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  • Question 1 - A man in his forties comes in with chest pain resembling a heart...

    Incorrect

    • A man in his forties comes in with chest pain resembling a heart attack and is diagnosed with a myocardial infarction. During his hospitalization, it is discovered that he has familial hypercholesterolemia but his triglyceride levels are normal. What is the underlying biochemical abnormality?

      Your Answer: Defective apolipoprotein E

      Correct Answer: Defective LDL receptors

      Explanation:

      Lipid Metabolism and Transport in the Body

      The breakdown of triglycerides in the small intestine is facilitated by pancreatic lipase. These triglycerides are then transported to the liver and other parts of the body through chylomicrons.

      Very low-density lipoprotein (VLDL) is responsible for carrying triglycerides from the liver to peripheral tissues. When there is an overproduction of VLDL in the liver, it can lead to high levels of triglycerides in the body.

      Pure hypercholesterolaemia is a condition that arises due to a defect in the process of cholesterol uptake into cells. This process relies on apolipoprotein B-100 binding to LDL receptors and facilitating endocytosis. When this process is disrupted, it can lead to high levels of cholesterol in the body.

    • This question is part of the following fields:

      • Basic Sciences
      22.1
      Seconds
  • Question 2 - Which statement regarding microtubules is accurate in relation to Chediak-Higashi syndrome? ...

    Incorrect

    • Which statement regarding microtubules is accurate in relation to Chediak-Higashi syndrome?

      Your Answer: They make poor targets for anti-cancer drugs

      Correct Answer: They are arranged in a 9+2 formation in cilia

      Explanation:

      Microtubules and Chediak-Higashi Syndrome

      Microtubules are structures composed of alpha and beta tubulin dimers that are arranged in a helix and can be added or removed to vary the length. They are found in flagella, mitotic spindles, and cilia, where they have a 9+2 arrangement. Chemotherapy agents, such as taxanes, target microtubules in breast cancer treatment.

      Chediak-Higashi syndrome is an autosomal recessive condition that presents with albinism, bleeding and bruising due to platelet dysfunction, and susceptibility to infections due to abnormal neutrophils. The LYST gene is responsible for lysosomal trafficking proteins and is affected in this syndrome.

      In summary, microtubules are important structures in various cellular processes and are targeted in cancer treatment. Chediak-Higashi syndrome is a rare genetic disorder that affects lysosomal trafficking proteins and presents with various symptoms.

    • This question is part of the following fields:

      • Basic Sciences
      10.4
      Seconds
  • Question 3 - Which food is a rich source of vitamin D in the diet? ...

    Correct

    • Which food is a rich source of vitamin D in the diet?

      Your Answer: Oily fish

      Explanation:

      Sources of Vitamin D

      Vitamin D is a type of fat-soluble vitamin that can be found in certain foods such as cheese, butter, eggs, and oily fish. However, vegetable sources of vitamin D are limited, although some foods are fortified with this vitamin. For instance, 100 grams of sundried shiitake mushrooms contain 1600 IU of vitamin D, while one egg contains 20 IU. Wild salmon is also a good source of vitamin D, with 100 grams containing 800 IU, while farmed salmon contains 200 IU.

      Aside from food sources, sunlight is also a good source of vitamin D. Exposure of arms and legs to sunlight for 10-15 minutes can provide 3000 IU of vitamin D. However, it is difficult to obtain the daily requirement of 25-50 IU of vitamin D through sunlight alone, especially for people living in temperate climates. As a result, many people may have insufficient vitamin D levels. It is important to ensure that we get enough vitamin D through a combination of food sources and sunlight exposure.

    • This question is part of the following fields:

      • Basic Sciences
      8.1
      Seconds
  • Question 4 - A 32-year-old snowboarder presents to the Emergency department complaining of pain and swelling...

    Incorrect

    • A 32-year-old snowboarder presents to the Emergency department complaining of pain and swelling around the first metacarpophalangeal joint (MCP joint) following a fall during practice.
      Upon examination, there is significant swelling and bruising on the ulnar side of the joint.

      What is the most probable injury that the patient has sustained?

      Your Answer: Accessory collateral ligament

      Correct Answer: Ulnar collateral ligament

      Explanation:

      Skier’s Thumb: A Common Injury in Winter Sports

      Skier’s thumb, also known as gamekeeper’s thumb, is a common injury that occurs in winter sports. It is caused by damage or rupture of the ulnar collateral ligament, which is located at the base of the thumb. This injury can result in acute swelling and gross instability of the thumb. In severe cases where a complete tear of the ligament is suspected, an MRI may be necessary to confirm the diagnosis, and surgical repair may be required.

      Once the acute swelling has subsided, treatment for skier’s thumb typically involves immobilization in a thumb spica. This is the standard therapy for cases of partial rupture.

    • This question is part of the following fields:

      • Basic Sciences
      20.4
      Seconds
  • Question 5 - What are the primary constituents of the cytoskeleton in eukaryotic cells? ...

    Incorrect

    • What are the primary constituents of the cytoskeleton in eukaryotic cells?

      Your Answer: Microfilaments and alpha/beta microtubules

      Correct Answer: Microfilaments, intermediate filaments and microtubules

      Explanation:

      The Eukaryotic Cytoskeleton: A Structural Support System

      The eukaryotic cytoskeleton is a network of structures that provide structural support to the cell. It helps the cell maintain its shape, protects it from external pressure, and performs intracellular transport. The cytoskeleton is made up of three major structures: microfilaments, intermediate filaments, and microtubules. Microfilaments are thin double helices made up of actin and are involved in pressure resistance and cell motility. Intermediate filaments have a more complex structure and maintain cell shape while bearing tension. Microtubules are hollow cylinders made up of alpha and beta tubulin proteins and are involved in intracellular transport, cell movement, and form the mitotic spindle during cytokinesis.

      Cilia, flagella, and lamellipodia are structures that are not part of the cell’s cytoskeleton but are made up of components of it and perform unique functions such as cell movement and extracellular sensing. Kinesin and dynein are motor proteins that support microtubule function. Microfilaments and alpha/beta microtubules are incorrect because they leave out intermediate filaments. Tubulin and actin are proteins of microtubules and microfilaments, respectively, but myosin is a motility protein involved in muscle contraction. The eukaryotic cytoskeleton is an essential component of the cell that provides structural support and enables various cellular functions.

    • This question is part of the following fields:

      • Basic Sciences
      213.3
      Seconds
  • Question 6 - Over the last five years, the total number of patients admitted and deaths...

    Incorrect

    • Over the last five years, the total number of patients admitted and deaths in the East and North Hertfordshire NHS Trust have been recorded. In the year 2010/2011, there were 95,071 patients admitted and 1,912 deaths. What is the crude mortality ratio for this group in that year (per 100 admissions)?

      Your Answer: 1.7

      Correct Answer: 2

      Explanation:

      In this scenario, the crude mortality ratio is established by comparing the number of deaths occurring within the hospital in a given year to the total number of admissions, disregarding age or gender-specific mortality rates. For instance, with 1,912 deaths out of 95,071 admissions, the ratio computes to 0.02, or 2.0% when calculated per 100 admissions (1,912/95,071 = 0.02/100= 2.0%. When recalculated per 1,000 admissions, the crude admission rate would be 20 per 1,000.

    • This question is part of the following fields:

      • Basic Sciences
      20.9
      Seconds
  • Question 7 - You encounter a patient in the Emergency department who has been in a...

    Incorrect

    • You encounter a patient in the Emergency department who has been in a severe car accident. You need to insert a venous cannula for aggressive fluid resuscitation. Applying the Hagen-Poiseuille equation, you select a cannula with appropriate dimensions for maximum flow into the vein.
      As per this law, which of the following statements is correct?

      Your Answer: Flow is not affected by the viscosity of the fluid

      Correct Answer: Flow will be faster through a shorter cannula

      Explanation:

      Poiseuille’s Equation and Fluid Flow in Cylinders

      Poiseuille’s equation is used to describe the flow of non-pulsatile laminar fluids through a cylinder. The equation states that the flow rate is directly proportional to the pressure driving the fluid and the fourth power of the radius. Additionally, it is inversely proportional to the viscosity of the fluid and the length of the tube. This means that a short, wide cannula with pressure on the bag will deliver fluids more rapidly than a long, narrow one.

      It is important to note that even small changes in the radius of a tube can greatly affect the flow rate. This is because the fourth power of the radius is used in the equation. Therefore, any changes in the radius will have a significant impact on the flow rate. Poiseuille’s equation is crucial in determining the optimal conditions for fluid delivery in medical settings.

    • This question is part of the following fields:

      • Basic Sciences
      9.2
      Seconds
  • Question 8 - What type of molecule does haemoglobin belong to? ...

    Incorrect

    • What type of molecule does haemoglobin belong to?

      Your Answer: Triglyceride

      Correct Answer: Quaternary protein structure

      Explanation:

      The Structure and Functions of Proteins

      Proteins are complex molecules that can vary in structure from single amino acids to large, folded molecules. Amino acids are joined together by peptide bonds to form dipeptides and polypeptides. More complex molecules can also have disulphide bonds and ionic bonds. The primary structure of a protein is a simple amino acid chain, while the secondary structure is a specific shape such as a helix or pleated sheet. The tertiary structure is a more globular shape, arranged by ionic, hydrogen, and disulphide bonds, and hydrophobic interactions. The quaternary structure is a complex protein containing several polypeptide chains held together by interactions.

      Proteins have multiple roles within the human body, including as hormones, food substrates, enzymes, receptor molecules, muscles, cell membrane constituents, carrier molecules in blood, and determinants of oncotic/osmotic pressures. However, proteins can be easily damaged by denaturation, which is the loss of the specific three-dimensional shape of a molecule. Denaturation can be caused by heat, salts, heavy metals, solvents, detergents, and extremes of pH.

      In summary, proteins are essential molecules with a diverse range of structures and functions within the human body. their structure and potential for denaturation is crucial for maintaining their proper function.

    • This question is part of the following fields:

      • Basic Sciences
      7.8
      Seconds
  • Question 9 - Which form of vitamin D is the most active in the human body?...

    Correct

    • Which form of vitamin D is the most active in the human body?

      Your Answer: 1, 25 (OH) 2 vitamin D

      Explanation:

      The Process of Vitamin D Production and Activation

      Vitamin D comes in two forms, D2 and D3. D3 can be produced in the skin through a reaction that requires UV light, while D2 cannot. Both forms can also be obtained through diet, with some foods now being supplemented with Vitamin D. However, the production of Vitamin D3 in the skin can be affected by various factors such as seasons, latitude, clothing, sun block, and skin tone, making it difficult for individuals to get adequate levels of Vitamin D through sunlight alone, especially in the UK during winter.

      Once absorbed into the lymph, Vitamin D2 and D3 circulate in the bloodstream and reach the liver. Here, the liver enzyme 25-hydroxylase adds an OH group to the Vitamin D molecule, resulting in 25(OH) Vitamin D. The compound then travels to the kidney, where the enzyme 1-alpha hydroxylase adds another OH group, creating the active form of Vitamin D, 1,25 (OH)2Vitamin D. When there is enough of this active form, an inactive metabolite called 24,25 (OH)2Vitamin D is produced instead. this process is important in ensuring adequate Vitamin D levels for overall health and well-being.

    • This question is part of the following fields:

      • Basic Sciences
      9.7
      Seconds
  • Question 10 - What RNA base pairs with adenine when synthesizing a complementary RNA strand from...

    Incorrect

    • What RNA base pairs with adenine when synthesizing a complementary RNA strand from DNA, using RNA polymerase to split the helix at specific points?

      Your Answer: Lysine

      Correct Answer: Uracil

      Explanation:

      Differences between DNA and RNA

      DNA and RNA differ in several ways. The primary sugar in DNA is deoxyribose, while in RNA it is ribose. Additionally, DNA is double stranded, while RNA is single stranded. This single stranded structure with un-paired bases allows for transcription to occur when the DNA bases are freed. Each base has a specific pairing, with guanine always binding to cytosine and adenine always binding to thymine in the DNA strand. During transcription, the same complementary RNA bases assemble with the DNA bases, except for thymine, which is not an RNA base. Instead, uracil serves as the RNA pyrimidine base equivalent of thymine. Finally, lysine is an amino acid coded for by the RNA base triplet AAA, where A represents adenine.

    • This question is part of the following fields:

      • Basic Sciences
      16.6
      Seconds
  • Question 11 - While taking a patient's medical history, you discover that their family has a...

    Incorrect

    • While taking a patient's medical history, you discover that their family has a strong history of a certain disease. Autosomal dominant diseases are often caused by defects in structural genes and typically present in early adulthood, affecting both males and females equally. Which of the following diseases does not follow an autosomal dominant pattern of inheritance?

      Your Answer: Neurofibromatosis type 1

      Correct Answer: Haemochromatosis

      Explanation:

      Abnormal Binding Proteins and Iron Deposition: A Genetic Disorder

      Abnormal binding proteins can lead to the deposition of iron in the body, resulting in various health complications. This genetic disorder is inherited in an autosomal recessive manner. The deposition of iron can cause cardiomyopathy, cirrhosis, pancreatic failure due to fibrosis, and skin pigmentation.

      In general, disorders that affect metabolism or DNA replication on a cellular or genetic level tend to be autosomal recessive. On the other hand, genetic disorders that affect the structure of the body on a larger level are usually autosomal dominant. While there may be exceptions to these rules, they can serve as a helpful guide for exam preparation. Proper of this genetic disorder can aid in its diagnosis and management.

    • This question is part of the following fields:

      • Basic Sciences
      20
      Seconds
  • Question 12 - What occurs during metaphase II of meiosis? ...

    Correct

    • What occurs during metaphase II of meiosis?

      Your Answer: The cell's chromosomes attach to the meiotic spindle to divide into chromatids

      Explanation:

      The Process of Meiosis

      Meiosis is a complex process that involves two major cycles. The first cycle, meiosis I, condenses the reproductive cell’s DNA into chromosomes that are then replicated, creating two pairs of each original chromosome. These pairs are then separated, and the cell divides with one chromosome in each daughter cell. The second cycle, meiosis II, splits the chromosomes into individual chromatids, which are then separated as in meiosis I. This separation is facilitated by a spindle, a set of parallel fibers that attach to the center of each chromosome and split into two, making the chromatids travel on the polar opposite sides of the cell. The cell then divides again, giving rise to four haploid daughter cells.

      During meiosis II, the chromosomes align on the spindle in metaphase II. Tetrads separate during anaphase I and line up during metaphase I. Sister chromatids separate on the meiotic spindle during anaphase II. Finally, chromosomes uncoil and lengthen at the end of meiosis, in telophase II. This process is essential for the production of gametes and the continuation of sexual reproduction in many organisms.

    • This question is part of the following fields:

      • Basic Sciences
      22
      Seconds
  • Question 13 - At what stage of meiosis does the process of homologous recombination occur? ...

    Incorrect

    • At what stage of meiosis does the process of homologous recombination occur?

      Your Answer: Metaphase II

      Correct Answer: Prophase I

      Explanation:

      Homologous Recombination: A Mechanism for DNA Repair and Genetic Variation

      Homologous recombination is a process that allows for the exchange of nucleotide sequences between two similar or identical DNA molecules. This occurs during meiosis, specifically during the second phase of prophase I, where sister chromatids swap sequences. The primary purpose of homologous recombination is to accurately repair harmful double-strand DNA breaks. This process results in new combinations of DNA sequences that provide genetic variation in daughter cells and, ultimately, the organism’s offspring.

      In prokaryotic organisms such as bacteria and viruses, homologous recombination occurs during horizontal gene transfer. This process involves the exchange of genetic material between different strains and species. Homologous recombination plays a crucial role in the evolution of these organisms by allowing for the acquisition of new traits and adaptations.

      Overall, homologous recombination is a vital mechanism for DNA repair and genetic variation. It ensures the accuracy of DNA replication and contributes to the diversity of life on Earth.

    • This question is part of the following fields:

      • Basic Sciences
      94.8
      Seconds
  • Question 14 - Which process occurs mainly in the smooth endoplasmic reticulum? ...

    Incorrect

    • Which process occurs mainly in the smooth endoplasmic reticulum?

      Your Answer: Lysosome production

      Correct Answer: Steroid synthesis

      Explanation:

      The Functions of Endoplasmic Reticulum and Lysosomes

      The endoplasmic reticulum (ER) is a complex network of membranes that is divided into two types: rough and smooth. The rough ER is characterized by the presence of ribosomes on its cytosolic side, which makes it an important site for protein production, modification, and transport. On the other hand, the smooth ER is involved in cholesterol and steroid handling, as well as calcium storage in some cells. This type of ER is particularly prominent in cells that produce large amounts of steroid hormones, such as those found in the adrenal cortex.

      Lysosomes, on the other hand, are organelles that are responsible for breaking down and recycling cellular waste. They are formed by the Golgi apparatus, which is another complex network of membranes found in eukaryotic cells. Lysosomes contain a variety of enzymes that are capable of breaking down different types of molecules, including proteins, lipids, and carbohydrates.

      In summary, the ER and lysosomes are two important organelles in eukaryotic cells that play different roles in cellular metabolism. While the ER is involved in protein production, modification, and transport, the lysosomes are responsible for breaking down and recycling cellular waste.

    • This question is part of the following fields:

      • Basic Sciences
      10.1
      Seconds
  • Question 15 - As part of your general practice placement, you have been tasked with conducting...

    Incorrect

    • As part of your general practice placement, you have been tasked with conducting an audit on the duration of solid food introduction in the practice population. You review the data for the last six infants born within the practice:
      6 months, 7 months, 8 months, 9 months, 10 months, 11 months.

      What is the variance value for the duration of solid food introduction in the practice population?

      Your Answer: 8.6

      Correct Answer: 74.9

      Explanation:

      Variance and Standard Deviation in Breast Feeding Duration

      Variance is a statistical measure that indicates how spread out a set of data is. In the case of breast feeding duration, variance can help us understand how much the duration varies from the mean. The formula for variance involves squaring the difference between each data point and the mean, then dividing the sum by n-1, where n is the total number of data points. In a sample population, n-1 is a better estimate of variance than n because it accounts for the variability within the sample.

      For example, if the variance of breast feeding duration is 74.9 months, this indicates that the duration is widely distributed from the mean of 17.6 months. A smaller variance, such as 4.5 months, would indicate that the duration varies less and is closer to the mean. The standard deviation, which is the square root of the variance, is also important in the spread of data. In a normal distribution, 95% of observations will fall within two standard deviations of the mean.

      In the case of breast feeding duration, the mean is 17.6 months, indicating that babies are breast fed for an average of 15 and a half months. The median, which is the middle number in the data set, is 15 months, meaning that half of the babies were breast fed for 15 months. variance and standard deviation can help us better understand the distribution of breast feeding duration and other medical measurements.

    • This question is part of the following fields:

      • Basic Sciences
      10
      Seconds
  • Question 16 - What factor causes a shift of the oxygen dissociation curve to the left?...

    Incorrect

    • What factor causes a shift of the oxygen dissociation curve to the left?

      Your Answer: Increased atmospheric pressure

      Correct Answer: Increased pH

      Explanation:

      The Oxygen Dissociation Curve and its Effects on Oxygen Saturation

      The oxygen dissociation curve is a graph that compares the oxygen saturation of hemoglobin (Hb) at different partial pressures of oxygen. When more oxygen is needed by the tissues, the curve shifts to the right. This means that at the same partial pressure of oxygen, less oxygen is bound to Hb, allowing it to be released to the tissues. This effect is caused by increased levels of CO2 and temperature, which assist in the transfer of oxygen to more metabolically active tissues. Additionally, increased levels of 2,3-DPG also aid in this process.

      On the other hand, a left shift in the curve reflects conditions where there is less need for oxygen in the tissues, such as in the lungs. This allows for increased binding of oxygen to Hb, allowing it to be taken up before transport to the tissues that require it. Overall, the oxygen dissociation curve plays a crucial role in regulating oxygen saturation in the body and ensuring that oxygen is delivered to the tissues that need it most.

    • This question is part of the following fields:

      • Basic Sciences
      4.8
      Seconds
  • Question 17 - What occurs in eukaryotic prophase? ...

    Correct

    • What occurs in eukaryotic prophase?

      Your Answer: Chromatin condenses into chromosomes

      Explanation:

      The Stages of Prophase in Eukaryotic Mitosis

      Prophase is the first stage of eukaryotic mitosis, except for plant cells which have a preprophase stage. During prophase, the cell’s chromatin, which is made up of DNA and associated proteins, condenses into double rod-shaped structures called chromosomes. This process is facilitated by the condensin protein I and/or II complexes. As the chromosomes form, the nuclear membrane and nucleoli disintegrate and disappear, making the chromatin visible.

      Before prophase, the cell’s DNA is replicated during interphase, resulting in identical pairs of chromosomes called chromatids. These chromatids attach to each other at a DNA element called the centromere. DNA and centrosome duplication occur during interphase, while chromosome alignment takes place during metaphase. The nuclear membrane and nucleoli re-form during telophase, and the sister chromatids separate during anaphase.

      In summary, prophase is the initial stage of eukaryotic mitosis where chromatin condenses into chromosomes, and the nuclear membrane and nucleoli disappear. Chromosome alignment, DNA and centrosome duplication, and re-formation of the nuclear membrane and nucleoli occur in subsequent stages.

    • This question is part of the following fields:

      • Basic Sciences
      20.1
      Seconds
  • Question 18 - During which stage of the cell cycle does the replication of DNA occur?...

    Incorrect

    • During which stage of the cell cycle does the replication of DNA occur?

      Your Answer: G2 phase

      Correct Answer: S phase

      Explanation:

      The Five Phases of the Cell Cycle

      The cell cycle is a complex process that is divided into five main phases, each with its unique cellular events. The first phase is the G0 phase, which is a resting phase where the cell has stopped dividing and is out of the cell cycle. The second phase is the G1 phase, also known as interphase Gap 1, where cells increase in size, and a checkpoint control mechanism prepares the cell for DNA synthesis.

      The third phase is the S phase, where DNA replication occurs. The fourth phase is the G2 phase, also known as Gap 2, which is a gap between DNA synthesis and the onset of mitosis. During this phase, the cell continues to grow until it is ready to enter mitosis. Finally, the fifth phase is the M phase, also known as mitosis, where cell growth stops, and the cell focuses its energy to divide into two daughter cells.

      A checkpoint in the middle of mitosis, known as the metaphase checkpoint, ensures that the cell is prepared to complete division. the five phases of the cell cycle is crucial in how cells divide and grow.

    • This question is part of the following fields:

      • Basic Sciences
      5.4
      Seconds
  • Question 19 - What is the term for the process described below in laboratory testing?

    Enzymes...

    Correct

    • What is the term for the process described below in laboratory testing?

      Enzymes are immobilised on a solid surface, such as a bead or well, and allowed to come into contact with the sample. After washing, another enzyme is added with a label allowing quantitation of the analyte.

      Your Answer: Enzyme-linked immunosorbent assay

      Explanation:

      ELISA: A Common Immunoassay in Medical Diagnostic Testing

      An enzyme-linked immunosorbent assay (ELISA) is a type of immunoassay that is widely used in medical diagnostic testing. This method uses antibodies to identify and/or quantify the analyte being tested. The ELISA process involves several steps, including coating a plate with the antigen, adding the patient’s sample, washing the plate to remove any unbound material, adding an enzyme-linked antibody, washing the plate again, and adding a substrate to produce a measurable signal.

      Over time, many modifications have been made to the ELISA, making it a versatile tool in the laboratory for measuring various analytes. Some of the substances that can be measured using immunoassays include thyroid hormone, testosterone, oestrogen, troponin, and vitamin D. The ELISA has been around for a long time and is still widely used today due to its accuracy, sensitivity, and specificity.

    • This question is part of the following fields:

      • Basic Sciences
      10.3
      Seconds
  • Question 20 - What is the final product of glycolysis besides ATP? ...

    Incorrect

    • What is the final product of glycolysis besides ATP?

      Your Answer:

      Correct Answer: Pyruvate

      Explanation:

      Glycolysis: The Energy-Producing Reaction

      Glycolysis is a crucial energy-producing reaction that converts glucose into pyruvate while releasing energy to create ATP and NADH+. It is one of the three major carbohydrate reactions, along with the citric acid cycle and the electron transport chain. The reaction involves ten enzymatic steps that provide entry points to glycolysis, allowing for a variety of starting points. The most common starting point is glucose or glycogen, which produces glucose-6-phosphate.

      Glycolysis occurs in two phases: the preparatory (or investment) phase and the pay-off phase. In the preparatory phase, ATP is consumed to start the reaction, while in the pay-off phase, ATP is produced. Glycolysis can be either aerobic or anaerobic, but it does not require nor consume oxygen.

      Although other molecules are involved in glycolysis at some stage, none of them form its end product. Lactic acid is associated with anaerobic glycolysis. glycolysis is essential for how the body produces energy from carbohydrates.

    • This question is part of the following fields:

      • Basic Sciences
      0
      Seconds

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Basic Sciences (9/19) 47%
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