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Question 1
Incorrect
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A 59-year-old man arrives at the emergency department complaining of severe pain in his right leg. He reports that the front of his shin became swollen and red three days ago, and the symptoms have since spread to his ankle and foot. He recalls sustaining a small skin cut in the affected area while gardening. Upon examination, the man has a temperature of 37.9 degrees Celsius, a pulse rate of 96 beats per minute, a respiratory rate of 18 breaths per minute, and a blood pressure of 110/65 mmHg. The leg is warm, tender, and visibly swollen and red, with no clear boundary between the affected and unaffected skin. There is no pus discharge or abscess. The patient has a medical history of diabetes, hypertension, and hyperlipidemia, and is currently taking metformin, amlodipine, and atorvastatin. The doctor diagnoses the patient with a skin tissue infection and prescribes flucloxacillin and paracetamol for pain relief. What is the most accurate description of the dermatological involvement in this patient's condition?
Your Answer: The upper dermis and superficial lymphatics are involved
Correct Answer: The dermis and subcutaneous tissues are involved
Explanation:Cellulitis affects the deeper dermis and subcutaneous tissues, while erysipelas only affects the upper dermis and superficial lymphatics. In this case, the patient’s symptoms strongly suggest a diagnosis of cellulitis, as there is a history of skin cut to the affected area, the patient is diabetic, and there is no clear demarcation between the affected and non-affected skin. Additionally, the patient reports significant pain, which is a common symptom of cellulitis. Cellulitis is typically caused by bacterial organisms such as Streptococcus pyogenes and Staphylococcus aureus, while erysipelas is caused by Streptococcus pyogenes and is characterized by a clear demarcation between affected and non-affected skin areas.
Understanding Cellulitis: Symptoms, Diagnosis, and Treatment
Cellulitis is a common skin infection caused by Streptococcus pyogenes or Staphylococcus aureus. It is characterized by inflammation of the skin and subcutaneous tissues, usually on the shins, accompanied by erythema, pain, swelling, and sometimes fever. The diagnosis of cellulitis is based on clinical features, and no further investigations are required in primary care. However, bloods and blood cultures may be requested if the patient is admitted and septicaemia is suspected.
To guide the management of patients with cellulitis, NICE Clinical Knowledge Summaries recommend using the Eron classification. Patients with Eron Class III or Class IV cellulitis, severe or rapidly deteriorating cellulitis, very young or frail patients, immunocompromised patients, patients with significant lymphoedema, or facial or periorbital cellulitis (unless very mild) should be admitted for intravenous antibiotics. Patients with Eron Class II cellulitis may not require admission if the facilities and expertise are available in the community to give intravenous antibiotics and monitor the patient.
The first-line treatment for mild/moderate cellulitis is flucloxacillin, while clarithromycin, erythromycin (in pregnancy), or doxycycline is recommended for patients allergic to penicillin. Patients with severe cellulitis should be offered co-amoxiclav, cefuroxime, clindamycin, or ceftriaxone. Understanding the symptoms, diagnosis, and treatment of cellulitis is crucial for effective management and prevention of complications.
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This question is part of the following fields:
- General Principles
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Question 2
Incorrect
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A 32-year-old female patient visits your clinic complaining of fatigue and unexplained weight gain. She mentions feeling extremely sensitive to cold temperatures. You suspect hypothyroidism and decide to conduct a test on her serum levels of thyroid stimulating hormone (TSH) and free thyroxine (T4). Which of the following hormones is not secreted from the anterior pituitary gland, where TSH is released?
Your Answer: Growth hormone
Correct Answer: antidiuretic hormone
Explanation:The hormone ADH (also known as vasopressin) is secreted by the posterior pituitary gland and acts in the collecting ducts of the kidneys to increase water reabsorption. Unlike ADH, all of the other hormone options presented are released from the anterior pituitary. ACTH is a component of the hypothalamic-pituitary-axis and increases the production and release of cortisol from the adrenal gland. GH (also called somatotropin) is an anabolic hormone that stimulates growth in childhood and has metabolic effects on protein, glucose, and lipids. FSH is a gonadotropin that promotes the maturation of germ cells.
Thyroid disorders are commonly encountered in clinical practice, with hypothyroidism and thyrotoxicosis being the most prevalent. Women are ten times more likely to develop these conditions than men. The thyroid gland is a bi-lobed structure located in the anterior neck and is part of a hypothalamus-pituitary-end organ system that regulates the production of thyroxine and triiodothyronine hormones. These hormones help regulate energy sources, protein synthesis, and the body’s sensitivity to other hormones. Hypothyroidism can be primary or secondary, while thyrotoxicosis is mostly primary. Autoimmunity is the leading cause of thyroid problems in the developed world.
Thyroid disorders can present in various ways, with symptoms often being the opposite depending on whether the thyroid gland is under or overactive. For example, hypothyroidism may result in weight gain, while thyrotoxicosis leads to weight loss. Thyroid function tests are the primary investigation for diagnosing thyroid disorders. These tests primarily look at serum TSH and T4 levels, with T3 being measured in specific cases. TSH levels are more sensitive than T4 levels for monitoring patients with existing thyroid problems.
Treatment for thyroid disorders depends on the cause. Patients with hypothyroidism are given levothyroxine to replace the underlying deficiency. Patients with thyrotoxicosis may be treated with propranolol to control symptoms such as tremors, carbimazole to reduce thyroid hormone production, or radioiodine treatment.
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This question is part of the following fields:
- Endocrine System
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Question 3
Incorrect
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A 35-year-old man arrives at the Emergency Department complaining of pain in his right hand following a fall during a football match earlier in the day. Upon conducting a thorough hand examination, you identify that the pain is concentrated in the anatomical snuffbox. To investigate a possible scaphoid bone fracture, you order an x-ray.
Which structure, passing through the anatomical snuffbox, is most likely to have been affected by this injury?Your Answer: The deep branch of the radial nerve
Correct Answer: The radial artery
Explanation:The radial artery is the only structure that passes through the anatomical snuffbox and is commonly injured by scaphoid bone fractures, as it runs over the bone at the snuffbox. Therefore, it is the most likely structure to be affected by such a fracture.
The median nerve does not pass through the anatomical snuffbox, but rather through the carpal tunnel, so it is less likely to be injured by a scaphoid fracture.
While the radial nerve does pass through the snuffbox, it is the superficial branch, not the deep branch, that does so. Therefore, if a scaphoid bone fracture were to damage the radial nerve, it would likely affect the superficial branch rather than the deep branch.
The basilic vein does not pass through the anatomical snuffbox, but rather travels along the ulnar side of the arm. The cephalic vein is the vein that passes through the snuffbox.
The extensor pollicis longus tendon forms the medial border of the snuffbox, but it is not one of its contents. It runs relatively superficially and is therefore less likely to be affected by a scaphoid bone fracture than a structure that runs closer to the bone, such as the radial artery.
The Anatomical Snuffbox: A Triangle on the Wrist
The anatomical snuffbox is a triangular depression located on the lateral aspect of the wrist. It is bordered by tendons of the extensor pollicis longus, extensor pollicis brevis, and abductor pollicis longus muscles, as well as the styloid process of the radius. The floor of the snuffbox is formed by the trapezium and scaphoid bones. The apex of the triangle is located distally, while the posterior border is formed by the tendon of the extensor pollicis longus. The radial artery runs through the snuffbox, making it an important landmark for medical professionals.
In summary, the anatomical snuffbox is a small triangular area on the wrist that is bordered by tendons and bones. It is an important landmark for medical professionals due to the presence of the radial artery.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 4
Incorrect
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A 25-year-old man is shot in the abdomen and experiences bleeding. What substance will cause vasoconstriction in response to this event?
Your Answer: None of the above
Correct Answer: Angiotensin II
Explanation:Vasoconstriction is not caused by renin. Angiotensin I is not biologically active. Aldosterone can raise blood pressure, but it does not have direct vasospastic effects.
Shock is a condition where there is not enough blood flow to the tissues. There are five main types of shock: septic, haemorrhagic, neurogenic, cardiogenic, and anaphylactic. Septic shock is caused by an infection that triggers a particular response in the body. Haemorrhagic shock is caused by blood loss, and there are four classes of haemorrhagic shock based on the amount of blood loss and associated symptoms. Neurogenic shock occurs when there is a disruption in the autonomic nervous system, leading to decreased vascular resistance and decreased cardiac output. Cardiogenic shock is caused by heart disease or direct myocardial trauma. Anaphylactic shock is a severe, life-threatening allergic reaction. Adrenaline is the most important drug in treating anaphylaxis and should be given as soon as possible.
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This question is part of the following fields:
- Gastrointestinal System
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Question 5
Correct
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A 45-year-old male with no past medical history is recently diagnosed with hypertension. His GP prescribes him lisinopril and orders a baseline renal function blood test, which comes back normal. The GP schedules a follow-up appointment for two weeks later to check his renal function. At the follow-up appointment, the patient's blood test results show:
Na 137 mmol/l
K 4.7 mmol/l
Cl 98 mmol/l
Urea 12.2 mmol/l
Creatinine 250 mg/l
What is the most likely cause for the abnormal blood test results?Your Answer: Bilateral stenosis of renal arteries
Explanation:Patients with renovascular disease should not be prescribed ACE inhibitors as their first line antihypertensive medication. This is because bilateral renal artery stenosis, a common cause of hypertension, can go undetected and lead to acute renal impairment when treated with ACE inhibitors. This occurs because the medication prevents the constriction of efferent arterioles, which is necessary to maintain glomerular pressure in patients with reduced blood flow to the kidneys. Therefore, further investigations such as a renal artery ultrasound scan should be conducted before prescribing ACE inhibitors to patients with hypertension.
Angiotensin-converting enzyme (ACE) inhibitors are commonly used as the first-line treatment for hypertension and heart failure in younger patients. However, they may not be as effective in treating hypertensive Afro-Caribbean patients. ACE inhibitors are also used to treat diabetic nephropathy and prevent ischaemic heart disease. These drugs work by inhibiting the conversion of angiotensin I to angiotensin II and are metabolized in the liver.
While ACE inhibitors are generally well-tolerated, they can cause side effects such as cough, angioedema, hyperkalaemia, and first-dose hypotension. Patients with certain conditions, such as renovascular disease, aortic stenosis, or hereditary or idiopathic angioedema, should use ACE inhibitors with caution or avoid them altogether. Pregnant and breastfeeding women should also avoid these drugs.
Patients taking high-dose diuretics may be at increased risk of hypotension when using ACE inhibitors. Therefore, it is important to monitor urea and electrolyte levels before and after starting treatment, as well as any changes in creatinine and potassium levels. Acceptable changes include a 30% increase in serum creatinine from baseline and an increase in potassium up to 5.5 mmol/l. Patients with undiagnosed bilateral renal artery stenosis may experience significant renal impairment when using ACE inhibitors.
The current NICE guidelines recommend using a flow chart to manage hypertension, with ACE inhibitors as the first-line treatment for patients under 55 years old. However, individual patient factors and comorbidities should be taken into account when deciding on the best treatment plan.
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This question is part of the following fields:
- Cardiovascular System
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Question 6
Correct
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A 25-year-old male is experiencing abdominal pain and is undergoing an abdominal ultrasound scan. During the scan, the radiologist observes signs of splenic atrophy. What could be the probable cause of this condition?
Your Answer: Coeliac disease
Explanation:In coeliac disease, the spleen may undergo atrophy and Howell-Jolly bodies may be observed in red blood cells. Histiocytosis X includes Letterer-Siwe disease, which involves the excessive growth of macrophages.
The Anatomy and Function of the Spleen
The spleen is an organ located in the left upper quadrant of the abdomen. Its size can vary depending on the amount of blood it contains, but the typical adult spleen is 12.5cm long and 7.5cm wide, with a weight of 150g. The spleen is almost entirely covered by peritoneum and is separated from the 9th, 10th, and 11th ribs by both diaphragm and pleural cavity. Its shape is influenced by the state of the colon and stomach, with gastric distension causing it to resemble an orange segment and colonic distension causing it to become more tetrahedral.
The spleen has two folds of peritoneum that connect it to the posterior abdominal wall and stomach: the lienorenal ligament and gastrosplenic ligament. The lienorenal ligament contains the splenic vessels, while the short gastric and left gastroepiploic branches of the splenic artery pass through the layers of the gastrosplenic ligament. The spleen is in contact with the phrenicocolic ligament laterally.
The spleen has two main functions: filtration and immunity. It filters abnormal blood cells and foreign bodies such as bacteria, and produces properdin and tuftsin, which help target fungi and bacteria for phagocytosis. The spleen also stores 40% of platelets, reutilizes iron, and stores monocytes. Disorders of the spleen include massive splenomegaly, myelofibrosis, chronic myeloid leukemia, visceral leishmaniasis, malaria, Gaucher’s syndrome, portal hypertension, lymphoproliferative disease, haemolytic anaemia, infection, infective endocarditis, sickle-cell, thalassaemia, and rheumatoid arthritis.
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This question is part of the following fields:
- Haematology And Oncology
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Question 7
Correct
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A 54-year-old male visits his GP complaining of sudden and severe abdominal pain that extends to his back. He has a history of heavy alcohol consumption, osteoarthritis, and asthma, and is a smoker. He is currently taking a salbutamol and corticosteroid inhaler. During the examination, his BMI is found to be 35kg/m².
What is the most probable reason for his symptoms?Your Answer: Heavy alcohol use
Explanation:Pancreatitis is most commonly caused by heavy alcohol use and gallstones, while osteoarthritis and smoking are not direct contributors. However, the use of a steroid inhaler and a high BMI may also play a role in the development of pancreatitis by potentially leading to hypertriglyceridemia.
Acute pancreatitis is a condition that is primarily caused by gallstones and alcohol consumption in the UK. However, there are other factors that can contribute to the development of this condition. A popular mnemonic used to remember these factors is GET SMASHED, which stands for gallstones, ethanol, trauma, steroids, mumps, autoimmune diseases, scorpion venom, hypertriglyceridaemia, hyperchylomicronaemia, hypercalcaemia, hypothermia, ERCP, and certain drugs. It is important to note that pancreatitis is seven times more common in patients taking mesalazine than sulfasalazine. CT scans can show diffuse parenchymal enlargement with oedema and indistinct margins in patients with acute pancreatitis.
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This question is part of the following fields:
- Gastrointestinal System
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Question 8
Incorrect
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Sophie, a 6-week-old baby, presents to the emergency department for evaluation. Her mother has observed that Sophie has been experiencing shortness of breath for the past 3 weeks, particularly during feeding. Sophie was born at 36 weeks and her mother reports no other issues since birth.
During the examination, a continuous machinery murmur with a left-sided sub-clavicular thrill is detected, and a diagnosis of patent ductus arteriosus is made. Surgery is not deemed necessary, but a medication that inhibits prostaglandin synthesis is recommended.
What is the most probable pharmacological treatment that will be offered?Your Answer: Prostaglandin E1
Correct Answer: Indomethacin
Explanation:The inhibition of prostaglandin synthesis in infants with patent ductus arteriosus is achieved through the use of indomethacin. This medication (or ibuprofen) is effective in promoting closure of the ductus arteriosus by inhibiting prostaglandin synthesis.
Beta-blockers such as bisoprolol are not used in the management of PDA, making this answer incorrect.
Steroids like dexamethasone and prednisolone are not typically used in the treatment of PDA, although they may be given to the mother if premature delivery is expected. Therefore, these answers are also incorrect.
Understanding Patent Ductus Arteriosus
Patent ductus arteriosus is a type of congenital heart defect that is generally classified as ‘acyanotic’. However, if left uncorrected, it can eventually result in late cyanosis in the lower extremities, which is termed differential cyanosis. This condition is caused by a connection between the pulmonary trunk and descending aorta. Normally, the ductus arteriosus closes with the first breaths due to increased pulmonary flow, which enhances prostaglandins clearance. However, in some cases, this connection remains open, leading to patent ductus arteriosus.
This condition is more common in premature babies, those born at high altitude, or those whose mothers had rubella infection in the first trimester. The features of patent ductus arteriosus include a left subclavicular thrill, continuous ‘machinery’ murmur, large volume, bounding, collapsing pulse, wide pulse pressure, and heaving apex beat.
The management of patent ductus arteriosus involves the use of indomethacin or ibuprofen, which are given to the neonate. These medications inhibit prostaglandin synthesis and close the connection in the majority of cases. If patent ductus arteriosus is associated with another congenital heart defect amenable to surgery, then prostaglandin E1 is useful to keep the duct open until after surgical repair. Understanding patent ductus arteriosus is important for early diagnosis and management of this condition.
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This question is part of the following fields:
- Cardiovascular System
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Question 9
Correct
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A middle-aged woman with myasthenia gravis experiences a myasthenic crisis leading to respiratory failure. Which nerve root is most commonly affected in this scenario?
Your Answer: C4
Explanation:The phrenic nerve receives input from C3, C4, and C5, which is essential for keeping the diaphragm functioning properly. In cases of medical emergencies, mechanical ventilation is often the first-line management. C2 primarily innervates muscles in the neck, while C7 and T1 are part of the brachial plexus and contribute to the formation of nerves in the upper limb.
The Phrenic Nerve: Origin, Path, and Supplies
The phrenic nerve is a crucial nerve that originates from the cervical spinal nerves C3, C4, and C5. It supplies the diaphragm and provides sensation to the central diaphragm and pericardium. The nerve passes with the internal jugular vein across scalenus anterior and deep to the prevertebral fascia of the deep cervical fascia.
The right phrenic nerve runs anterior to the first part of the subclavian artery in the superior mediastinum and laterally to the superior vena cava. In the middle mediastinum, it is located to the right of the pericardium and passes over the right atrium to exit the diaphragm at T8. On the other hand, the left phrenic nerve passes lateral to the left subclavian artery, aortic arch, and left ventricle. It passes anterior to the root of the lung and pierces the diaphragm alone.
Understanding the origin, path, and supplies of the phrenic nerve is essential in diagnosing and treating conditions that affect the diaphragm and pericardium.
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This question is part of the following fields:
- Respiratory System
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Question 10
Incorrect
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John is a 50-year-old African-American male who is admitted to hospital for potential isoniazid toxicity, after he developed worsening nausea, vomiting, rash and fever. During his hospital stay, it is identified that John is a slow acetylator, which led to the isoniazid toxicity.
As a slow acetylator, which of the following drugs could also be potentially toxic if given to this patient?Your Answer: Enalapril
Correct Answer: Sulfasalazine
Explanation:Understanding Drug Metabolism: Phase I and Phase II Reactions
Drug metabolism involves two types of biochemical reactions, namely phase I and phase II reactions. Phase I reactions include oxidation, reduction, and hydrolysis, which are mainly performed by P450 enzymes. However, some drugs are metabolized by specific enzymes such as alcohol dehydrogenase and xanthine oxidase. The products of phase I reactions are typically more active and potentially toxic. On the other hand, phase II reactions involve conjugation, where glucuronyl, acetyl, methyl, sulphate, and other groups are typically involved. The products of phase II reactions are typically inactive and excreted in urine or bile. The majority of phase I and phase II reactions take place in the liver.
First-Pass Metabolism and Drugs Affected by Zero-Order Kinetics and Acetylator Status
First-pass metabolism is a phenomenon where the concentration of a drug is greatly reduced before it reaches the systemic circulation due to hepatic metabolism. This effect is seen in many drugs, including aspirin, isosorbide dinitrate, glyceryl trinitrate, lignocaine, propranolol, verapamil, isoprenaline, testosterone, and hydrocortisone.
Zero-order kinetics describe metabolism that is independent of the concentration of the reactant. This is due to metabolic pathways becoming saturated, resulting in a constant amount of drug being eliminated per unit time. Drugs exhibiting zero-order kinetics include phenytoin, salicylates (e.g. high-dose aspirin), heparin, and ethanol.
Acetylator status is also an important consideration in drug metabolism. Approximately 50% of the UK population are deficient in hepatic N-acetyltransferase. Drugs affected by acetylator status include isoniazid, procainamide, hydralazine, dapsone, and sulfasalazine. Understanding these concepts is important in predicting drug efficacy and toxicity, as well as in optimizing drug dosing.
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This question is part of the following fields:
- General Principles
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Question 11
Incorrect
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A 67-year-old patient is being evaluated after being admitted for treatment of a persistent Clostridium difficile infection. The patient had received treatment for a previous infection three weeks ago, but the symptoms did not subside, and she continued to experience diarrhoea. The patient was hospitalized three days ago due to a life-threatening Clostridium difficile infection.
The patient has been receiving oral vancomycin and IV metronidazole for the past few days, but there has been no improvement in her symptoms. What would be the venous blood gas results in this case?Your Answer: Metabolic alkalosis + hypokalaemia
Correct Answer: Metabolic acidosis + hypokalaemia
Explanation:If a patient experiences prolonged diarrhoea, they may develop metabolic acidosis and hypokalaemia. This is likely the case for a patient with a history of prolonged Clostridium difficile infection, as the loss of bicarbonate ions from the GI tract during diarrhoea can lead to metabolic acidosis. Prolonged diarrhoea can also result in hypokalaemia due to the direct loss of potassium from the GI tract, which the body may be unable to compensate for. Therefore, metabolic acidosis and hypokalaemia are the expected outcomes in this scenario.
Understanding Metabolic Acidosis
Metabolic acidosis is a condition that can be classified based on the anion gap, which is calculated by subtracting the sum of chloride and bicarbonate from the sum of sodium and potassium. The normal range for anion gap is 10-18 mmol/L. If a question provides the chloride level, it may be an indication to calculate the anion gap.
Hyperchloraemic metabolic acidosis is a type of metabolic acidosis with a normal anion gap. It can be caused by gastrointestinal bicarbonate loss, prolonged diarrhea, ureterosigmoidostomy, fistula, renal tubular acidosis, drugs like acetazolamide, ammonium chloride injection, and Addison’s disease. On the other hand, raised anion gap metabolic acidosis is caused by lactate, ketones, urate, acid poisoning, and other factors.
Lactic acidosis is a type of metabolic acidosis that is caused by high lactate levels. It can be further classified into two types: lactic acidosis type A, which is caused by sepsis, shock, hypoxia, and burns, and lactic acidosis type B, which is caused by metformin. Understanding the different types and causes of metabolic acidosis is important in diagnosing and treating the condition.
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This question is part of the following fields:
- Renal System
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Question 12
Correct
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A 28-year-old male patient comes to you with worries about his increasing breast size, despite not experiencing any weight gain in other areas. Upon further inquiry, he also mentions a painless lump in his right testicle. He reveals that his father had testicular cancer in the past.
What is the probable reason for gynaecomastia in this scenario?Your Answer: Increased oestrogen: androgen ratio
Explanation:Gynaecomastia is a common symptom of testicular cancer and is caused by an increased oestrogen:androgen ratio. This occurs because germ-cell tumours produce hCG, which causes Leydig cells to produce more oestradiol in relation to testosterone. Leydig cell tumours also directly secrete more oestradiol and convert additional androgen precursors to oestrogens. This results in a relative reduction in androgen concentration and an increased conversion of androgens to oestrogens.
Obesity can also cause gynaecomastia due to increased levels of aromatase, the enzyme responsible for the conversion of androgens to oestrogens. However, this is not the most likely cause in this case as the patient has not gained weight elsewhere and presents with symptoms of testicular cancer.
Undescended testis is a significant risk factor for testicular cancer, but it is not a direct cause of gynaecomastia. Similarly, a prolactinoma can cause breast enlargement in males, but it is not commonly associated with testicular cancer or gynaecomastia.
In summary, gynaecomastia in testicular cancer is caused by an increased oestrogen:androgen ratio, which can result from germ-cell or Leydig cell tumours. Other potential causes, such as obesity, undescended testis, or prolactinoma, are less likely in this clinical scenario.
Testicular cancer is a common type of cancer that affects men between the ages of 20 and 30. The majority of cases (95%) are germ-cell tumors, which can be further classified as seminomas or non-seminomas. Non-germ cell tumors, such as Leydig cell tumors and sarcomas, are less common. Risk factors for testicular cancer include infertility, cryptorchidism, family history, Klinefelter’s syndrome, and mumps orchitis. Symptoms may include a painless lump, pain, hydrocele, and gynaecomastia.
Tumour markers can be used to diagnose testicular cancer. For germ cell tumors, hCG may be elevated in seminomas, while AFP and/or beta-hCG are elevated in non-seminomas. LDH may also be elevated in germ cell tumors. Ultrasound is the first-line diagnostic tool.
Treatment for testicular cancer depends on the type and stage of the tumor. Orchidectomy, chemotherapy, and radiotherapy may be used. Prognosis is generally excellent, with a 5-year survival rate of around 95% for Stage I seminomas and 85% for Stage I teratomas.
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This question is part of the following fields:
- Renal System
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Question 13
Correct
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Which one of the following statements about blood clotting is false?
Your Answer: Administration of aprotinin during liver transplantation surgery prolongs survival
Explanation:Aprotinin, which decreases bleeding by inhibiting fibrinolysis, was taken off the market in 2007 due to its link to higher mortality rates. Vitamin K-dependent protein C may actually increase the risk of thrombosis in the initial stages of warfarin treatment.
The Coagulation Cascade: Two Pathways to Fibrin Formation
The coagulation cascade is a complex process that leads to the formation of a blood clot. There are two pathways that can lead to fibrin formation: the intrinsic pathway and the extrinsic pathway. The intrinsic pathway involves components that are already present in the blood and has a minor role in clotting. It is initiated by subendothelial damage, such as collagen, which leads to the formation of the primary complex on collagen by high-molecular-weight kininogen (HMWK), prekallikrein, and Factor 12. This complex activates Factor 11, which in turn activates Factor 9. Factor 9, along with its co-factor Factor 8a, forms the tenase complex, which activates Factor 10.
The extrinsic pathway, on the other hand, requires tissue factor released by damaged tissue. This pathway is initiated by tissue damage, which leads to the binding of Factor 7 to tissue factor. This complex activates Factor 9, which works with Factor 8 to activate Factor 10. Both pathways converge at the common pathway, where activated Factor 10 causes the conversion of prothrombin to thrombin. Thrombin hydrolyses fibrinogen peptide bonds to form fibrin and also activates factor 8 to form links between fibrin molecules.
Finally, fibrinolysis occurs, which is the process of clot resorption. Plasminogen is converted to plasmin to facilitate this process. It is important to note that certain factors are involved in both pathways, such as Factor 10, and that some factors are vitamin K dependent, such as Factors 2, 7, 9, and 10. The intrinsic pathway can be assessed by measuring the activated partial thromboplastin time (APTT), while the extrinsic pathway can be assessed by measuring the prothrombin time (PT).
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This question is part of the following fields:
- Haematology And Oncology
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Question 14
Incorrect
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A woman in her 30s has recently delivered a baby boy without any complications despite having systemic lupus erythematosus. What immunoglobulins could potentially be decreased in her breast milk?
Your Answer: IgE
Correct Answer: IgA
Explanation:IgA is present in secretions like saliva, tears, and mucous. However, individuals with autoimmune disorders such as rheumatoid arthritis, systemic lupus erythematosus, and coeliac disease may have a deficiency of IgA. IgA is also present in breast milk, providing a temporary boost to the infant’s immune system during the early stages of life. On the other hand, IgD, IgE, and IgG are not present in breast milk. IgG, however, can cross the placenta, allowing the transfer of antibodies from the mother to the fetus during pregnancy.
Immunoglobulins, also known as antibodies, are proteins produced by the immune system to help fight off infections and diseases. There are five types of immunoglobulins found in the body, each with their own unique characteristics.
IgG is the most abundant type of immunoglobulin in blood serum and plays a crucial role in enhancing phagocytosis of bacteria and viruses. It also fixes complement and can be passed to the fetal circulation.
IgA is the most commonly produced immunoglobulin in the body and is found in the secretions of digestive, respiratory, and urogenital tracts and systems. It provides localized protection on mucous membranes and is transported across the interior of the cell via transcytosis.
IgM is the first immunoglobulin to be secreted in response to an infection and fixes complement, but does not pass to the fetal circulation. It is also responsible for producing anti-A, B blood antibodies.
IgD’s role in the immune system is largely unknown, but it is involved in the activation of B cells.
IgE is the least abundant type of immunoglobulin in blood serum and is responsible for mediating type 1 hypersensitivity reactions. It provides immunity to parasites such as helminths and binds to Fc receptors found on the surface of mast cells and basophils.
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This question is part of the following fields:
- General Principles
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Question 15
Incorrect
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A 50-year-old man with T2DM goes for his yearly diabetic retinopathy screening and is diagnosed with proliferative diabetic retinopathy. What retinal characteristics are indicative of this condition?
Your Answer: Microaneurysms
Correct Answer: neovascularization
Explanation:Diabetic retinopathy is a progressive disease that affects the retina and is a complication of diabetes mellitus (DM). The condition is caused by persistent high blood sugar levels, which can damage the retinal vessels and potentially lead to vision loss. The damage is caused by retinal ischaemia, which occurs when the retinal vasculature becomes blocked.
There are various retinal findings that indicate the presence of diabetic retinopathy, which can be classified into two categories: non-proliferative and proliferative. Non-proliferative diabetic retinopathy is indicated by the presence of microaneurysms, ‘cotton-wool’ spots, ‘dot-blot’ haemorrhages, and venous beading at different stages. However, neovascularization, or the formation of new blood vessels, is the finding associated with more advanced, proliferative retinopathy.
Understanding Diabetic Retinopathy
Diabetic retinopathy is a leading cause of blindness in adults aged 35-65 years-old. The condition is caused by hyperglycaemia, which leads to abnormal metabolism in the retinal vessel walls, causing damage to endothelial cells and pericytes. This damage leads to increased vascular permeability, which causes exudates seen on fundoscopy. Pericyte dysfunction predisposes to the formation of microaneurysms, while neovascularization is caused by the production of growth factors in response to retinal ischaemia.
Patients with diabetic retinopathy are typically classified into those with non-proliferative diabetic retinopathy (NPDR), proliferative retinopathy (PDR), and maculopathy. NPDR is further classified into mild, moderate, and severe, depending on the presence of microaneurysms, blot haemorrhages, hard exudates, cotton wool spots, venous beading/looping, and intraretinal microvascular abnormalities. PDR is characterized by retinal neovascularization, which may lead to vitreous haemorrhage, and fibrous tissue forming anterior to the retinal disc. Maculopathy is based on location rather than severity and is more common in Type II DM.
Management of diabetic retinopathy involves optimizing glycaemic control, blood pressure, and hyperlipidemia, as well as regular review by ophthalmology. For maculopathy, intravitreal vascular endothelial growth factor (VEGF) inhibitors are used if there is a change in visual acuity. Non-proliferative retinopathy is managed through regular observation, while severe/very severe cases may require panretinal laser photocoagulation. Proliferative retinopathy is treated with panretinal laser photocoagulation, intravitreal VEGF inhibitors, and vitreoretinal surgery in severe or vitreous haemorrhage cases. Examples of VEGF inhibitors include ranibizumab, which has a strong evidence base for slowing the progression of proliferative diabetic retinopathy and improving visual acuity.
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This question is part of the following fields:
- Neurological System
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Question 16
Incorrect
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A 75-year-old man comes to the hospital following a fall where he landed on his outstretched left hand. He reports experiencing pain in his left arm. Upon conducting an x-ray, it is revealed that he has a surgical neck fracture of the left humerus. Which nerve is commonly affected by this type of injury?
Your Answer: Median nerve
Correct Answer: Axillary nerve
Explanation:The axillary nerve is frequently injured in cases of surgical neck fractures of the humerus, as it passes through this area. Symptoms of axillary nerve injury include loss of sensation in the regimental badge area and difficulty with arm abduction due to the affected deltoid and teres minor muscles.
Damage to the median nerve is uncommon in cases of proximal or mid-shaft humeral fractures, as it is protected by surrounding muscle. However, it may be affected in distal humeral fractures as it passes through the cubital fossa.
The musculocutaneous nerve is well-protected by muscle and is rarely injured in cases of proximal humeral fractures.
The radial nerve is most commonly injured in midshaft humeral fractures, as it runs along the radial groove of the humerus.
Similarly to the median nerve, the ulnar nerve arises from the brachial plexus and runs along the medial surface of the upper arm. It is most commonly injured in cases of distal humeral fractures.
The humerus is a long bone that runs from the shoulder blade to the elbow joint. It is mostly covered by muscle but can be felt throughout its length. The head of the humerus is a smooth, rounded surface that connects to the body of the bone through the anatomical neck. The surgical neck, located below the head and tubercles, is the most common site of fracture. The greater and lesser tubercles are prominences on the upper end of the bone, with the supraspinatus and infraspinatus tendons inserted into the greater tubercle. The intertubercular groove runs between the two tubercles and holds the biceps tendon. The posterior surface of the body has a spiral groove for the radial nerve and brachial vessels. The lower end of the humerus is wide and flattened, with the trochlea, coronoid fossa, and olecranon fossa located on the distal edge. The medial epicondyle is prominent and has a sulcus for the ulnar nerve and collateral vessels.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 17
Incorrect
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A 24-year-old boxer presents to a physiotherapist with a wrist drop in his right arm, 8 weeks after sustaining a midshaft humeral fracture resulting in radial nerve palsy. An MRI scan reveals marked atrophy in the muscle inserting at the lateral supracondylar ridge of the humerus. To address this, the physiotherapist prescribes reverse dumbbell wrist curls to strengthen the affected muscle. Which muscle has undergone significant atrophy in this patient, based on the MRI findings and treatment plan?
Your Answer:
Correct Answer: Extensor carpi radialis longus
Explanation:The extensor carpi radialis longus muscle is innervated by the radial nerve. However, in a patient with a radial nerve palsy due to a midshaft humeral fracture, this muscle may be the only forearm extensor directly supplied by the radial nerve. Therefore, it is the most likely correct answer when considering exercises to strengthen the affected muscle.
The extensor carpi radialis brevis muscle, which originates from the lateral epicondyle of the humerus, is also innervated by a branch of the radial nerve. However, its insertion point is different from that described in the MRI, making it an unlikely answer.
The extensor digitorum brevis muscle, which assists in extending the toes, is not relevant to the patient’s wrist condition.
The extensor digitorum longus muscle, which is involved in foot dorsiflexion and toe extension, is also not relevant to the patient’s wrist condition.
Upper limb anatomy is a common topic in examinations, and it is important to know certain facts about the nerves and muscles involved. The musculocutaneous nerve is responsible for elbow flexion and supination, and typically only injured as part of a brachial plexus injury. The axillary nerve controls shoulder abduction and can be damaged in cases of humeral neck fracture or dislocation, resulting in a flattened deltoid. The radial nerve is responsible for extension in the forearm, wrist, fingers, and thumb, and can be damaged in cases of humeral midshaft fracture, resulting in wrist drop. The median nerve controls the LOAF muscles and can be damaged in cases of carpal tunnel syndrome or elbow injury. The ulnar nerve controls wrist flexion and can be damaged in cases of medial epicondyle fracture, resulting in a claw hand. The long thoracic nerve controls the serratus anterior and can be damaged during sports or as a complication of mastectomy, resulting in a winged scapula. The brachial plexus can also be damaged, resulting in Erb-Duchenne palsy or Klumpke injury, which can cause the arm to hang by the side and be internally rotated or associated with Horner’s syndrome, respectively.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 18
Incorrect
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A 49-year-old woman has been diagnosed with a phaeochromocytoma. What is the primary amino acid from which catecholamines are derived?
Your Answer:
Correct Answer: Tyrosine
Explanation:Tyrosine serves as the precursor for catecholamine hormones, which undergo modification by a DOPA decarboxylase enzyme to form dopamine. Subsequently, through two additional enzymatic alterations, dopamine is converted to noradrenaline and ultimately adrenaline.
Adrenal Physiology: Medulla and Cortex
The adrenal gland is composed of two main parts: the medulla and the cortex. The medulla is responsible for secreting the catecholamines noradrenaline and adrenaline, which are released in response to sympathetic nervous system stimulation. The chromaffin cells of the medulla are innervated by the splanchnic nerves, and the release of these hormones is triggered by the secretion of acetylcholine from preganglionic sympathetic fibers. Phaeochromocytomas, which are tumors derived from chromaffin cells, can cause excessive secretion of both adrenaline and noradrenaline.
The adrenal cortex is divided into three distinct zones: the zona glomerulosa, zona fasciculata, and zona reticularis. Each zone is responsible for secreting different hormones. The outer zone, zona glomerulosa, secretes aldosterone, which regulates electrolyte balance and blood pressure. The middle zone, zona fasciculata, secretes glucocorticoids, which are involved in the regulation of metabolism, immune function, and stress response. The inner zone, zona reticularis, secretes androgens, which are involved in the development and maintenance of male sex characteristics.
Most of the hormones secreted by the adrenal cortex, including glucocorticoids and aldosterone, are bound to plasma proteins in the circulation. Glucocorticoids are inactivated and excreted by the liver. Understanding the physiology of the adrenal gland is important for the diagnosis and treatment of various endocrine disorders.
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This question is part of the following fields:
- Endocrine System
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Question 19
Incorrect
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A 60-year-old man with chronic kidney disease secondary to diabetes is scheduled to undergo a contrast-enhanced CT scan for a suspected brain lesion. His latest eGFR is 51ml/min/1.73m2. After a multidisciplinary team discussion, it was decided that using contrast in the scan was in the patient's best interests, despite the increased risk of contrast-induced acute kidney injury. What would be the most suitable approach to minimize the risk of contrast-induced acute kidney injury in this situation?
Your Answer:
Correct Answer: Offer IV hydration before and after infusion
Explanation:To reduce the risk of contrast-induced acute kidney injury in high-risk patients, NICE guidelines recommend administering sodium chloride at a rate of 1 mL/kg/hour for 12 hours before and after the procedure. While there is some evidence supporting the use of acetylcysteine via IV infusion, it is not strong enough to be recommended in the guidelines. In at-risk patients, it is important to discuss whether the contrast is necessary. Waiting for the patient’s eGFR to improve is not a realistic option in this scenario, as the patient has chronic kidney disease. While maintaining tight glycaemic control is important for long-term kidney function, it is less relevant in this setting. Potentially nephrotoxic medications such as NSAIDs should be temporarily stopped, and ACE inhibitor therapy should be considered for cessation in patients with an eGFR less than 40ml/min/1.73m2, according to NICE guidelines.
Contrast media nephrotoxicity is characterized by a 25% increase in creatinine levels within three days of receiving intravascular contrast media. This condition typically occurs between two to five days after administration and is more likely to affect patients with pre-existing renal impairment, dehydration, cardiac failure, or those taking nephrotoxic drugs like NSAIDs. Procedures that may cause contrast-induced nephropathy include CT scans with contrast and coronary angiography or percutaneous coronary intervention (PCI). Around 5% of patients who undergo PCI experience a temporary increase in plasma creatinine levels of more than 88 µmol/L.
To prevent contrast-induced nephropathy, intravenous 0.9% sodium chloride should be administered at a rate of 1 mL/kg/hour for 12 hours before and after the procedure. Isotonic sodium bicarbonate may also be used. While N-acetylcysteine was previously used, recent evidence suggests it is not effective. Patients at high risk for contrast-induced nephropathy should have metformin withheld for at least 48 hours and until their renal function returns to normal to avoid the risk of lactic acidosis.
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This question is part of the following fields:
- Renal System
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Question 20
Incorrect
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A 67-year-old man presents with sudden onset headache, blurry vision, and weakness in his right arm. He has a history of multiple episodes of fleeting blindness and was diagnosed with diabetes mellitus 25 years ago. On physical examination, he has generalised lymphadenopathy, splenomegaly, and reduced tone and power in the right arm compared to the left. Fundoscopy reveals blurred disc margins and engorged retinal veins. Investigations show an increased erythrocyte sedimentation rate and plasma viscosity, and serum electrophoresis shows a monoclonal spike. Which plasma component is most likely responsible for his clinical features?
Your Answer:
Correct Answer: IgM
Explanation:Hyperviscosity syndrome is a condition that can occur in paraproteinemia, where there is an overproduction of IgM. This is because IgM is a pentamer, which means it is larger in size and can cause increased viscosity.
An elderly man is displaying stroke-like symptoms, but they are not in contiguous anatomical locations. This makes it unlikely that the cause is embolism or thrombosis, and suggests a global cause of ischemia. The presence of fleeting blindness (amaurosis fugax), increased viscosity, and monoclonal spike on serum electrophoresis all point towards a plasma cell dyscrasia, specifically hyperviscosity syndrome. Additional fundoscopic findings further support this suspicion.
Hyperviscosity can be caused by various conditions, but multiple myeloma is the most common. Other differentials include Waldenstrom’s macroglobulinemia and polycythemia rubra vera. The presence of generalized lymphadenopathy and splenomegaly make Waldenstrom’s macroglobulinemia more likely than the others.
In Waldenstrom’s macroglobulinemia, there is an overproduction of IgM, which is different from the other immunoglobulins as it is a pentamer. This makes it the largest immunoglobulin and more likely to cause hyperviscosity when in excess quantities. This is why Waldenstrom’s tends to present with hyperviscosity syndrome, while multiple myeloma rarely does.
Understanding Waldenstrom’s Macroglobulinaemia
Waldenstrom’s macroglobulinaemia is a rare condition that primarily affects older men. It is a type of lymphoplasmacytoid malignancy that is characterized by the production of a monoclonal IgM paraprotein. This condition can cause a range of symptoms, including systemic upset, hyperviscosity syndrome, hepatosplenomegaly, lymphadenopathy, and cryoglobulinemia.
One of the most significant features of Waldenstrom’s macroglobulinaemia is the hyperviscosity syndrome, which can lead to visual disturbances and other complications. This occurs because the pentameric configuration of IgM increases serum viscosity, making it more difficult for blood to flow through the body. Other symptoms of this condition can include weight loss, lethargy, and Raynaud’s.
To diagnose Waldenstrom’s macroglobulinaemia, doctors will typically look for a monoclonal IgM paraprotein in the patient’s blood. A bone marrow biopsy can also be used to confirm the presence of lymphoplasmacytic lymphoma cells in the bone marrow.
Treatment for Waldenstrom’s macroglobulinaemia typically involves rituximab-based combination chemotherapy. This approach can help to reduce the production of the monoclonal IgM paraprotein and alleviate symptoms associated with the condition. With proper management, many patients with Waldenstrom’s macroglobulinaemia are able to live full and healthy lives.
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This question is part of the following fields:
- Haematology And Oncology
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Question 21
Incorrect
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A 2-year-old toddler presents to the emergency department with a low-grade fever and difficulty breathing. The mother reports that the toddler has had some nasal discharge for the past two days and started coughing a few hours ago. The toddler has no significant medical history, being born full term at 39 weeks via normal vaginal delivery. The toddler is developmentally normal and received all vaccinations according to the immunisation schedule. During examination, the toddler appears lethargic and has a barking cough. Auscultation reveals an inspiratory stridor bilaterally, with no crepitations or wheezes heard. Air entry is equal bilaterally. The toddler's temperature is 38.3ºC, oxygen saturation is 93% based on pulse oximetry, blood pressure is 98/55 mmHg (normal range: SBP 72-140 mmHg; DBP 37-56 mmHg), and the heart rate is 120 beats per minute (normal range: 100-190 beats per minute).
What is the most likely association with this toddler's condition?Your Answer:
Correct Answer: Steeple sign
Explanation:The infant is displaying symptoms of croup, including a barking cough and inspiratory stridor, which is typical for their age. While chest radiographs are not typically used to diagnose croup, if a neck radiograph is taken, the steeple sign may be present, indicating subglottic narrowing due to inflammation of the larynx and trachea.
The thumb sign, which is indicative of an oedematous epiglottis, is not present in this case, and the infant does not display symptoms of epiglottitis, such as drooling or dysphagia. Additionally, the infant is not in the typical age range for epiglottitis.
The sail sign, which suggests left lower lobe collapse, is not present as the infant has equal bilateral air entry. The coffee bean sign, which is suggestive of sigmoid volvulus, is also not relevant as it typically presents with abdominal pain and distension, rather than respiratory symptoms, and is uncommon in children.
Croup is a respiratory infection that affects young children, typically those between 6 months and 3 years old. It is most common in the autumn and is caused by parainfluenza viruses. The main symptom is stridor, which is caused by swelling and secretions in the larynx. Other symptoms include a barking cough, fever, and cold-like symptoms. The severity of croup can be graded based on the child’s symptoms, with mild cases having occasional coughing and no audible stridor at rest, and severe cases having frequent coughing, prominent stridor, and significant distress or lethargy. Children with moderate or severe croup should be admitted to the hospital, especially if they are under 6 months old or have other airway abnormalities. Diagnosis is usually made based on clinical symptoms, but a chest x-ray can show subglottic narrowing. Treatment typically involves a single dose of oral dexamethasone or prednisolone, and emergency treatment may include high-flow oxygen or nebulized adrenaline.
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This question is part of the following fields:
- General Principles
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Question 22
Incorrect
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A 52-year-old man with a history of heart failure visits the clinic complaining of breathlessness for the past three weeks, despite following his prescribed treatment. He reports difficulty breathing while lying down and has resorted to using three large pillows at night. His current medication includes ramipril, carvedilol, furosemide, and bendroflumethiazide. As a healthcare provider, you are contemplating adding a low dose of amiloride to his current regimen. Can you explain the mechanism of action of amiloride?
Your Answer:
Correct Answer: Inhibits epithelial sodium channels
Explanation:Potassium-sparing diuretics are classified into two types: epithelial sodium channel blockers (such as amiloride and triamterene) and aldosterone antagonists (such as spironolactone and eplerenone). However, caution should be exercised when using these drugs in patients taking ACE inhibitors as they can cause hyperkalaemia. Amiloride is a weak diuretic that blocks the epithelial sodium channel in the distal convoluted tubule. It is usually given with thiazides or loop diuretics as an alternative to potassium supplementation since these drugs often cause hypokalaemia. On the other hand, aldosterone antagonists like spironolactone act in the cortical collecting duct and are used to treat conditions such as ascites, heart failure, nephrotic syndrome, and Conn’s syndrome. In patients with cirrhosis, relatively large doses of spironolactone (100 or 200 mg) are often used to manage secondary hyperaldosteronism.
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This question is part of the following fields:
- General Principles
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Question 23
Incorrect
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You are attending a journal club run for the senior doctors of the geriatrics department, where you are completing a rotation. In this session, one of the doctors presents a paper that is examining the impact of a new medication on elderly patients.
Throughout the presentation, the doctor highlights several limitations of the study and mentions that the likelihood of a type II error is significant.
What does this mean in terms of the study's findings?Your Answer:
Correct Answer: The null hypothesis may have been accepted incorrectly
Explanation:A type II error occurs when the null hypothesis is accepted even though it is false. This means that the study fails to detect a difference that actually exists. It is important to note that a type II error does not necessarily indicate a flaw in the study design, but rather a lack of sufficient evidence to reject the null hypothesis.
It is possible for a study to use appropriate methods and still produce a type II error. Therefore, it is important to analyze the evidence separately from the study design.
In contrast, a type I error occurs when the null hypothesis is rejected incorrectly.
The probabilities of type I and type II errors are not directly related, as they are influenced by different factors.
The P value is a measure of the likelihood that the results are due to chance, and should be considered separately from the possibility of a type II error.
Significance tests are used to determine the likelihood of a null hypothesis being true. The null hypothesis states that two treatments are equally effective, while the alternative hypothesis suggests that there is a difference between the two treatments. The p value is the probability of obtaining a result by chance that is at least as extreme as the observed result, assuming the null hypothesis is true. Two types of errors can occur during significance testing: type I, where the null hypothesis is rejected when it is true, and type II, where the null hypothesis is accepted when it is false. The power of a study is the probability of correctly rejecting the null hypothesis when it is false, and it can be increased by increasing the sample size.
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This question is part of the following fields:
- General Principles
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Question 24
Incorrect
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A 20-year old woman arrives at the Emergency department after a night out with her friends. According to her friends, she has been talking to herself about nonsensical things and appears agitated and restless. During the examination, it is noted that her reflexes are heightened and an electrocardiogram (ECG) reveals ventricular ectopics. What type of substance abuse is suspected in this case?
Your Answer:
Correct Answer: Ecstasy
Explanation:Ecstasy Overdose
Ecstasy, also known as MDMA, is a drug that stimulates the central nervous system. It can cause increased alertness, euphoria, extroverted behavior, and rapid speech. People who take ecstasy may also experience a lack of desire to eat or sleep, tremors, dilated pupils, tachycardia, and hypertension. However, more severe intoxication can lead to excitability, agitation, paranoid delusions, hallucinations, hypertonia, and hyperreflexia. In some cases, convulsions, rhabdomyolysis, hyperthermia, and cardiac arrhythmias may also develop.
Severe cases of MDMA poisoning can result in hyperthermia, disseminated intravascular coagulation, rhabdomyolysis, acute renal failure, hyponatremia, and even hepatic damage. In rare cases, amphetamine poisoning may lead to intracerebral and subarachnoid hemorrhage and acute cardiomyopathy, which can be fatal. Chronic amphetamine users may also experience hyperthyroxinemia.
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This question is part of the following fields:
- Pharmacology
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Question 25
Incorrect
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To which major food group does the molecule CH3CH(NH2)COOH belong?
Your Answer:
Correct Answer: Protein
Explanation:The Basics of Amino Acids and Alanine
Amino acids are the building blocks of proteins, which are essential for the functioning of living organisms. One such amino acid is alanine, also known as CH3CH(NH2)COOH. The basic structure of an amino acid consists of an amine group (NH2) and a carboxylic acid group (COOH), which are both acidic and basic, respectively. These groups combine to give proteins a unique set of characteristics.
Alanine is a simple amino acid with a methyl group in its R region. The formula for proteins is R-CH-NH2COOH, where R is a variable region. Amino acids combine to form dipeptides and polypeptides, which make up proteins. the basics of amino acids and their structures is crucial in the complex nature of proteins and their functions in living organisms.
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This question is part of the following fields:
- Clinical Sciences
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Question 26
Incorrect
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A 65-year-old man visits the haemofiltration unit thrice a week for treatment. What is responsible for detecting alterations in salt concentrations, such as sodium chloride, in normally functioning kidneys and adjusting the glomerular filtration rate accordingly?
Your Answer:
Correct Answer: Macula densa
Explanation:The macula densa is a specialized area of columnar tubule cells located in the final part of the ascending loop of Henle. These cells are in contact with the afferent arteriole and play a crucial role in detecting the concentration of sodium chloride in the convoluted tubules and ascending loop of Henle. This detection is affected by the glomerular filtration rate (GFR), which is increased by an increase in blood pressure. When the macula densa detects high sodium chloride levels, it releases ATP and adenosine, which constrict the afferent arteriole and lower GFR. Conversely, when low sodium chloride levels are detected, the macula densa releases nitric oxide, which acts as a vasodilator. The macula densa can also increase renin production from the juxtaglomerular cells.
Juxtaglomerular cells are smooth muscle cells located mainly in the walls of the afferent arteriole. They act as baroreceptors to detect changes in blood pressure and can secrete renin.
Mesangial cells are located at the junction of the afferent and efferent arterioles and, together with the juxtaglomerular cells and the macula densa, form the juxtaglomerular apparatus.
Podocytes, which are modified simple squamous epithelial cells with foot-like projections, make up the innermost layer of the Bowman’s capsule surrounding the glomerular capillaries. They assist in glomerular filtration.
The Loop of Henle and its Role in Renal Physiology
The Loop of Henle is a crucial component of the renal system, located in the juxtamedullary nephrons and running deep into the medulla. Approximately 60 litres of water containing 9000 mmol sodium enters the descending limb of the loop of Henle in 24 hours. The osmolarity of fluid changes and is greatest at the tip of the papilla. The thin ascending limb is impermeable to water, but highly permeable to sodium and chloride ions. This loss means that at the beginning of the thick ascending limb the fluid is hypo osmotic compared with adjacent interstitial fluid. In the thick ascending limb, the reabsorption of sodium and chloride ions occurs by both facilitated and passive diffusion pathways. The loops of Henle are co-located with vasa recta, which have similar solute compositions to the surrounding extracellular fluid, preventing the diffusion and subsequent removal of this hypertonic fluid. The energy-dependent reabsorption of sodium and chloride in the thick ascending limb helps to maintain this osmotic gradient. Overall, the Loop of Henle plays a crucial role in regulating the concentration of solutes in the renal system.
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This question is part of the following fields:
- Renal System
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Question 27
Incorrect
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A 67-year-old man presents to the emergency department after collapsing while shopping. He is experiencing profuse sweating and has a blood pressure of 98/63 mmHg. The patient reports severe epigastric pain as his only complaint.
The suspected cause of his symptoms is peptic ulcer disease, which may have caused erosion into a blood vessel. Upon endoscopy, a perforation is discovered in the posterior medial wall of the second part of the duodenum.
What is the most likely blood vessel that has been affected?Your Answer:
Correct Answer: Gastroduodenal artery
Explanation:The gastroduodenal artery is a potential source of significant gastrointestinal bleeding that can occur as a complication of peptic ulcer disease. The most likely diagnosis based on the given clinical information is peptic ulcer disease, which can cause the ulcer to penetrate through the posteromedial wall of the second part of the duodenum and into the gastroduodenal artery. This can result in a severe gastrointestinal bleed, leading to shock, which may present with symptoms such as low blood pressure, sweating, and collapse.
The answers Splenic artery, Left gastric artery, and Coeliac trunk are incorrect. The splenic artery runs behind the stomach and connects the coeliac trunk to the spleen, and does not pass near the second part of the duodenum. The left gastric artery runs along the small curvature of the stomach and supplies that region, and does not pass through the posteromedial wall of the duodenum. The coeliac trunk arises from the abdominal aorta at the level of T12 and gives rise to the splenic, left gastric, and common hepatic arteries, but does not lie near the second part of the duodenum.
Managing Acute Bleeding in Peptic Ulcer Disease
Peptic ulcer disease is a condition that can lead to acute bleeding, which is the most common complication of the disease. In fact, bleeding accounts for about three-quarters of all problems associated with peptic ulcer disease. The gastroduodenal artery is often the source of significant gastrointestinal bleeding in patients with this condition. The most common symptom of acute bleeding in peptic ulcer disease is haematemesis, but patients may also experience melaena, hypotension, and tachycardia.
When managing acute bleeding in peptic ulcer disease, an ABC approach should be taken, as with any upper gastrointestinal haemorrhage. Intravenous proton pump inhibitors are the first-line treatment, and endoscopic intervention is typically the preferred approach. However, if endoscopic intervention fails (which occurs in approximately 10% of patients), urgent interventional angiography with transarterial embolization or surgery may be necessary. By following these management strategies, healthcare providers can effectively address acute bleeding in patients with peptic ulcer disease.
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This question is part of the following fields:
- Gastrointestinal System
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Question 28
Incorrect
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A 26-year-old medical student visits his doctor with a complaint of experiencing dry mouth, particularly at night, which has been affecting his sleep. He has a medical history of allergic rhinitis and is currently taking chlorphenamine for it.
What is the correct explanation for the mechanism of action of chlorphenamine?Your Answer:
Correct Answer: H1 receptor antagonist
Explanation:Chlorphenamine is a medication.
Antihistamines for Allergic Rhinitis and Urticaria
Antihistamines, specifically H1 inhibitors, are effective in treating allergic rhinitis and urticaria. Sedating antihistamines like chlorpheniramine have antimuscarinic properties that can cause dry mouth and urinary retention. On the other hand, non-sedating antihistamines like loratadine and cetirizine are less likely to cause drowsiness. However, there is some evidence that cetirizine may still cause some level of drowsiness compared to other non-sedating antihistamines. Overall, antihistamines are a valuable treatment option for those suffering from allergic rhinitis and urticaria.
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This question is part of the following fields:
- Musculoskeletal System And Skin
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Question 29
Incorrect
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Which one of the following types of reaction occurs during phase II drug metabolism?
Your Answer:
Correct Answer: Conjugation
Explanation:Drug metabolism involves two phases. In phase I, the drug undergoes oxidation, reduction, or hydrolysis. In phase II, the drug is conjugated.
Understanding Drug Metabolism: Phase I and Phase II Reactions
Drug metabolism involves two types of biochemical reactions, namely phase I and phase II reactions. Phase I reactions include oxidation, reduction, and hydrolysis, which are mainly performed by P450 enzymes. However, some drugs are metabolized by specific enzymes such as alcohol dehydrogenase and xanthine oxidase. The products of phase I reactions are typically more active and potentially toxic. On the other hand, phase II reactions involve conjugation, where glucuronyl, acetyl, methyl, sulphate, and other groups are typically involved. The products of phase II reactions are typically inactive and excreted in urine or bile. The majority of phase I and phase II reactions take place in the liver.
First-Pass Metabolism and Drugs Affected by Zero-Order Kinetics and Acetylator Status
First-pass metabolism is a phenomenon where the concentration of a drug is greatly reduced before it reaches the systemic circulation due to hepatic metabolism. This effect is seen in many drugs, including aspirin, isosorbide dinitrate, glyceryl trinitrate, lignocaine, propranolol, verapamil, isoprenaline, testosterone, and hydrocortisone.
Zero-order kinetics describe metabolism that is independent of the concentration of the reactant. This is due to metabolic pathways becoming saturated, resulting in a constant amount of drug being eliminated per unit time. Drugs exhibiting zero-order kinetics include phenytoin, salicylates (e.g. high-dose aspirin), heparin, and ethanol.
Acetylator status is also an important consideration in drug metabolism. Approximately 50% of the UK population are deficient in hepatic N-acetyltransferase. Drugs affected by acetylator status include isoniazid, procainamide, hydralazine, dapsone, and sulfasalazine. Understanding these concepts is important in predicting drug efficacy and toxicity, as well as in optimizing drug dosing.
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This question is part of the following fields:
- General Principles
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Question 30
Incorrect
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In a research facility, the replication of a heat-sensitive strain of Streptococcus pyogenes is being investigated. An inhibitor was introduced during gel electrophoresis to target an enzyme involved in DNA replication on the lagging strand. The results showed that replication on the leading strand proceeded without interruption, while replication on the lagging strand was fragmented.
What enzyme inhibitor was utilized in this study?Your Answer:
Correct Answer: Ligase
Explanation:Ligase is responsible for connecting Okazaki fragments on the lagging strand to create a continuous strand during DNA replication. While the leading strand undergoes continuous replication, the lagging strand is replicated in fragments known as Okazaki fragments. DNA ligase is an enzyme that joins these fragments together to form a complete section of DNA on the lagging strand.
Helicase is a type of enzyme found in eukaryotes that unwinds double-stranded DNA during replication.
Primase is an RNA polymerase that creates RNA primers, which are necessary for DNA replication to begin.
RNase H is an enzyme that breaks down RNA primers during DNA replication.
DNA Replication in Prokaryotes vs Eukaryotes
DNA replication is the process by which genetic information is copied and passed on to the next generation of cells. In prokaryotes, DNA replication occurs in the cytoplasm, while in eukaryotes, it occurs in the nucleus. Additionally, prokaryotes have a single origin of replication, while eukaryotes have multiple origins.
During DNA replication, the double helix is unzipped by DNA helicase, creating a replication fork. Single-stranded binding proteins prevent the DNA from reannealing. DNA polymerase III elongates the leading strand in a 5′-3′ direction, while DNA polymerase I removes RNA primers and replaces them with DNA. DNA ligase seals up the fragments.
While the basic mechanisms of DNA replication are similar in prokaryotes and eukaryotes, there are some differences in the process. Understanding these differences can help researchers better understand the genetic processes of different organisms.
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This question is part of the following fields:
- General Principles
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