Class IV patients should be at complete rest and are confined to bed or chair. Any physical activity brings discomfort and symptoms occur even at rest.
The NYHA scale is an important tool for healthcare professionals to assess the severity of cardiac failure in patients. It helps to determine the appropriate treatment plan and level of care needed for each patient. By using this scale, healthcare professionals can communicate more effectively with each other and with patients about the severity of their condition. It also helps patients to understand their limitations and adjust their activities accordingly. Overall, the NYHA scale is a valuable tool in the management of cardiac failure patients.
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This question is part of the following fields:
- Cardiovascular System
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Question 30
Correct
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You are requested to assess a patient in the emergency department who has experienced abrupt onset chest pain, dyspnoea and diaphoresis. After reviewing the patient's ECG, you identify changes within a specific section and promptly arrange for transfer to the catheterisation laboratory.
What is the underlying process indicated by the affected section of the ECG?Your Answer: Period between ventricular depolarisation and repolarisation
Explanation:The ST segment on an ECG indicates the period when the entire ventricle is depolarized. In the case of a suspected myocardial infarction, it is crucial to examine the ST segment for any elevation or depression, which can indicate a STEMI or NSTEMI, respectively.
The ECG does not have a specific section that corresponds to the firing of the sino-atrial node, which triggers atrial depolarization (represented by the p wave). The T wave represents ventricular repolarization.
In atrial fibrillation, the p wave is absent or abnormal due to the irregular firing of the atria.
Understanding the Normal ECG
The electrocardiogram (ECG) is a diagnostic tool used to assess the electrical activity of the heart. The normal ECG consists of several waves and intervals that represent different phases of the cardiac cycle. The P wave represents atrial depolarization, while the QRS complex represents ventricular depolarization. The ST segment represents the plateau phase of the ventricular action potential, and the T wave represents ventricular repolarization. The Q-T interval represents the time for both ventricular depolarization and repolarization to occur.
The P-R interval represents the time between the onset of atrial depolarization and the onset of ventricular depolarization. The duration of the QRS complex is normally 0.06 to 0.1 seconds, while the duration of the P wave is 0.08 to 0.1 seconds. The Q-T interval ranges from 0.2 to 0.4 seconds depending upon heart rate. At high heart rates, the Q-T interval is expressed as a ‘corrected Q-T (QTc)’ by taking the Q-T interval and dividing it by the square root of the R-R interval.
Understanding the normal ECG is important for healthcare professionals to accurately interpret ECG results and diagnose cardiac conditions. By analyzing the different waves and intervals, healthcare professionals can identify abnormalities in the electrical activity of the heart and provide appropriate treatment.
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This question is part of the following fields:
- Cardiovascular System
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